Reaction Rates and Equilibria Flashcards
3 conditions required for a reaction to occur
- collision
- orientation: reactants must align properly to break and form bonds
- energy: the collision must provide the energy of activation
rate of the reaction equation
rate of reaction = change in concentration of reactant or product/ time
factors that affect the rate of reaction
- change in temperature
- change in reaction conc
- adding a catalyst
what happens to the rate of reaction when increasing the temperature
there is an increase in the KE of the reactant molecules, which makes them move faster, makes them collide more often, and makes them collide with more energy
what happens to the rate of reaction when increasing the reactant concentration
when there are more reacting molecules, more collisions that form products can occur and the reaction goes faster
what happens to the rate of reaction when you add a catalyst?
speeds up the rate of the reaction of both the forward and reverse reactions by the same amountsk by providing an alternative pathway that has a lower activation energy. As a result, more collisions provide sufficient energy for reactants to form product
activation energy
the minimum amount of energy required to break the bonds between atoms of the reactants
what happens to k as you decrease activation energy?
the smaller the Ea the larger the k
molecularity
the number of molecules that must collide to generate product
half-life in a chemical reaction
the time required to halve the reactant concentration
the half-life for a first-order reaction
t1/2 = ln2/k
the half-life for a second-order reaction
t1/2 = 1/k[A]0
dynamic equilibria
the reaction keeps happening both forward and reverse at the same rate
equilibrium conditions
- The rate of forward reaction is equal to the rate of the reverse reaction
- the forward and reverse reactions continue at the same rate
describe the properties of an equilibrium constant for a reversible chemical reaction
- it is a fixed value at a specific temperature
- the value that the system will evolve to reach an equilibrium
what is activity
the effective molar conc of a species in the solution
Kc
the numerical value obtained by substituting experimentally measured molar concentrations at equilibrium into the expression
large Kc
large amounts of products produced from the forward reaction
small Kc
low concentration of products and high concentration of reactants
reaction quotient Q
uses non-equilibrium concentrations
Q< Kc
more products will be synthesized
Q> Kc
the reaction proceeds to the left
le chatelier’s principle
when a stress is placed on a reaction at equilibrium the system responds by changing the rate of the forward or reverse reaction in the direction that relieves that stress
k -1
the kinetic rate of the reverse reaction