Reaction of iodide ions with concentrated sulfuric acid Flashcards

1
Q

Reaction of iodide ions with concentrated sulfuric acid

The reaction of sodium iodide and concentrated sulfuric acid is:

A

H2SO4 (l) + NaI (s) → HI (g) + NaHSO4 (s)

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2
Q

H2SO4 (l) + NaI (s) → HI (g) + NaHSO4 (s)

2HI (g) + H2SO4 (l) → I2 (g) + SO2 (g) + 2H2O (l)

what happens during this reaction to the next

A

Hydrogen iodide decomposes readily

Sulfuric acid oxidises the hydrogen iodide to form several products:

The concentrated sulfuric acid oxidises HI and is itself reduced to sulfur dioxide gas

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3
Q

2HI (g) + H2SO4 (l) → I2 (g) + SO2 (g) + 2H2O (l)

6HI (g) + H2SO4 (l) → 3I2 (g) + S (s) + 4H2O (l)

what happens between these reactions

A

Iodine is seen as a violet/purple vapour in first reaction

The concentrated sulfuric acid oxidises HI and is itself reduced to sulfur:

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4
Q

6HI (g) + H2SO4 (l) → 3I2 (g) + S (s) + 4H2O (l)

8HI (g) + H2SO4 (l) → 4I2 (g) + H2S (s) + 4H2O (l)

what happens between these reactions

A

Sulfur is seen as a yellow solid in first reaction

The concentrated sulfuric acid oxidises HI and is itself reduced to hydrogen sulfide:

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5
Q

8HI (g) + H2SO4 (l) → 4I2 (g) + H2S (s) + 4H2O (l)

what happens this reaction

A

Hydrogen sulfide has a strong smell of bad eggs

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