rates + equilibrium Flashcards

1
Q

order of reaction definition

A

shows the extent to which the concentration of a reagent affects the rate of reaction
the power to which the concentration of a reagent is raised to in the rate equation

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2
Q

what does it mean if a reagent is 0 order

A

the rate is unaffected by changes in concentration of that reagent

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3
Q

what does it mean if a reagent is 1st order

A

if the concentration changes, the rate will change by the same factor/amount

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4
Q

what does it mean if a reagent is 2nd order

A

if the concentration changes, the rate will change by the square of that amount

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5
Q

rate constant k definition

A

the constant of proportionality in the rate equation

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6
Q

what affects rate constant k

A

temperature and catalysts, not concentration or pressure

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7
Q

how does temperature affect k

A

increase in temperature increases k value
- high temp = more kinetic energy = more successful collisions = high rate = larger k value

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8
Q

how do catalysts affect k

A

catalysts increase k
- catalyst = faster rate = larger k value

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9
Q

what does a very high k value mean

A

fast reaction rate

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10
Q

what does a very small k value mean

A

slow reaction rate

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11
Q

what is the overall order of a reaction

A

the sum of all orders of reagents taking part in reaction

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12
Q

half life definition

A

how long it takes for reactant concentration to half

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13
Q

what can be found from concentration-time graphs of a reaction

A

the order of the reactant can be found by measuring the half life

  • if half life gets smaller = 0 order
  • if half life stays constant = 1st order
  • if half life increases = 2nd order
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14
Q

which step of a reaction is the rate determining step

A

the slowest step, as a reaction can only go as fast as the slowest part of a reaction

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15
Q

if the gradient of a first order rate-conc graph is measured what does this give

A

the value of k
this is because rate = k[reactant] so as conc = x axis and rate = y axis gradient = k

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16
Q

when determining composition of a reaction mixture, why is the analysis of a physical property preferable to a chemical analysis

A
  • measuring the change in a physical property will not interfere with reaction
  • chemical analysis means the reaction must be stopped so analysis can take place to determine composition
17
Q

suggest 2 physical properties that could be measured + how

A

colour change of gases or solutions
- this could be done using a colorimeter calibrated with known concentrations of the coloured substance

release of gas
- this could be done with a gas syringe or by measuring loss of mass

18
Q

what is the rate equation

A

rate = k[reactants]^order

19
Q

what is the half life equation

A

k = ln(2) / half life

half life known as t 1/2

20
Q

what is the arrhenius equation

A

k = Ae^(- Ea / R T)
rearranged to
lnk = -Ea / R T + lnA

21
Q

what are all the variables in arrhenius equation

A

k = rate constant
A = pre exponential factor (aka arrhenius constant)
e = eulers constant
Ea = activation energy (Jmol-1)
T = temp (K)
R = gas constant

22
Q

what 3 types of reactions does the arrhenius equation describe

A
  • reactions involving gases
  • reactions occurring in solution
  • reactions occurring on the surface of a catalyst
23
Q

mole fraction definition

A

the fraction of the total number of moles that each substance in a reaction is responsible for - the amount of moles of a component divided by total number of moles in the mixture

24
Q

partial pressure definition

A

the proportion of the total pressure that each chemical in a reaction is responsible for - the amount of pressure that would be exerted by a gas within a mixture if it occupied the same volume on its own at the same temp

25
Q

what types of substance can be included in kc and kp calculations

A

ones in gaseous or aqueous states
no solids or liquids!

26
Q

partial pressure p(X) equation

A

p(X) = total pressure x mole fraction

27
Q

homogenous equilibria definition

A

all species are in the same state

28
Q

heterogenous equilibria definition

A

all species aren’t in the same state

29
Q

what factors affect kc and kp

A

only temperature

concentration, pressure and catalysts have no effect

30
Q

why does concentration/pressure not have an effect on kc and kp

A

changes in pressure or concentration change the position of the equilibrium, but as this affects concentration of reacting substances, the position of equilibrium moves back to minimise the effect of this change, overall no effect

31
Q

why do catalysts have no effect on kc and kp

A

catalysts increase rates of forwards and backwards reactions equally so no effect

32
Q

how does temperature affect kc and kp

A

for exothermic reactions, increasing temp = decreasing kc/kp as this favours the opposite reaction, so decreased products/increased reactants = decreased kc/kp

for endothermic reactions increasing temp = increasing kc/kp as this favour the forward reaction, so increased products/decreased reactants = increased kc/kp