Rate Equations Flashcards

1
Q

What does a rate equation show

A

How changes in the concentrations of reactants affect the rate of reaction

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2
Q

What does each letter stand for in rate=k[A]^x[B]^y

A

-constant k is rate constant
-[A] and [B] represent the concentrations of reactants in mol/dm3
-powers x and y are the reaction orders with respect to A and B in equation

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3
Q

What is the overall order of a reaction

A

The sum of the orders for all the substances that appear in the rate equation

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4
Q

What does factor does rate constant (k) vary with

A

Temperature

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5
Q

What is a first order reaction

A

Reaction is first order with respect to a reactant if the rate of reaction is proportional to concen of that reactant, raised to power one in the rate equation

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6
Q

What type of line is on graph for first order reaction

A

Straight line passing through the origin

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7
Q

What is the half-life of a reaction

A

The time for the concentration of one of the reactants to fall by half

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8
Q

What is a second order reaction

A

If the rate of reaction is proportional to the concentration of that reaction squared, raised to the power two in the rate equation for that reactant

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9
Q

What does doubling concentration of X raised to power 2 in rate equation do to rate

A

Increases rate by factor of four

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10
Q

What does concentration-time graph look like for second order reaction and how to find gradient

A

Curve, draw tangents to curve to find gradient

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11
Q

What is a zero order reaction and what does concentration-rate graph look like

A

When rate of reaction is unaffected by changes in the concentration of that reactant, raised to the power zero
-graph is straight line

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12
Q

What do the units of the rate constant depend on

A

The overall order of the reaction

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13
Q

Does the half-life of a first order reaction change depending on starting concentration

A

No it is the same whatever the starting concentration

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14
Q

How to find the half-life of a second order reaction

A

Half-life is inversely proportional to the starting concentration

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