Radical Chemistry 2 Flashcards

1
Q

The following reaction is a conjugate addition to form intermolecular carbon-carbon bond forming reactions of radicals
What is the mechanism and product?

A
  • Driven by the formation of a stronger I-SnBu3 bond
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2
Q

Why is no β-elimination observed for this reaction

A

No β-elimination of oxygen is observed, unlike in ionic reactions, due to the strong carbon-oxygen bond
(In ionic reactions we must also consider the ability of a leaving group to stablise a negative charge, which is high in the case of oxygen)

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3
Q

The following reaction is a intramolecular carbon-carbon bond forming reaction of radicals
What is the mechanism and product?

A
  • 5-exo-trig cyclisation reaction
  • Driving forcing is making a stronger C-C sigma bond from a weaker C-C sigma bond
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4
Q

C-Se is an example of another bond which will react with a radical
This reaction is an intramolecular C-C bond forming reaction of radicals
What is the mechanism and product

A
  • Unusually this reaction reaction favours the formation of a 5-exo-trig cyclisation
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5
Q

Why is the 5-exo-trig cyclisation preferred over the alternative 6-endo-trig cyclisation

A
  • Carbon 5 is closer than carbon 6 to react with the radical conformationally
  • Less strain in the 5-membered transition state
  • Both pathways are favoured according to Baldwin’s guidelines for ring closure, but the 5-exo-trig cyclisation is faster
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6
Q

Where does the nomenclature of these reactions come from?

A
  • Exo/Endo - does the double bond form part of the ring (endo) or not (exo)
  • Trig - trigonal planar, double bonds are sp² hybridised
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7
Q

Why is intramolecular C-C bond forming reactions of radicals favoured compared to the intermolecular processes

A

The radical and the double bond are more likely to come into contact with the intramolecular process
(however the precursors to these reactions are harder to get)

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8
Q

The following is an example of a 6-exo-trig radical cyclisation, which takes advantage of the ready sterochemical inversion of alkenyl radicals
What is the mechanism and the product?

A

Requires rotation around sp² carbon so radical and C-C double bond are closer together

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9
Q

Radicals can be used to make larger rings (macrocycles), where high dilution conditions are used to decrease the rate of premature quenching of the initially formed alkyl radicals by Bu₃SnH, giving the radical a chance to undergo macrocyclisation
What is the mechanism and product?

A
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10
Q

The real power of radical cyclisation is seen in domino reactions, where more than one carbon-carbon bond and several rings can be formed in one step
What is the first step of the mechanism?

A
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11
Q

The real power of radical cyclisation is seen in domino reactions, where more than one carbon-carbon bond and several rings can be formed in one step
How does this intermediate further react?

A
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12
Q

The high reactivity of radicals can be exploited to functionalise otherwise inert, unreactive bonds. The following example is a classic case of the Barton nitrite photolysis reaction, used to functionalise steroid frameworks
What is the mechanism

A

Driving force is the formation of strong N-O bond
SN2 reaction

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13
Q

This intermediate is then irradiated
What is the mechanism and the product?

A
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14
Q

The Hoffmann-Loffler-Freytag reaction is useful for forming five-membered rings satuarted nitrogen heterocycles (pyrrolidines) and involves the generation of highly reactive nitrogen-centred radical cations
What is the mechanism and product when we react with acid then irradiate

A
  • Last step with NaOH in an SN2 reaction
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15
Q

What is the mechanism for the last step of the Hoffmann-Loffler-Freytag reaction

A
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