Introduction to Palladium Catalysis II Flashcards

1
Q

How does Pd(0) react?

A

It is electron rich (d¹⁰)
Nucleophilic

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2
Q

How dooes Pd(II) react?

A

Electron poor (d⁸)
Electrohilic

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3
Q

The Pd(0) compound can go oxidative addition with the following benzohalide
What is the transition state and the product

A
  • Selective cis-addition of X and R to the meatal centre (concerted reaction)
  • Metal is oxidised from Pd(0) to Pd(II), hence oxidative addition
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4
Q

How many ligands are there on a saturated Palladium

A

4

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5
Q

What is the opposing reaction for oxidative addition?

A

Reductive elimination
(it is essentially plucking palladium complex out and reforming a bond between x and y
The metal is reduced from Pd(II) to Pd(0) in the process
(x-y because doesn’t always have to occur between a carbon-halogen)

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6
Q

What is the key feature of the substitents to allow reductive elimination to occur?

A

The substituents undergoing reductive elimination (X and Y) need to be cis to each other

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7
Q

What is the driving force of a reductive elimination?

A
  • Thermodynamics (formation of stronger bonds)
  • Reductive elimination is easy and fast when strong bonds are formed
  • Two halogens or C-X bond would be too weak and a lot slower
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8
Q

What occurs in transmetallation and why is it important?

A
  • Transmetallation transfers a carbon ligand from one metal (e.g. Li, Mg, Cu, Zn, B, Si, Sn) to another metal (e.g. Pd) - note some of these aren’t metals like silicon or boron
  • This step is important, because it allows the transfer of different groups onto palladium which can the be coupled together in the reductive elimination step
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9
Q

What is the role of the base in the Suzuki reaction?

A

The base acts as an activator, increasing the nucleophilicity by generating a negatively charged ‘ate’ complex, and speeds up transmetallation:

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10
Q

Why can Boronic acid alone not be used in a transmetallation within a Suzuki reaction?
Draw a mechanism for this

A
  • Boronic acids are not very nucleophilic (C-B bond not very polarised) meaning the transmetallation is slow
  • Other activators can be added in, e.g. CsF (F- has a very high affinity for B)
  • The activators will drive electron density into B empty P orbital which will give a complex which is negatively charged
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11
Q

Name some standard reaction conditions for the Suzuki reaction

A
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12
Q

If the boronic acid/ester coupling partner for a Suzuki reaction is not available, a different transmetallating reagent can be used:
What can replace X

A

(the benefit of the bottom three are that they are very reactive meaning they do not require an activator)

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13
Q

How can we make bornic acids from transmetallation from organolithium

A

By reacting it with a trimethoxyboron group
OMe are leaving groups

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14
Q

How can we form a boronic ester from hydroboration of alkynes and alkenes

A

Alkyne displaces the hydrogen on boron

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15
Q

How can a Boronic ester be formed from Pd cross-coupling

A
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