Pure 2.6 - Hyperbolic Functions Flashcards

1
Q

What is the formula for the hyperbolic sine (or sinh) function in terms of e?

A

sinh(π‘₯)=(eΛ£-e⁻ˣ)/2

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2
Q

What is the formula for the hyperbolic cosine (or cosh) function in terms of e?

A

cosh(π‘₯)=(eΛ£+e⁻ˣ)/2

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3
Q

What is the formula for the hyperbolic tangent (or tanh) function in terms of e?

A

sinh(π‘₯)=sinh(π‘₯)/cosh(π‘₯)=(eΛ£-e⁻ˣ)/(eΛ£+e⁻ˣ)=(eβ‚‚Λ£-1)/(eβ‚‚Λ£+1)

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4
Q

What are the hyperbolic functions of the reciprocal trigonometric functions?

A

cosech(π‘₯)=1/sinh(π‘₯)=2/(eΛ£-e⁻ˣ)
sech(π‘₯)=1/cosh(π‘₯)=2/(eΛ£+e⁻ˣ)
coth(π‘₯)=1/tanh(π‘₯)=(eβ‚‚Λ£+1)/(eβ‚‚Λ£-1)

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5
Q

Describe the relationship between the values of sinh and -sinh.

A

For any value π‘Ž, sinh(-π‘Ž)=-sinh(π‘Ž)

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6
Q

Describe the relationship between the values of cosh and -cosh.

A

For any value π‘Ž, cosh(-π‘Ž)=-cosh(π‘Ž)

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7
Q

What is an even function?

A

Any function where f(-π‘₯)=f(π‘₯)

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8
Q

What is an odd function?

A

Any function where f(-π‘₯)=-f(π‘₯)

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9
Q

What are the inverse hyperbolic functions and their domains if they have any?

A

𝑦=sinh(π‘₯) β†’ 𝑦=arcinh(π‘₯)
𝑦=cosh(π‘₯), π‘₯β‰₯0β†’ 𝑦=arcosh(π‘₯), π‘₯β‰₯1
𝑦=tanh(π‘₯) β†’ 𝑦=artanh(π‘₯), |π‘₯|<1

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10
Q

What are the definitions of the inverse hyperbolic functions in terms of π‘₯?

A

arsinh(π‘₯)=ln(π‘₯+√(π‘₯Β²+1))
arcosh(π‘₯)=ln(π‘₯+√(π‘₯Β²-1)), π‘₯β‰₯1
artanh(π‘₯)=Β½ln((1+π‘₯)/(1-π‘₯)), |π‘₯|<1

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11
Q

What is coshΒ²(𝑨)-sinhΒ²(𝑨)

A

1

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12
Q

What are the hyperbolic addition formulae?

A

sinh(𝐴±𝐡)≑sinh(𝐴)cosh(𝐡)Β±cosh(𝐴)sinh(𝐡)

cosh(𝐴±𝐡)≑cosh(𝐴)cosh(𝐡)Β±sinh(𝐴)sinh(𝐡)

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13
Q

Describe Osborn’s rule.

A

To get the hyperbolic identity of the corresponding trigonometric identity;
replace cos by cosh
replace sin with sinh
However replace any product or implied product of two sin terms by minus the product of two sinh terms

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14
Q

f(π‘₯)=sinh(π‘₯) find f’(π‘₯).

A

cosh(π‘₯)

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15
Q

f(π‘₯)=cosh(π‘₯) find f’(π‘₯).

A

sinh(π‘₯)

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16
Q

f(π‘₯)=tanh(π‘₯) find f’(π‘₯).

A

sechΒ²(π‘₯)

17
Q

f(π‘₯)=arsinh(π‘₯) find f’(π‘₯).

A

1/√(π‘₯Β²+1)

18
Q

f(π‘₯)=arcosh(π‘₯) find f’(π‘₯).

A

1/√(π‘₯Β²-1), π‘₯>1

19
Q

f(π‘₯)=artanh(π‘₯) find f’(π‘₯).

A

1/1-π‘₯Β², |π‘₯|<1

20
Q

f’(π‘₯)=sinh(π‘₯) find f(π‘₯).

A

cosh(π‘₯)+𝑐

21
Q

f’(π‘₯)=cosh(π‘₯) find f(π‘₯).

A

sinh(π‘₯)+𝑐

22
Q

f’(π‘₯)=1/√(π‘₯Β²+1) find f(π‘₯).

A

arsinh(π‘₯)+𝑐

23
Q

f’(π‘₯)=1/√(π‘₯Β²-1) find f(π‘₯).

A

arcosh(π‘₯)+𝑐, π‘₯>1

24
Q

f’(π‘₯)=tanh(π‘₯) find f(π‘₯).

A

ln(cosh(π‘₯))+𝑐

25
Q

f’(π‘₯)=1/√(π‘ŽΒ²+π‘₯Β²) find f(π‘₯).

A

arsinh(π‘₯π‘Ž/)+𝑐

26
Q

f’(π‘₯)=1/√(π‘₯Β²-π‘ŽΒ²) find f(π‘₯).

A

arcosh(π‘₯/π‘Ž)+𝑐, π‘₯>π‘Ž