Pulmonary Ventilation Flashcards
Avg. Alveolar Diameter
100 um
Normal Lung Compliance
200 mls of air/ 1 cm H20 increase in transpulmonary pressure
What does an increase in transpulmonary pressure indicate?
Forces trying to collapse the lung have increased
How much air is drawn in with each breath?
500 mls
Normal Alveolar Pressures
0 cmH20 (ATM pressure) at rest
-1 cmH20 upon inspiration
+1 upon expiration
Normal Pleural Pressures
- 5 cmH20 at rest
- 7.5 cmH20 upon inspiration
How long does it take to inspire and expire air?
2 seconds inspire
2-3 seconds expire
Compliance
How much the lungs will expand with each unit increase in transpulmonary pressure
What is constant in the compliance curve?
Alveolar pressure
What changes in compliance curve?
Pleural pressure and change in volume of air that moves
What determines the shape of the compliance curve?
Elastic forces of the lungs (Not linear because lung is trying to collapse, taking more force to overcome resistance creating the “lag”)
Elastic forces of lung tissue
Elastin & collagen (stretch as lungs fill)
1/3 total elastic forces
Elastic forces caused by surface tension in alveoli wall
2/3 total elastic forces
Needs surfactant
Air-water interface
water molecules at the surface form very strong attraction cause the water surface to contract
Surfactant
Reduces surface tension of water
Secreted by Type II alveolar epithelial cells
10% alveolar surface area
Contains phospholipids (reduce surface tension 8-50%)