Prokaryotic transcription Flashcards

1
Q

central dogma of biology

A

DNA is transcribed to RNA which is translated into proteins.
Only possible reversal in direction occurs from retroviral ability to reverse transcribe RNA to DNA

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

advantages of having mRNA as a mediator molecule in transcription

A
  1. allows cell to separate storage of info from utilisation of info (safe storage in nucleus)
  2. greater amplification of synthetic output (1DNA molecule codes for multiple mRNA molecules)
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

mono vs polycistronic mRNA

A

monocistronic: each mRNA molecule produces one type of protein

polycistronic: each mRNA molecule contains info that can produce multiple discreet proteins

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

advantages of polycistronic mRNAs (3)

A
  1. usually proteins produced share a related function, so polycistronic mRNAs can ensure an almost equimolar amount of each protein in the cell
  2. saves energy (reduces unnecessary transcription)
  3. decreases required size of genome
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

promoter definition

A

Region of nucleotides within DNA that allows binding of certain proteins (eg, RNAP)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

RNAP enzyme forms (2)

A
  1. CORE ENZYME: 2 alpha units, beta, beta prime and omega unit. High affinity for DNA, low for promoter, hence is used in elongation
  2. HOLOENZYME: core enzyme + sigma subunit. High affinity to promoter, low to DNA hence used for formation of initiation complex

HICE: holo initiation, core elongation

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Structure of a prokaryotic promoter

A

-35 region: responsible for binding of sigma factor hence closed complex formation
-10 region (pribnow box): responsible for open complex formation
+1 region: start of coding sequence

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Role of 3’ and 5’ UTRs

A

Untranslated regions that are between promoter and coding sequence (5’) or between coding sequence and terminator (3’)

protect the mRNA from being degraded

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

up/down elements

A

can be present in the sequence between -35 and -10 of promoter and either upregulate or downregulate gene transcription

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Promoter strength def

A

number of transcripts that are initiated by a promoter per unit time.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

Factors affecting promoter strength (4)

A
  1. affinity of RNAP to promoter (regulated by -35)
  2. efficacy of closed complex to open complex conversion
  3. efficacy of promoter clearance
  4. presence of an up element (increases strength)
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

Basal transcription def

A

average rate of transcription in the absence of an activator or repressor element

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Structure and function of activators

A

Activators are TFs that bind to DNA increasing the strength of a promoter
Increase time that RNAP can bind with operator without dissociating so it helps the initiation of closed complex

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Structure and function of a repressor

A

TF that have binding sequences overlapping with the promoter
Binds to operator to prevent RNAP from binding there itself –> no transcription if present

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

Factors affecting extent of activation/repression

A
  1. conc of element present
  2. affinity of element to DNA
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Initiation process

A

-creation of holoenzyme from binding of sigma subunit and free cytoplasmic core enzyme
-collision of holoenzyme with DNA and sliding along strand until it recognises the promoter region
-closed complex forms when RNAP binds to promoter
-RNAP denatures double helix and forms an open complex
-formation of transcription bubble and addition of a small number of rNTPs
-sigma factor is discarded and RNAP breaks away from promoter to enter elongation phase

17
Q

Elongation process

A

-dissociation of sigma factor causes conformational change into claw shape which increases enzyme’s synthesis speed
-transcription bubble is constantly expanding downstream and contracting at the enzyme’s rear
-reaches termination signal
-loss of affinity to DNA and so enzyme disengages

18
Q

Termination process

A

caused by reaching termination signal
2TYPES:
1. RHO INDEPENDENT:
-termination signal is GC rich palindrome followed by a long polyA
-structure of the palindrome sequence during transcription is a hairpin loop
-causes DNA/RNA hybrid to pause
-A rich region causes release of transcript and RNAP

  1. RHO DEPENDENT:
    -requires Rho termination factor (hexameric protein)
    -GC palindrome sequence is present but no poly A
    - Rho factor binds to RUTS (rho utilization site)
    -the pause of RNAP caused by hairpin loop allows Rho to move into termination region and unwind DNA-RNA complex
19
Q

operon def

A

An operon is a cluster of genes under a single promoter, hence controlled together

20
Q

Positive and negative transcription control

A

POSITIVE: occurs usually for weak promoters with a low affinity for RNAP: basal transcription is low or non (due to weakness) and so an activator binds to activator binding site to increase transcription rate

NEGATIVE: occurs usually for strong promoters with high affinity for RNAP: basal transcription is high and so repressors bind to operator to lower/stop transcription rate

21
Q

LAC OPERON structure

A

order of upstream-downstream:

-LacI repressor site
-CAP (activator binding) site
-promoter
-operator
-LacZ: beta galactosidase
-LacY: lactose permease
-LacA

22
Q

2 factors that affect transcription rate of lac operon in different environments

A
  1. ALLOLACTOSE conc: binds to repressor and can dissociate it from operator
  2. cAMP and CAP complex conc: binds to CAP site and increases rate of transcription
23
Q

what is the relationship between levels of glucose and levels of cAMP?

A

inverse proportion,
high glucose levels = low cAMP
low glucose levels = high cAMP

24
Q

lac operon: no lactose no glucose

A

NO TRANSCIRPTION:
1. no allolactose present so the receptor is transcribed, translated and bound to operator
2. high levels of cAMP so the CAP-cAMP complex is formed but this doesn’t change the fact that RNAP cant bind to promoter

25
Q

lac operon: lactose present without glucose

A

HIGH TRANSCIRPTION RATE
1. allolactose present which allows the receptor to bind to it and dissociate from operator (RNAP binds to promoter)

  1. cAMP levels are high so high conc of CAP-cAMP complex, which increases trasncirption
26
Q

lac operon: both lactose and glucose

A

LOW TRANSCRIPTION RATE:
1. allolactose present which allows the receptor to bind to it and dissociate from operator (RNAP binds to promoter)

  1. cAMP in low levels so no cAMP-CAP complexes formed meaning no increase in transcription rate
27
Q

lac operon: glucose present without lactose

A

NO TRANSCIRPTION:
1. no allolactose present so the receptor is transcribed, translated and bound to operator
2. low levels of cAMP so the CAP-cAMP complex is not formed

28
Q

cis vs trans acting elements

A

cis acting: short DNA stretches of a defined sequence that act as binding sites

trans acting: proteins (eg. TFs/repressors) that bind to cis acting factors

29
Q

possible mutations of the lac operon (2)

A
  1. Lac1- mutant: no functional repressor is present (RECESSIVE)
  2. Lac0- mutant: no functional operator that the repressor can bind to (DOMINANT)