pro euk l Flashcards

1
Q

euk vs pro: cell size

A

euk: larger, 10 to 100 micrometers
prok: smaller, 0.5 to 5 micrometers

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2
Q

euk vs pro: nucleus

A

euk: nucleus with nuclear envelope presemt
pro: no true nucleus

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3
Q

euk vs pro: genetic material

A

euk:
Linear DNA associated with many proteins;
Found in membrane bound nucleus;
No plasmids
pro:
Circular DNA associated with few histone-like proteins;
Found in a region of the cytoplasm known as the nucleoid region;
Plasmids present

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4
Q

euk vs pro: type of ribosomes

A

euk: 80S, may be attached to ER or free in cytoplasm
pro: 70S, only found in cytoplasm

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5
Q

euk vs pro: organelles present

A

euk: many membrane bound organelles present
pro: no membrane bound organelles

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6
Q

euk vs pro: cell walls

A

euk: composed of cellulose in plants
pro: composed of peptidoglycan

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7
Q

euk vs pro genome: size

A

euk: larger with more base pairs (10^7 to 10^11)
pro: smaller with less base pairs
(10^4 to 10^7)

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8
Q

euk vs pro genome: appearance

A

euk: multiple, linear molecules
pro: single, circular molecule

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9
Q

euk vs pro genome: molecule

A

both are double helix DNA

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10
Q

euk vs pro genome: association with proteins

A

euk: large amounts of genome is associated with histones, scaffold proteins
pro: less amounts of genome is associated with histone-like proteins

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11
Q

describe level of DNA packing/coiling in eukaryotic genome

A

high level:
negatively charged DNA double helix is associated with positively charged histones via electrostatic attraction: DNA is wound
around 8 histone proteins twice to form nucleosomes with linker DNA joining adjacent nucleosomes, forming a 10nm fiber/chromatin, which
coils around itself to form 30nm fibre/solenoid
the solenoid forms looped domains when associated with scaffold proteins, forming 300nm fibre, which then supercoils to form metaphase chromosome (at metaphase)

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12
Q

describe level of DNA packing/coiling in prokaryotic genome

A

Relatively low:
DNA double helix is folded into looped domains by protein-
DNA associations
the looped domains further undergo supercoiling with the help of DNA gyrase and topoisomerase

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13
Q

why do we need to package and coil DNA

A
  1. to compact DNA to fit into the nucleus in eukaryotes or nucleoid in prokaryotes
  2. to prevent DNA breakage or damage since DNA molecules move around alot during nuclear division
  3. for regulation of gene expression in eukaryotes
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14
Q

euk vs pro genome: location

A

euk: nucleus
pro: non membrane bound nucleoid region

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15
Q

euk vs pro genome: presence of extrachromosomal DNA

A

euk: yes if mitochondrial and chloroplast circular DNA are considered
pro: yes of which are plasmids

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16
Q

euk vs pro genome: number of genes

A

euk: 25000
pro: 4500

17
Q

pro vs euk genome: presence of introns

A

euk: many
pro: rare

18
Q

pro vs euk genome: presence of promoters

A

both have promoters present

19
Q

pro vs euk genome: presence of repeated sequences

A

euk: many such as telomeres/centromeres
pro: rare

20
Q

pro vs euk genome: presence of enhancers/silencers

A

euk: common
pro: rare

21
Q

pro vs euk genome: presence of operons

A

euk: few
pro: many

22
Q

describe structure of introns

A
  • non coding DNA sequences found within a gene, specifically
    between exons in a specific
    segment of DNA (also present in
    pre- mRNA)
  • only in eukaryotes
23
Q

describe function of introns

A
  • enables a process
    called ‘alternative RNA splicing’
    to occur where different combinations of different exons
    of a single pre-mRNA can be
    joined such that different
    mature mRNAs are produced

so that one gene can now code for more than one polypeptide

24
Q

describe structure of promoter

A
  • located just
    upstream of the
    transcription start
    site of a gene, hence it is called a proximal control element
  • has critical elements
    e.g.1. TATA box, loacted
    upstream of transcription start
    site)
    e.g. 2. CAAT and GC boxes, located upstream of TATA but are not always present and are not critical in determining transcription frequency
25
Q

describe function of promoter

A
  • recognition & binding site for
    general transcription factors which then recruits RNA
    Polymerase to form transcription
    initiation complex which initiates
    transcription
    -TATA box in promoter is where general transcription factoers bind to so it determines precise location of transcription start sitet site
  • CAAT and GC box improves the efficiency of promter
26
Q

describe structure of enhancers/silencer

A

are non coding regulatory DNA sequences
usually located far away from the
promoter (usually much further
upstream or downstream), hence being called a distal control element

27
Q

describe function of enhancer

A
  • recognition & binding site for
    activators
  • increase the frequency of
    transcription by promoting the
    assembly of the transcription
    initiation complex
    (with the help of
    DNA bending
    proteins that bend
    spacer DNA)
28
Q

describe function of silencer

A
  • recognition & binding site for
    repressors
  • decrease the frequency of
    transcription by
    preventing the
    assembly of the
    transcription
    initiation complex
29
Q

what are specific transcription factors?

A

proteins with a DNA binding site that is complementary in shape and charge to a specific regulatory sequence of DNA which it binds to

30
Q

structure of telomeres

A

1- found at both ends/terminals of linear, eukaryotic chromosomes
2- non-coding DNA made up of a series of tandem repeat sequences which are a specific sequence of nucleotides occurring many times in a row
3- in humans, each repeat has
the sequence 5’ TTAGGG 3’
4- have a single stranded region
at their 3’ ends known as the 3’
overhang and which due to a limitation of DNA polymerase,
this region of DNA does not have acomplementary strand)

31
Q

describe role of telomeres in the end replication problem

A

Telomeres ensure that genes are not eroded and vital
genetic information is not lost with each round of DNA replication due to the end replication problem.
As DNA polymerase requires a free 3’OH of a pre-existing strand to add nucleotides, the last RNA primer on the lagging strand with DNA cannot be replaced with DNA. Hence, the DNA molecule shortens with each round of
replication. Telomeres, which are non-coding sequences at the ends of linear chromosomes will be lost before any vital genetic information is. Since
telomeres are non-coding, they can be lost without any deleterious effect.

32
Q

describe the role of telomeres in stabilising ends of chromosomes

A

2-Telomeres protect and stabilize the terminal ends of chromosomes by forming a loop using the 3’overhang.
This prevents single-stranded terminal end of one chromosome from annealing to a complementary single-stranded terminal end of another
chromosome, prevent fusing of 2 chromosomes.
The formation of the loop also prevents the cell’s DNA repair machinery from detecting the chromosome as damaged DNA (i.e. double stranded
breaks) and trigger apoptosis.

33
Q

describe telomere’s role in their own extension

A

3-Telomeres allow their own extension, as they have a 3’ overhang which provides an attachment point for the correct positioning of the enzyme
telomerase. Although telomeres shorten with every round of DNA replication, telomerase activity in germ cells, embryonic stem cells and cancer cells can
maintain telomere length.

34
Q

how does telomerase work

A

A short 3-nucleotide segment of RNA within telomerase binds to part of a DNA repeat in the 3’overhang by complementray base pairing.
2. The adjacent part of the RNA within telomerase is used as a template to synthesise a short
complementary 6-nucleotide DNA repeat.
3. Telomerase catalyses the formation of the phosphodiester bonds between the existing
3’OH group of existing DNA overhang and 5’ phosphate group of incoming deoxyribonucleotide

After the repeat is made, telomerase translocates 6 nucleotides to the right in the 5’
to 3’ direction of the DNA overhang and begins to
make another repeat. The above process is repeated such that a series of tandem repeats are
made, elongating the telomere.

5.Then primase makes an RNA primer near the end of the telomere. DNA polymerase adds
nucleotides to the 3’OH end of the primer and hence synthesizes a complementary strand . The nick is then sealed by ligase. The RNA
primer is eventually removed.

35
Q

structure of centromeres

A
  1. Constricted region on chromosome where kinetochore
    microtubules attach during
    nuclear division
    2- non-coding DNA made up of a
    series of tandem repeat sequences
36
Q

function of centromeres

A

1- allow sister chromatids to
adhere to each other
2- allow kinetochore proteins to attach and which in turn
allow spindle fibres to attach so
that sister chromatids/homologous
chromosomes can align along the
metaphase plate and subsequently be separated to
opposite poles.

Ultimately, allow s
proper alignment and
segregation of
chromosomes.