Principles of Science Flashcards

1
Q

How are histological samples are prepared?

A
  1. Fixation – sample placed in fixative for length of time (formalin, 24hr, 70% alc)
  2. Process – paraffin wax & solvent (histolene)
  3. Section – cut with rotary micro turn
  4. Stained – haematoxylin (blue nuclei) & eosin (pink protein)
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2
Q

What skills are involved in examining histological sections

A

Directions of sectioning

  1. Longitudinal – horizontal (along)
  2. Transverse – vertical (across)
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3
Q

Recognise examples of the main tissue types

A
1. Simple Epithelial tissue
		○ Form boundaries/barriers (dark purple staining)
			 Squamous – blood vessels (passive)
			 Cuboidal – glands (semi-acive)
			 Columnar – gut (active)
2. Connective tissue
	○ Lie in between epithelia & muscle
	○ Contains proteins & provides active tissue support
	○ ECM – support network of proteins 
	○ Dense Irregular CT (tendon) – multidirectional collagen bundles 

3. Muscle
	○ Skeletal/striated – longitudinal = striations 
	○ Cardiac 
	○ Smooth 

4. Nerves
	○ Nerve bundles from CNS 
            ○ Bundles found in muscle tissue
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4
Q

Explain what is meant by a “protein structural hierarchy”

A

Primary – linear chain of sequential amino acids
Secondary – AA chains folded into alpha-helix or beta-plated sheets
Tertiary – interact with protein regions & forms final protein structure
Quaternary – multiple protein complex which define function

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5
Q

Describe the structure of a peptide bond, its properties and influence on protein structure.

A

Structure = A-carbon w/ 4 bonds – R group, H, amino group & carboxyl group

Properties = links carboxyl & amino groups together

Influence = planar – double bond, O pulls electrons, fold rotating bonds around alpha carbon

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6
Q

Describe the types of chemical bonding responsible for determining protein conformation.

A

Chemical Bonding Protein Conformation
Covalent Primary (peptide bond)
Hydrogen Secondary
Ionic Tertiary & Quaternary (electrostatic)
Hydrophobic Tertiary & Quaternary (Van der Waals)

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7
Q

Explain the following terms: α-helix; coiled-coil; parallel and antiparallel β-pleated sheets; domain

A

A-helix – hydrogen bonding 4 residues apart, clockwise, R group outward

Parallel B – H bonds interact w/ chains, planar (sheet), tetrahedral (bent), amino top & carboxyl down orientation (1 direction)

Antiparallel B – 2 peptide strands running in opposite directions held together by hydrogen bonding between the strands

Tertiary Domain – region of polypeptide chain which forms a stable independent structural tertiary unit

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8
Q

Use haemoglobin as an example of a protein possessing quaternary structure, the function of which depends on conformation.

A

Haemoglobin
□ a carrier protein, transporting 02 or C02 around the body
□ made up from 2 pairs of different polypeptide chains (4 subunits)

  1. Starts in T (tense) state
  2. one oxygen attaches to haemoglobin
  3. conforms quaternary structure into R (relaxed) state
  4. higher affinity for oxygen & o2 molecules attach quickly = sigmoid curve
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9
Q

Outline the structure of collagen, explaining how its triple gamma-helix differs from that of an alpha-helix

A

Collagen
□ 3 helical chains that wind around central axis
□ Gly-X-Y
□ X = amino acid (proline/lysine or hydroxylysine)
□ Y = hydroxyl group (proline or hydroxyproline)
□ Gly = glycine in centre of each helix

Differs = collagen R group inwards (alpha outwards), 1 vs 3 chains

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10
Q

Explain the detrimental functional consequences that may ensure when conformational variants are formed, using prion proteins as examples and to explain their role in BSE and Scrapie

A

Prions
□ Transmissible via contaminated feed (eating other infected animals)
□ Protein is an infectious agent (conformational change)

BSE = bovine spongiform encephalopathy
□ Toxic build up of plaque in brain neural tissue

Scrapie = sheep
□ PrPc transforms into PrPSc causing fibrils to aggregate into neural tissue as
plaque

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11
Q

Define the following terms: substrate; product; reaction rate; equilibrium constant; rate constant; activation energy; induced fit

A

Substrate – beginning component

Product – end component

Reaction rate – how fast substrate turns into product or vice versa

Equilibrium constant – ratio between both rate constants (forward & back)

Rate constant – measuring combined rate of reaction forward or backward

Activation energy – how much free energy is needed for transition state

Induced fit – active site moulds itself around a substrate (flexible)

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12
Q

Outline the physical basis of how enzymes achieve massive reaction rate increases as compared with uncatalysed reactions.

A
  • Enzymes lower activation energy needed for a transition state
    • Enzymes only speeds up rate to reach equilibrium
    • No difference in free energy or equilibrium constant
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13
Q

Explain in qualitative terms using a graphical representation of enzyme activity plotted against substrate concentrations. (Michaelis-Menten Kinetics)

A
  • Hyperbolic profile
    • Inc. substrate conc. = inc. rate of reaction
    • Plateaus at Vmax (all binding sites saturated)
    • Enzymes determine speed of forward & back rate constants
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14
Q

Outline the properties of an allosteric enzyme and explain qualitatively how its action differs from enzymes exhibiting Michaelis-Menten kinetics.

A

Allosteric enzyme properties
- Bind to allosteric sites on enzymes at start/end/branching parts of metabolic
pathway

Feedback regulation – conforms active sites of enzymes

- Inhibitors stabilise T states
- Activators stabilise R states

Differs – use half Vmax, activator shift curve left (less sub.), inhibitor shift right
(more sub.)

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15
Q

Outline the control of enzymatic activity by: phosphorylation/dephosphorylation, protein and/or nucleotide binding, Ca2+ binding in EF-hand, proteolysis.

A

Phosphorylation
□ Control covalent bonding
□ Kinase enzymes involved (serine/threonine & tyrosine)
□ Specificity – to adjacent residues, determine which AA get phosphorylated
□ Requires ATP –> ADP + P (added to protein)

Dephosphorylation
□ Phosphatases enzymes involved
□ Phosphate gets removed from protein

Regulatory Proteins/Nucleotides
□ Inactive – cAMP-dependant protein kinase (regulatory & catalytic subunits)
□ Cyclic AMP activates enzyme kinase activity
□ Active – cAMP in regulatory subunits & catalytic subunits separate

Ion Binding (Calcium EF-hand)
□ High volume of Ca enter cell (usually kept out)
□ Calcium binds to tight loop connected to 2 a-helixs E & F

Proteolysis
□ Sequential activation of protease activity
□ ensures rapid signal amplification.
□ Protease factors –> prothrombin –> thrombin –> fibrogen –> fibrin –> clot

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16
Q

Define the terms: nucleic acid, DNA, RNA, nucleotide.

A

Nucleic acid – polymer of nucleotides (long repeating chains)

DNA – deoxyribonucleic acid (double helix)

RNA – ribonucleic acid (single strand)

Nucleotide – 5 carbon sugar ring, nitrogenous base & 1-3 phosphate groups

17
Q

Discuss the structures of DNA and RNA outlining their similarities and differences.

A

DNA – double helix, thymine pyrimidine, deoxyribose sugar (2’ prime lacks hydroxyl group)

RNA – single strand, uracil pyrimidine, ribose sugar

18
Q

Understand how nucleotides are linked together to form chains and how base-pairing across chains allows for the double helix structure of DNA.

A

Phosphodiester bonds – link nucleotides = nucleic acids

DNA directionality – 5’ prime hydroxyl to 3’ prime hydroxyl

Watson-Crick DNA pairing – A=T (2 H bonds), G—C (3 H bonds)

Double helix – sugar phosphate backbones & bases stacked centrally on top of each other, bases in grooves

19
Q

Outline the process of DNA replication understanding the terms: origin of replication, replication fork, leading and lagging strand

A

Origin of Replication - a particular sequence in a genome at which replication is initiated
Replication Fork – The separation of the two single strands of DNA creates a ‘Y’ shape via helicases
Strands – synthesised in opposite direction

DNA Replication Process
□ 1. Enzymes unwind the parental double helix
□ 2. Proteins stabilize the unwound parental DNA
□ 3. The leading Strand is synthesized continuously by DNA polymerase.
□ 4. The lagging strand is Synthesized discontinuously.
□ 5. DNA polymerase digests RNA primer and replaces it with DNA
□ 6. DNA ligase joins the discontinuous fragments of the lagging strand

20
Q

Explain how DNA is compacted into chromatin within eukaryotic cells.

A
  • Package & condense DNA, prevent DNA damage & control gene expression
    • Nucleosome is basic structure of chromatin (beads on a string)
    • Histone H1 proteins pull nucleosome together to condense chromatin further
21
Q

Outline the basic structures of nucleosomes, 30nm/solenoid fibre, chromosome.

A

Nucleosome – 146bp of DNA wrapped 1.7x around its core, core = octamer of
histone proteins connected by linker DNA

30nm/solenoid fibre – H1 histone protein brings nucleosomes together into rings,
multiple stacked rings form fibre

Chromosome – chromatin, nucleosomes, histones & DNA helix

22
Q

Understand the basics of polymerase chain reaction (PCR) and DNA sequencing.

A

Polymerase Chain Reaction
□ 1. Heat 94 degrees to denature (separate) DNA strands
□ 2. Cool 50-60 degrees to anneal primers onto DNA strands
□ 3. Heat 72 degrees for DNA polymerase to build complementary DNA strands (elongate new strands)

DNA sequencing
□ PCR replicate DNA fragment to produce large quantities for analysis
□ dNTPs & ddNTPs terminate chains at different lengths via denature, annealing & elongation
□ each NTP has fluorescent tag for each nitrogenous base
□ separated through gel electrophoresis