Principles & Instruments PT 1 Flashcards
2D image is composed of
pixels
3D image elements
voxels
an ellipse can be used to measure
area
comet tail and ring down are
reverberation artifacts
contrast res =
dynamic range / shades
What is the contrast res for a system with a 4 bit memory and 32 dB dynamic range?
2 dB/shade
4 bit memory will use 16 shades of gray (2x2x2x2)
contrast res = dynamic range over shades
32 dB / 16 shades = 2 dB/shade
advantage of virtual beam forming (VBF) over traditional pulse echo imaging (PEI)
VBF allows for simultaneous real-time gray scale, color, and spectral doppler display
why can VBF display info collected in all 3 modes?
it allows for very fast frame rates
in traditional PEI, the gray scale and color image
is frozen or refreshes very slowly while doppler tracings are displayed
VBF uses ______ to improve detail resolution across the whole image, ______ is not needed
receive focusing
transmit focusing
Pulse-echo systems use strength and _____ of received signals to create the gray scale image. Magnitude and _____ of the received signal are used to create the doppler display
time of flight
direction
gain =
ratio of amplifier output to the electric power input (measured in dB)
increasing the number of bits per pixel in an image memory will improve the
contrast resolution
the ability of a display to distinguish between echoes of different intensities
contrast resolution
increased pixel number with higher numbers of bits per pixel will demonstrate
the best contrast res on a digital display
bit density and contrast res relationship
direct
more bits per pixel = more shades of gray =
improved contrast res
spatial compounding can reduce
artifacts like enhancement or shadowing
shut this function off to make a stone more evident
reducing rejection or increasing dynamic range will _____ the number of grays on the image
increase
pulse duration
time it takes for one pulse to occur
System control that simultaneously enhances far field echoes and diminishes near field echoes
time gain compensation
increases amplitude of all reflections to create image
overall gain
transducer component that reduces sensitivity and efficiency of the US system
damping layer by preventing the lowest intensities from forming
circumference =
area =
volume =
cm
cm^2
cm^3
8 bit of memory has how many shades of gray?
256 shades of gray
8 bit memory has 2^8 = # of shades of gray = 2x2x2x2x2x2x2x2 = 256 shades of gray
removes low amplitude signals and noise from the image
increasing rejection
increases the # of shades of gray displayed on the image, including low level echoes and noise
increasing compression
amplification of the received signal occurs in the
beam former
the beam former generates
the voltages applied to the transducer
the beam former determines
PRF, frequency, and intensity of the beam
scanning, focusing, and apodization are functions of the
beam former
US system component responsible for changing PRF with changes in depth
pulser
adjusts timing of voltage applied to crystal to adjust PRF
pulser
allows focusing at multiple depths on the image
dynamic receive focusing (NOT ADJUSTABLE)
System component responsible for 3D image acquisition and presentation
image processor
____ is predominant factor causing attenuation of the US beam and can be counteracted by ____
sound absorption
increasing TCG settings in the far field
tissue harmonic imaging
reduces grating lobe and side lobe artifacts
cine is
postprocessing that allows for review of the stored image data from the last few seconds of real time scanning
M-Mode horizontal axis and vertical axis
time (horizontal)
distance (vertical)
2D imaging is best when the US beam strike the specular interface at what angle?
90 degrees
perpendicular angle of incidence increases
specular reflection
system control to improve anterior aortic wall
center beam perpendicular to vessel wall
contrast resolution (dB/shade) =
dynamic range / # of shades of gray
converts scan line data into image format for display
image processor
period of 5 MHz transducer
.2 microseconds
5 MHz = 5,000,000 Hz
period = 1 / frequency = 1/5,000,000 = .0000002 s