PRACTICE TEST 1, 2 & 3 Flashcards
WHAT TYPE OF TESTING DOES THE
BLOOD BANK TECHNOLOGIST PERFORM
WHEN DETERMINING BLOOD GROUP
OF A PATIENT?
A. Genotyping
B. Phenotyping
C. Both genotyping and phenotyping
D. Polymerase Chain Reaction
B. Phenotyping
WHICH OF THE FOLLOWING IS TRUE?
A. An individual with the AB genotype is homozygous
for A and B
B. An individual with the BO genotype is homozygous
for B
C. An individual with the OO genotype is
heterozygous for O
D. An individual with the BB genotype is homozygous
for B
D. An individual with the BB genotype is
homozygous for B
WHICH GENOTYPE IS HETEROZYGOUS
FOR C?
A. DCE/DCE
B. Dce/dce
C. dCE/dCe
D. Dce/dCe
D. Dce/dCe
WHICH GENOTYPE(S) WILL GIVE RISE TO THE BOMBAY PHENOTYPE?
A. HH only
B. HH and Hh
C. hh only
D. Hh and hh
C. hh only
LEXIE’S BLOOD TYPE IS AB. WHICH OF THE FOLLOWING DESCRIBES THE EXPRESSION OF MOST BLOOD GROUP ANTIGENS? A. Dominant B. Codominant C. Recessive D. Corecessive
B. Codominant
MEREDITH’S BLOOD TYPE IS AO AND HER HUSBAND, DEREK IS BO. WHAT BLOOD TYPE IS NOT POSSIBLE FOR THEIR OFFSPRING? A. AB B. A OR B C. O D. ALL ARE POSSIBLE
D. ALL ARE POSSIBLE
THE ALLEGED FATHER OF A CHILD IN A DISPUTED CASE OF PATERNITY IS BLOOD GROUP AB. THE MOTHER IS GROUP O AND THE CHILD IS GROUP O. WHAT TYPE OF EXCLUSION IS THIS? A. Direct/primary/ first order B. Random C. Probabiity D. Indirect/ secondary/ second order
D. Indirect/ secondary/ second order
IgM ANTIBODIES HAVE THE ABILITY TO
DIRECTLY AGGLUTINATE RBCs AND
CAUSE VISIBLE AGGLUTINATION, WHY
IS THIS SO?
A. IgM antibodies are larger molecules and have the ability to
bind more antigen
B. IgM antibodies tend to clump together more readily to
bind more antigen
C. IgM antibodies are found in greater concentrations than
IgG molecules
D. IgM antibodies are not limited by subclass specificity
A. IgM antibodies are larger molecules and have the ability
to bind more antigen
RANJIT’S SERUM IS INCOMPATIBLE WITH O CELLS.
HIS RBCs GIVE A NEGATIVE REACTION TO ANTI-H
LECTIN. WHAT IS THE MOST LIKELY CAUSE OF THESE
RESULTS?
A. The patient may be a subgroup A
B. The patient may have an immunodeficiency
C. The patient may be a Bombay individual
D. The patient may have developed alloantibodies
C. The patient may be a Bombay individual
WHAT ANTIBODIES ARE FORMED BY A BOMBAY INDIVIDUAL? A. Anti-A and Anti-B B. Anti- A,B C. Anti- A, anti-B and anti-H D. Anti-H
C. Anti- A, anti-B and anti-H
ACQUIRED B ANTIGENS HAVE BEEN FOUND IN? A. Group A persons B. Bombay individuals C. Group O D. All blood groups
A. Group A persons
A PATIENT’S RBC FORWARD TYPES AS GROUP O BUT
THE SERUM AGGLUTINATES B CELLS (4+). YOUR
NEXT STEP WOULD BE?
A. Extend reverse typing for 15 mins
B. Perform an antibody screen, including a room temperature
incubation
C. Incubate washed red cells with Anti-A1 and anti-A,B for
thirty mins at room temperature
D. Test patient’s cells with Dolichos biflorus
C. Incubate washed red cells with Anti-A1 and anti-A,B for
thirty mins at room temperature
WHICH BLOOD GROUP HAS THE LEAST AMOUNT OF H ANTIGEN? A. A1B B. A2 C. B D. A1
A. A1B
TED’S GENOTYPE IS Dce/dce. HOW IS HE CLASSIFIED? A. Rh positive B. Rh negative C. Rh null D. Rh stallion
A. Rh positive
TESTING FOR Rh ANTIBODIES ARE USUALLY?? A. IgM B. IgM and IgG C. IgG D. IgA
C. IgG
WHAT TECHNIQUES ARE NECESSARY FOR WEAK D TESTING? A. Saline + 22°C incubation B. Albumin or LISS + 37°C incubation C. Saline + 37°C incubation D. 37°C incubation + IAT
D. 37°C incubation + IAT
PENNY IS SUSPECTED OF HAVING PCH. WHICH
PATTERN OF REACTIVITY IS CHARACTERISTIC OF THE
DONATH-LANDSTEINER ANTIBODY?
A. The antibody attaches to RBCs at 4°C and causes
hemolysis at 37° C
B. The antibody attaches to RBCs at 37° C and causes
agglutination at the IAT phase
C. The antibody attaches to RBCs at 22 ° C and cause
hemolysis at 37° C
D. The antibody attaches to RBCs and causes agglutination at
the IAT phase
A. The antibody attaches to RBCs at 4°C and causes
hemolysis at 37° C
HOW CAN INTERFERING ANTI-P1 ANTIBODY BE REMOVED FROMA MIXTURE OF ANTIBODIES? A. Neutralization with saliva B. Agglutination with human milk C. Combination with urine D. Neutralization with hydatid cyst fluid
D. Neutralization with hydatid cyst fluid
AN ANTIBODY SHOWS STRONG REACTIONS IN ALL TEST
PHASES. ALL SCREEN AND PANEL CELLS ARE POSITIVE. THE
SERUM IS THEN TESTED WITH A CORD CELL AND THE
REACTION IS NEGATIVE. WHAT ANTIBODY IS SUSPECTED?
A. Anti-i
B. Anti-I
C. Anti-H
D. Anti-p
B. Anti-I
WHICH GROUP OF ANTIBODIES ARE COMMONLY FOUND AS COLD AGGLUTININS? A. Anti-K, anti-k and anti-Jsb B. Anti-D, anti-e, anti-C C. Anti- fya, anti-Fyb D. Anti-M and anti-N
D. Anti-M and anti-N
WHICH OF THE FOLLOWING ANTIBODIES CHARACTERISTICALLY GIVES A REFRACTILE MIXED-FIELD APPEARANCE? A. Anti-Sda B. Anti-s C. Anti-K D. Anti-Dia
A. Anti-Sda
An emergency trauma patient requires transfusion. 6 units of blood are ordered stat. because of hypovolemia, blood extraction was difficult and was not able to submit sample. O negative blood is released. When will compatibility testing be performed?
A. Compatibility testing must be performed before blood is
issued.
B. Compatibility testing will be performed when a patient
sample is available
C. Compatibility testing may be performed immediately using
donor serum
D. Compatibility testing is not necessary when blood is
released in emergency situations.
B. Compatibility testing will be performed when a patient sample is available
CAN CROSSMATCHING BE PERFORMED ON OCTOBER 14
USING A PATIENT SAMPLE DRAWN ON OCTOBER 12?
A. Yes, a new sample would not be needed
B. No, a new sample is needed because the 2 day limit has
expired
C. No, a new sample is needed for each testing
D. The discretion is based on the ordering physician
A. Yes, a new sample would not be needed
A MAJOR CROSSMATCH AND SCREENING CELLS ARE 2+ AT
IS, 1+ AT 37°C AND NEGATIVE AT THE IAT PHASE. IDENTIFY
THE MOST LIKELY PROBLEM?
A. Combination of antibodies
B. Cold alloantibody
C. Rouleaux
D. Test error
B. Cold alloantibody