Practice Test #1 Flashcards
What Ethernet feature will allow increased FCoE network throughput as long as all network devices recognize their specific size?
Quality of service
Jumbo frames
Frame relay
TCP offloading
Jumbo frames
OBJ 2.2: By allowing jumbo frames, network throughput can be increased. Fibre Channel over Ethernet (FCoE) is a computer network technology that encapsulates Fibre Channel frames over Ethernet networks. This allows Fibre Channel to use 10 Gigabit Ethernet networks (or higher speeds) while preserving the Fibre Channel protocol. Jumbo frames are Ethernet frames with more than 1500 bytes of payload, the IEEE 802.3 standard limit.
You work for Dion Training as a physical security manager. You are concerned that the physical security at the entrance to the company is not sufficient. To increase the security, you are determined to prevent piggybacking. What technique should you implement first?
Install a RFID badge reader at the entrance
Require all employees to wear security badges when entering the building
Install CCTV to monitor the entrance
Install an access control vestibule at the entrance
Install an access control vestibule at the entrance
Overall explanation
An access control vestibule, or mantrap, is a device that only allows a single person to enter per authentication.
Which of the following authentication protocols was developed by Cisco to provide authentication, authorization, and accounting services?
TACACS+
RADIUS
Kerberos
CHAP
TACACS+
TACACS+ is an extension to TACACS (Terminal Access Controller Access Control System) and was developed as a proprietary protocol by Cisco.
Which of the following communication types can only be used with IPv6?
Broadcast
Anycast
Multicast
Unicast
Anycast
OBJ 1.4: Anycast only works with IPv6. Anycast communications are sent to the nearest receiver in a group of receivers with the same IP.
What is the broadcast address associated with the host located at
189.76.60.164/26?
189.76.60.192
189.76.60.191
189.76.60.129
189.76.60.128
189.76.60.191
Explanation:
The notation /26 means that the first 26 bits of the IP address are used for the network portion. The corresponding subnet mask in dotted-decimal notation is 255.255.255.192. With /26, there are 6 bits available for host addresses (since 32 - 26 = 6), resulting in 2⁶ = 64 total addresses per subnet.
Step 2: Determine the Subnet’s Range
Since each subnet contains 64 addresses, the valid ranges (in the fourth octet) will increment by 64. The possible ranges in the fourth octet are as follows:
0 to 63, 64 to 127, 128 to 191, 192 to 255.
Step 3: Locate the Host’s Subnet
The given IP address is 189.76.60.164. Look at the last octet (164) to determine which block it falls into. Since 164 is between 128 and 191, the network this address belongs to starts at 189.76.60.128.
Step 4: Identify the Broadcast Address
In any subnet, the broadcast address is the very last address in the range. For a subnet that starts at 189.76.60.128 and has 64 addresses, the broadcast address is:
Network Address + (Total Addresses - 1)
= 128 + 63
= 191
Thus, the broadcast address is 189.76.60.191.
