POF Q36 - Limitations Flashcards
A jet transport aeroplane is in a straight climb at a constant IAS and constant weight. The operational limit that may be exceeded is:
Select one:
a.VMO.
b.MMO.
c.VA.
d.MD.
b.MMO.
Which of these statements about flutter are correct or incorrect? 1) If flutter occurs, IAS should be reduced. 2) Resistance to flutter increases with increasing wing stiffness.
Select one:
a.1) is correct, 2) is incorrect.
b.1) is incorrect, 2) is incorrect.
c.1) is incorrect, 2) is correct.
d.1) is correct, 2) is correct.
d.1) is correct, 2) is correct.
VLE is defined as the:
Select one:
a.maximum flap extended speed.
b.maximum speed at which the landing gear may be extended or retracted.
c.maximum authorised speed.
d.maximum landing gear extended speed.
d.maximum landing gear extended speed.
What is the relationship of VMO and MMO, in a climb and descent?
Select one:
a.If climbing at VMO, it is possible to exceed MMO.
b.If descending at MMO, VMO cannot be exceeded.
c.If climbing at VMO, Mach number is decreasing.
d.If climbing at MMO, Indicated Airspeed is increasing.
a.If climbing at VMO, it is possible to exceed MMO.
Which of these statements about flutter are correct or incorrect? 1) Mass balancing increases the likleyhood of flutter. 2) The risk of flutter increases as IAS increases.
Select one:
a.1) is correct, 2) is correct.
b.1) is incorrect, 2) is correct.
c.1) is incorrect, 2) is incorrect.
d.1) is correct, 2) is incorrect.
b.1) is incorrect, 2) is correct.
Control surface flutter can be reduced by:
Select one:
a.mass balancing of the control surface.
b.reducing structural stiffness of the control surface attachment structure.
c.increasing airspeed.
d.aerodynamic balancing of the control surface.
a.mass balancing of the control surface.
VMO:
Select one:
a.should not be greater than VC
b.should not be less than VD
c.should be chosen in between VC and VD
d.is equal to the design speed for maximum gust intensity
a.should not be greater than VC
A commercial jet aeroplane is performing a straight descent at a constant Mach number with constant mass. The operational speed limit that may be exceeded is:
Select one:
a.MMO.
b.VD.
c.VNE.
d.VMO.
d.VMO.
What can happen to the aeroplane structure flying at a speed just exceeding VA?
Select one:
a.It may suffer permanent deformation because the flight is performed at too large dynamic pressure.
b.It may break if the elevator is fully deflected upwards.
c.It will collapse if a turn is made.
d.It may suffer permanent deformation if the elevator is fully deflected upwards.
d.It may suffer permanent deformation if the elevator is fully deflected upwards.
What may happen if the “ultimate load factor” is exceeded?
Select one:
a.Structural failure.
b.No structural failure, only plastic or permanent deformation.
c.Elastic or temporary deformation only.
d.Flutter.
a.Structural failure.
The positive manoeuvring limit load factor for a light aeroplane in the utility category in the clean configuration may not be more than:
Select one:
a.4,4
b.2,5
c.6
d.3,8
a.4,4
Which factor should be taken into account when determining VA?
Select one:
a.The limit load factor.
b.The calculation factor.
c.The ultimate load factor.
d.The safety factor.
a.The limit load factor.
How does VA (EAS) change when the aeroplane’s mass decreases by 19%?
Select one:
a.VA does not change.
b.19% reduced.
c.4,36% reduced.
d.10% reduced.
d.10% reduced.
The manoeuvring speed VA, expressed as indicated airspeed, of a transport aeroplane:
Select one:
a.depends on aeroplane mass and pressure altitude.
b.depends on aeroplane mass and is independent of pressure altitude.
c.is independent of aeroplane mass, but dependent on pressure altitude.
d.is a constant value.
a.depends on aeroplane mass and pressure altitude.
An aircraft has a mass of 60.000 kg and a limiting positive load factor of 2,5 g. VA is calculated as the EAS at which full positive elevator deflection will give the limiting load factor at the stall, and is 237 kts. If the aircraft mass is reduced to 40.000 kg by fuel burn, what will be the new VA?
Question 15 Select one:
a.150 kts
b.237 kts
c.194 kts
d.375 kts
c.194 kts
Vs new = Vs old x √(new mass ÷ old mass)
Va new = 237 x √(40000 ÷ 60000)
Va new = 193.51 knots