oxidation Flashcards

1
Q

can alkyl side chains be oxidized

A

yes

terminal carbon oxidation and w-1 carbon oxidation

oxidized to corresponding alcohol.
terminal carbon oxidation produces a primary alcohol that can either be used in conjugation reactions OR can be oxidized further to aldehyde-> carboxylic acid via ADH and ALDH

w-1 carbon oxidation produces a secondary alcohol that can be oxidized further to ketone via ADH or used in phase 2 reactions

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2
Q

what catalyzes the oxidation of alkyl side chains

A

MFO system

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3
Q

what catalyzes the oxidation of alcohols

A

ADH

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4
Q

oxidative deamination occurs on…

A

primary amines on primary substituted Carbon atom

primary amines on secondary substituted carbon atom

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5
Q

explain oxidative deamination mechanism

A

primary amines on primary substituted carbon:

oxidized to corresponding alcohol - chemically unstable intermediate (carbinolamine) falls apart to produce aldehyde + ammonia (NH3)

primary amines on secondary substituted carbon - carbinolamine intermediate falls apart and ketone + NH3 produced

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6
Q

what reaction occurs on tertiary alkyl amines

A

N-dealkylation

in the case of 2 alpha carbons 2 reactions are possible. either top or bottom carbon can be oxidized. unstable intermediate (carbinolamine) is formed which falls apart and alkyl group leaves

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7
Q

reactions possible on tertiary amines

A

tertiary alkyl amines: N-dealkylation

other tertiary amines (like pyridine) - N-oxide formation

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8
Q

what oxidation reaction is SLOW

A

oxidation of dialkyl amides

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9
Q

hemi acetal is a ___ metabolite

A

oxidative

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10
Q

what reaction produces a hemi acetal intermediate

A

O-dealkylation

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11
Q

explain the mechanism/products of O-dealkylation

A

produces a chemically unstable oxidative metabolite (hemi acetal) that falls apart spontaneously to produce the corresponding ALCOHOL + aldehyde

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12
Q

what reaction produces sulfone

A

sulfoxidation of thioethers (sulfides).

sulfides are first oxidized to sulfoxides (reversible) and then sulfoxides are oxidized to sulfone (IRREVERSIBLE in most cases)

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13
Q

what reaction produces hemithioacetal

A

the oxidation of a sulfide with 1 R group being methyl

this is VERY UNSTABLE – even more unstable than hemiacetal because S is a good leaving group

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14
Q

explain the oxidation of thioethers with 1 R group being methyl

A

The C in methyl is the alpha carbon which gets oxidized to its corresponding alcohol.

this forms a HIGHLY UNSTABLE hemithioacetal intermediate which falls apart to produce formaldehyde + thiol (sulfhydryl)

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15
Q

explain the oxidation of nitriles

A

no direct oxidation on Cyano group (c triple bond N) in humans, but it is possible for the microorganisms in the gut

if there is another carbon attached to the cyano C with at least 1 available hydrogen, oxidation is possible and a cyanohydrin intermediate is produced. produces CYANIDE + corresponding aldehyde

CYANIDE IS TOXIC

cyano groups are allowed in drugs if hydrophilic enough (acetonitrile) CH3-C triple bond N

once carbons start being added it becomes a problem

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16
Q

explain the mechanism of oxidation of carbon-carbon triple bond

A

oxidized to a hypothetical intermediate, hydride shift and then a ketene is formed.
reacts with water to produce corresponding carboxylic acid

17
Q

what structures undergo N-hydroxylation

A

aromatic amides
barbiturates
others

18
Q

how many possible choices are there for N-hydroxylation on barbiturates?
are they both likely to occur?

A

2 possible choices, but it is likely that only 1 will occur because the purpose of phase 1 is just to introduce a polar functional group

19
Q

AR-NH2 is likely to undergo N-hydroxylation

what is a very important consideration

A

if the aromatic ring is 2 or more fused rings. the NITRENIUM ION is produced because there is enough stability to keep it there

AR-N+-H

potent carcinogen

20
Q

explain the reactions possible for carbon carbon double bonds

A

cis olefin will be oxidized to produce cis epoxide
trans olefin will be oxidized to produce trans epoxide

these epoxides are CHEMICALLY REACTIVE so we dont want them floating around for too long,

therefore, they are hydrolyzed by epoxy hydrase to produce DIOL

21
Q

explain the oxidation of aromatic systems

A

arene oxide formation. arene oxide is CHEMICALLY REACTIVE and can be intercepted by arene oxide hydrase (epoxy hydrase) to form a dihydro diol.
then, dihydro dehydrogenase removes the 2 H’s to form a stabilized DIOL

OR

arene oxide can undergo further reactions to produce PHENOL (para mostly) if the R substituent is electron donating

22
Q

which has weaker activation energy – C-H or C-D? what does this mean?

A

C-H is weaker so that bond is clipped in the NIH shift demonstration

23
Q

where is a likely place for hydroxylation?

A

at the benzylic carbon (carbon attached to aromatic ring)

24
Q

can azo compounds be oxidized?

A

yes - in aromatic and aliphatic azo compounds, one N can be oxidized to form azoxide

25
Q
A