Organic Chemistry Reactions 2

Question 1

what type of reaction uses Br2 (uv)

alkane

Answer 1

subsitution

Question 2

what type of reaction uses H2, and what does it form

alkene

Answer 2

addition

forms alkane chain, H is added

Question 3

H+/MnO4

Alkene

Answer 3

Oxidation: breaks Double bond and adds H

forms a diol

Question 4

Br2

alkene

Answer 4

addition: adds 2 Br

Question 5

HBr

H x any halide

Answer 5

Addition, Br and H is added

Placement depends on major and minor

Question 6

H2O/H+

alkene

Answer 6

addition: forms alcohol
O-H and H is added,
placement depends on major and minor

Question 7

Conc H2SO4

Alcohol

Answer 7

elimination: craetes a double bond, eliminates the O-H’s and H to do so

Question 8

PLC3, PLC5, SOCL2

alcohol

Answer 8

Substitution: Cl is replaces the O-H

Question 9

H+/MnO4 - H+/Cr2O7 -2

alcohol

Answer 9

Oxidation: double bond with O,
OH stays on same C.
Carboxylic acid

Question 10

H2O

Carboxylic acid

Answer 10

acid reactions: double bond with O stays, H is taken off O-H. molcule is + H3O+
equilibrium

Question 11

Na: Metal

Carboxylic acid

Answer 11

acid: double bond with O stays, DNa replaces OH

molecule + H2. molecule = salt

Question 12

Na2CO3: metal carbonate

carboxylic acid

Answer 12

acid: double bond with O stays, DNa replaces OH. Molecule (salt) + CO2

Question 13

NaOH: Base

carboxylic acid

Answer 13

acid: double bond with O stays, DNa replaces OH. Molecule (salt) + H2O

Question 14

KOH (aq) minor from Br

Haloalkanes

Answer 14

substitution (done with minor from HBr reaction): OH replaces Br alcohol

Question 15

Conc NH3 (alc)
Haloalkanes

Answer 15

Substitution: NH2 replaces Br (from Hbr reaction) amine

Question 16

KOH (alc) major from Br

Haloalanes (sayteffs rule)

Answer 16

elimination: double bond is formed with a major and minor, from where the Br was, (from HBr reaction)