Organic Chemistry Flashcards

1
Q

What is the following called that has a carbon with a halide group on it?

A

Alkyl Halide

IUPAC = halo- and -halide

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2
Q

What is it called when a halide is located on a chain with a carbonyl group?

A

Acyl halide

IUPAC = halocarbonyl- and -oyl Halide

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3
Q

What is the IUPAC ending for alcohol?

A

C-OH

IUPAC = Hydroxy- and -ol

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4
Q

What is the IUPAC for Aldehyde?

A

C-HO

IUPAC = oxo- and -al

Terminal Group

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5
Q

What is the IUPAC for Ketone?

A

IUPAC = oxo- and -one

Not terminal, in the middle

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6
Q

What is the IUPAC for carboxylic Acid?

A

COOH-

IUPAC = Carboxy- and -oic acid

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7
Q

What is the IUPAC for ether?

A

C-O-C

IUPAC: alkoxy- and -ether

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8
Q

What is the IUPAC for ester?

A

C-O-C=0-C

IUPAC: alkoxycarbonyl- and oate

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9
Q

Explain the IUPAC for Amine

A

C-NH2

IUPAC : amino- and -amine

C-N (same as peptide bonds)

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10
Q

Explain the IUPAC for Amide

A

C=0-NH2

IUPAC: amido- and -amide

(derivative like carboxylic acid….. d=derivative)

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11
Q

Explain the IUPAC for Imine

A

C=N

IUPAC: Imino- and =imine

(Two i’s like in imine meaning double bond)

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12
Q

What is the IUPAC for Nitrile?

A

-C=-(Triple bond) N

IUPAC: cyano- and -nitrile

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13
Q

What is the IUPAC for Thiol?

A

C-SH

IUPAC: sulfhydryl- and -thiol

like an alcohol

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14
Q

What are the common reagents to oxidize an alcohol, ketone or aldehyde?

A

To a ketone, aldehyde or carboxylic acid:

KMnO4

K2Cr2O7

CrO3 (Jones Reagent)

Ag2O (Tollen’s Reagent)

H2O2

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15
Q

What are the common reagents to reduce a carboxylic acid, ketone or aldehyde?

A

To an Alcohol:

LAH (Strong - can reduce carboxylic acid)

NaBH4 (Mild - can only reduce aldehyde or ketone)

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16
Q

Explain the Wolff-Kishner reduction reaction

A

The carbonyl is converted to a hydrazone, releases N2. When heated it forms an alkane

  • Must be done in basic solution
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17
Q

Explain the Clemmensen Reduction Reaction

A

Aldehyde or ketone is heated with amalgamated zinc in hydrochloric acid

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18
Q

Explain enolization tautomerization

A

-ene (double bond) + -ol (alcohol) = -enol

Where the keto form is favored due to the carbonyl group

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19
Q

Explain the Michael addition reaction

A

Strong base such as lithium diisopropyl amide (LDA) or potassium hydride (KH) either of which remove the proton from the -OH group. The resulting nuceophilic carbonion will react via an SN2 mechanism with an alpha-beta-unsaturated carbonyl compund in this reaction

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20
Q

Explain an hydration reaction with an aldehyde and ketone

A

presence of water, aldehyde and/or ketone a geminal diol will form

  • water acts as a nucleophile attacking at the carbonyl carbon
  • rate slow, but can be increased with addition of acid or base
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21
Q

Explain the formation of an acetal and ketal

A

Hemiacetal or hemiketal = one side OH & other OR

acetal or ketal = both sides OR

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22
Q

Explain the reaction with an aldehyde and/or ketone and HCN (Hydrogen cyanide)

A

HCN dissociaes and the strongly nucleophilic cyanide anion attacks the carbonyl carbon attom

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23
Q

What is it called when a reaction where water is lost between two molecules?

A

condensation reaction

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24
Q

Explain condensation with ammonia derivative reactions

A

The carbonyl group is attacked by the ammonia group

the oxygen leaves as H2O and the ammonia group takes over the double bond spot.

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25
Q

Explain an aldol condensation reaction

A

Two aldehyde’s react with an alcohol to combine together to form an aldol.

If the aldol is heated, the molecule will undergo elimination and will loose the alcohol to produce a water

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26
Q

explain the process of the wittig reaction

A

Method of forming C=C double bonds by converting aldehydes and keytones into alkenes (C=O becomes C=C)

  • First step: phosphonium salt from the SN2 rxn of an alkyl halide with the nucleophile triphenylphosphine (C6H5)3P. The phosphonium salt is then deprotonated with a strong base, yeilding a neutral ylide or phosphorane
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27
Q

Explain a halogenation reaction with aromatics

A

Halogenation adds a halogen to the aromatic ring with bromine or chlorine in the presence of a lewis acid, such as FeCl3, FeBr3 or AlCl3

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28
Q

Explain a sulfonation reaction of an aromatic ring

A

Ring reacts with fuming sulfuric acid (a misxture of sulfuric acid and sulfur trioxide) to form sulfonic acids

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29
Q

Explain nitration of aromatic rings

A

A mixture of nitric and sulfuric acids is used to create the nitronium ion, NO2+, a strong electrophile. This reacts with aromatic rings to produce nitro compounds

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30
Q

Explain acylation (friedel-crafts reactions)

A

A carbocation electrophile, usually an acyl group, is incoporated into the aromatic ring. These reactions are usually catalyzed by Lewis acids such as AlCl3.

This reaction can also be used to add alkyl groups, but the reaction is difficult to control and can lead to multiple products

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31
Q

Explain the three classes of substituents that impact the reactivity of an aromatic. (align in decreasing strength of effect)

A

1. Activating (ortho/para - directing Substituent)

  • Electron Donating

NH2 > NR2 > OH > NHCOR > OR > OCOR > R

2. Deactivating (ortho/para - directing Substituent)

  • Weakly Electron withdrawing

F > Cl > Br > I

3. Deactivating, Meta-directing substituents

  • Electron withdrwing

NO2 > SO3H > carbonyl compounds, including COOH, COOR, COR, and CHO

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32
Q

Explain catalytic reduction of a benzene ring

A

Ring can be reduced by catalytic hydrogenation under vigorous conditions (elevated temperature and pressure) to yeild cyclohexane. Ruthenium or rhodium on carbon are the most common catalysts; platinum or palladium may also be used

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33
Q

Explain the phenol synthesis reaction

A

Phenols may be synthesized from arylsulfonic acids with heat and NaOH. However, this reaction is useful only for phenol or its alkylated derivatives, as most functional groups are destroyed by the harsh reaction conditions

  • A more versatile method of synthesizing phenols proceeds using hydrolysis of diazonium salts
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34
Q

Explain elimination reactions of alcohols

A

Alcohols can be dehydrated in strongly acidic solutions (usually H2SO4) to produce alkenes.

The mechanism of this dehydration reaction is E1, and proceeds by first protonating the alcohol and then removing the water molecule to form the double bond

*Two products normally produced, major and minor based on their subsititution

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35
Q

Explain the oxidation using the Jones reagent

A

CH2OH side chain on a cyclic ring, turned into COOH using CrO3, H2SO4 in acetone

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36
Q

explain what happens when phenols are oxidized

A

Produce compounds called quinones (2,5 - cyclohexadiene-1,4diones

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37
Q

Explain the williamson ether synthesis

A

Produces asymmetrical ethers from the reaction of metal alkoxide ions with primary alkyl halides or tosylates The alkoxides behave as nucleophiles and displace the halide or tosylate in an SN2 reaction, producing an ether

**Williamson ether synthesis can also be applied to phenols. Relatively mild reaction conditions are sufficient, due to the acidity of phenols

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38
Q

Explain the synthesis of oxiranes

A

Cyclic ethers, oxiranes, are prepared in a number of ways. They can be synthesized by means of an internal SN2 displacement. Since the nucleophile and sustrate are part of the same molecule, they are in close proximity, facilitating the reaction

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39
Q

Explain the oxidation of an alkene with a peroxy acid (General Formula RCOOOH) such as mCPBA

A

Will produce an oxirane

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40
Q

Explain the cleavage of a straight-chain ether

A

Cleavage will take place only under vigorous conditions: high temperature in the presence of HBr or HI

  • Initiated by protonation of the ether oxygen
  • RxN proceeds via SN1 or SN2 mechanism, depending on the condition and the structure of the ether
  • usually producing an alkyl halide and an alcohol
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41
Q

Explain epoxide cleavage/opening of an ether

A

Reactions of epoxides provide additional insight into SN1 and SN2 reaction mechanisms.

  • Base-catalyzed cleavage of epoxides has the most SN2 character, so it occurs at the least hindered (least substituted) carbon. The basic environment provides the strong nucleophile required for SN2 reactions
  • Acid-catalyzed cleavage is thought to have some SN1 character as well as some SN2 character. The epoxide oxygen can be protonated, making it better leaving group. this give the carbons partial positive charges. Since substitution stabilizes this charge (tertiary carbson provide the most stable carbocations), the most substututed C becomes a good target for nuceophilic attack
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42
Q

What is this?

A

Acetic Acid

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43
Q

What is this?

A

Formic Acid

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44
Q

Explain oxidation reaction synthesis for carboxylic acids

A
  • Carboxylic acids can be prepared via oxidation of aldehydes, primary alcohols, and certain alkylbenzenes. Any strong oxidizing agent, including KMnO4, K2Cr2O7, and CrO3, will create a carboxylic acid.
  • A primary alcohol can also be oxidized first with PCC to create an aldehyde and then further oxidized with Tollen’s reagent to create the carboxylic acid
45
Q

Explain oxidative cleavage of alkenes to create a carboxylic acid

A

KMnO4, OH-, heat are used first then H+ to cleave the double bond and produce carboxylic acids

46
Q

Explain carbonation of organometallic reagents

A

Such as Grignard reagents, react with carbon dioxide (CO2) to form carboxylic acids. This reaction is useful for the conversion of tertiary alkyl halides into carboxylic acids, which cannot be accomplished through other methods. Note that this reaction adds one carbon atom to the chain

**Top row of image

47
Q

Is CN- a nucleophile or electrophile?

A

Strong nucleophile

Cyanide anion

and will displace primary and secondary halides in typical SN2 fashion

48
Q

explain the hydrolysis of Nitriles

A

Starting with an alkyl halide, a carboxylic acid can be produced by replacing the halide with a cyanide anion and then reacting with water to change the cyanide anion into -COOH

49
Q

Explain nucleophilic substitution

A

Nucleophile attacks the carbonyl group, carbonyl group reforms and kicks out a leaving group

50
Q

What is the key difference between nucleophilic substitution and nucleophilic addition?

A

Nucleophilic substitution is where the C=O bond reformes and there is an elimination of a leaving group

51
Q

Explain the carboxylic acid reduction reaction

A
  • Carboxylic acids can be reduced with lithium aluminum hydride (LAH) to their corresponding primary alcohols.
  • Aldehyde intermediates that may be formed in the course of the reaction with LAH are also reduced to their primary alcohol
  • The reaction occurs by nucleophilic addition of hydride (the H- ion) to the carbonyl group and elimination of water as a leaving group
52
Q

Explain the reactivity of the carboxylic acid derivatives in order

A
53
Q

Explain ester formation

A

**Need to keep water out of the reaction to make an ester or will reform carboxylic acid**

  • Carboxylic acids react with alcohols under acidic conditions, the oxygen on the carbonyl group can become protonated. This increases the polarity of the C=O bond, putting even more positive charge on the carbon and making it even more susceptible to nucleophilic attack
  • Again, water is eliminated as a leaving group, and the carbonyl re-forms
  • this condensation reaction occurs most rapidly with primary alcohols.
54
Q

Explain the Acyl Halide Formation reaction

A
  • Acyl halides = acid halides
  • Compounds with carbonyl groups bonded to halides
  • Several different reagents can accomplish this transformation; thionyl chloride, SOCl2, is the most common
  • Acid chlorides are very reactive, as the greater electron-withdrawing power of the Cl- makes the carbonyl carbon more susceptible to nucleophilic attack than the carbonyl carbon of the carboxylic acid. (Cl- also good LG)
55
Q

Explain decarboxylation of carboxylic acid

A
  • Carboxylic acids can undergo decarboxylation reactions, resulting in the loss of carbon dioxide and thus loss of the entire carboxyl group
  • The carboxyl group is lost and replaced with a hydrogen.
  • The reaction proceeds through a six-membered ring transition state.
  • The enol initially formed tautomerizes to the more stable keto form as the final product
56
Q

Explain micelle

A

Polar heads face outward, where they can be solvated by water molecules, and the nonpolar hydrocarbon chains are inside the sphere, protected from the solvent

57
Q

What are soaps normally made of?

A

A long-chain hydrocarbon with a highly polar end. Generally, this polar end or head is a salt of a carboxylic acid (with sodium ususally)

58
Q

what is the name of this?

A

acetyl chloride

or ethanoyl chloride

59
Q

What is the name of this?

A

Benzoyl chloride

60
Q

How does acyl halide boiling and melting point compare to carboxylic acid?

A

Acyl halides are less polar than comparable carboxylic acids, and demonstrate significantly lower melting and boiling points

61
Q

Explain a Grignard Reaction

A

** Strong carbon nucleophiles**

62
Q

Explain Diels-Alder Reaction

A

** Ring generating reaction **

63
Q

Explain the Wittig Alkene Synthesis

A

Begins with the attack of the nucleophile

64
Q

Explain the synthesis of the carboxylic acid

A

Reacts with water to form the carboxylic acid

65
Q

Explain the synthesis of Acyl Halides

A
  • The most common acyl halides are the acid chlorides, although acid bromides and iodides are occasionally encountered.
  • Acyl chlorides are prepared by reactions of a carboxylic acid with thionyl chlorides, SOCl2, producing SO2 and HCl as side products.
  • Alternately, PCl3 or PCl5 (or PBr3 to make acid bromide) can be used for this synthesis
66
Q

Explain the nucleophilic acyl subsitituation reaction of acyl halides

A

Halogen makes a strong electron-withdrawing group, making the carbonyl carbon more susceptible to nucleophilic attack than the carbonyl carbon of the carbonxylic acid.

  • Since halides are great LGs, nucleophilic attack will always be followed by re-formation of the carbonyl.
    • Therefore, acyl halides readily undergo nucleophilic substitution reactions, including hydrolysis (with H2O as nucleophile), which produces the origional carboxylic acid.
67
Q

Explain the hydrolysis reaction of acyl halides

A
  • Simplest reaction of acid halides is their conversion back to carboxylic acids by classic nucleophilic attack
  • Acyl halides react very rapidly with water to form their corresponding acid, along with HCL, which is responsible for their irritating odor
68
Q

Explain the conversion of acyl halides into anhydrides

A
  • Reaction of an acyl chloride with a carboxylate salt will produce an anhydride through nucleophilic attack and re-formation of the carbonyl
69
Q

Explain the Acyl Halide reaction conversion into an ester

A
  • Acyl halides can be converted into esters by reaction with alcohols.
  • The same type of nucleophilic attack found in hydrolysis leads to the formation of a tetrahedral intermediate, with the hydroxyl oxygen of the alcohol acting as the nucleophile
  • Chloride is displaced as the carbonyl re-forms, and the HCL is released as a side-product
70
Q

Explain the Acyl Halide reaction with conversion into amides

A
  • Nucleophilic substitution with amines
  • An amine, such as ammonia, attacks the carbonyl group, displacing chloride.
  • The side product is ammonium chloride, formed from excess ammonia and HCL.
  • Primary and secondary amines can also be used as nucleophile to create N-substituted amides
71
Q

Explain Friedel-Craft acylation with Acyl Halides

A
  • Aromatic rings can be acylated in a Friedel-Crafts reaction.
  • the mechanism is electrophilic aromatic substitution, and the attacking reagent is an acylium ion, formed by reaction of an acid chloride with AlCl3 or another Lewis acid.
  • The product is an alkyl aryl ketone
72
Q

Explain the reduction of Acyl Halides

A
  • Reduced to alcohol with a strong reducing agent such as LAH
  • Can also be selectively reduced to the intermediate aldehydes by catalytic hydrogenation in the presence of a “poison” such as quinoline, (AKA. Lindlar’s catalyst).
73
Q

What is the name of this compound?

A

acetic anhydride

No longer have -OH groups and therefore cannot form hydrogen bonds

74
Q

Explain the acyl chloride reaction to synthesis anhydride

A
  • Anhydrides can be readily synthesized by reaction of an acyl chloride with a carboxylate salt. this is the most effectient and most commonly used method of anhydride synthesis
75
Q

Explain cyclic anhydride self-condensation

A
  • Certain cyclic anhydrides can be formed simply by heating carboxylic acids. The reaction is driven by the increased stability of the newly formed ring; hence, only five- and six- membered ring anhydrides are easily made.
  • In this case, the hydroxyl of one - COOH group acts as a nucleophile, attacking the carbonyl on the other -COOH group and releasing water
76
Q

Explain the condensation of two carboxylic acids to form an anhydride

A
  • Two carboxylic acid molecules can condense to form an anhydride in a reaction releasing water; however, this reaction requires anhydrous conditions.
  • Therefore a dehydrating reagent that will remove the water produced in the reaction is neeeded to prevent immediate conversion back to the carboxylic acid
  • Reagents such as acetic anhydride, trifluoroacetic anhydride, phosphorus pentachloride, or dicyclohexylcarbodiimide (DCC) can be used for this purpose
77
Q

Explain the hydrolysis reaction of anhydride

A
  • Anhydrides are converted into carboxylic acids when exposed to water
  • Note that in this reaction, the leaving group is actually a carboxylic acid; because the anhydride is symmetrical, it produces two molecules of the same carboxylic acid
78
Q

Explain the conversion into amides from an anhydride

A
  • Anhydrides are cleaved by ammonia, producing an amide and a carboxylic acid.
  • The carboxylic acid then further reacts with ammonia to form an ammonium carboxylate
79
Q

explain the conversion of anhydride into esters and carboxylic acids

A

Anhydride + alcohol = ester + carboxylic acid

  • Anhydrides react with alcohols to form esters; a single anhydride molecule will produce one ester and also one molecule of carboxylic acid
80
Q

Explain Acylation of an anhydride

A
  • Friedel-Crafts acylation occurs readily with anhydrides in the presence of AlCl3 or other Lewis acid catalysts.
  • This reaction produces an aryl ketone and a carboxylic acid
81
Q

Explain the conversion of acyl chloride into esters

A

Acid chloride + alcohol —(anhydrous conditions)–> ester + HCl

  • Esters can be readily obtained from the reaction of acide chlorides with alcohols under anhydrous conditions
  • Phenolic (aromatic) esters are produced in the same way, although the aromatic acid chlorides are less reactive than aliphatic acid chlorides, requiring base to be added as a catalyst
82
Q

Explain the condensation of carboxylic acid and alcohol to form ester

A

Carboxylic acid + alcohol -(anhydrous condition)-> ester + H2O

  • Mixtures of carboxylic acids and alcohols will condense into esters under anhydrous conditions, liberating water.
  • use of sulfuric acid as a catalyst and dehydration reagent will drive the reaction forward
83
Q

Explain the hydrolysis of ester reaction

A

Ester -> carboxylic acid + alcohol

  • Esters, like the other derivatives of carboxylic acids, can be hydrolyzed, yeilding carboxylic acids and alcohols.
  • Hydrolysis can take place under either acidic or basic conditions.
    • Acidic conditions, the first step is protonation of the carbonyl oxygen, followed by water attacking the carbonyl carbon
    • Basic conditions, the nucleophile (OH-) directly attack the carbonyl carbon.
84
Q

Explain the conversion for ester into an amide

A

Ester + ammonia -> amide + alcohol

  • Nitrogen bases, such as ammonia, act as a nucleophile and attack the electrophilic cerbonyl carbon atom, displacing the ester functional group to yeild an amide and an alcohol side product
85
Q

Explain the process of transesterfication

A

Ester + alcohol -> New ester + new alcohol

  • Alcohols can act as nucleophiles and displace the alkoxy groups on esters.
  • This process, which transforms one ster into another, is called transesterification
86
Q

Explain the process of grignard addition

A
  • Grignard reagents add to the carbonyl groups of esters to form ketones; however, these ketones are more reactive than the initial esters are are readily attacked by more Grignard reagent.
  • Two equivalents of Grignard reagent can thus be used to produce tertiary alcohols with good yeild.
  • The intermediate ketone can be isolated only if the alkyl groups are sufficiently bulky to prevent further attack.
  • This reaction proceeds via nucleophilic substitution followed by nucleophilic addition
87
Q

Explain the process of condensation reactions of esters

A
  • Important reaction of esters is the Claisen condensation.
    • In the simplest case, two moles of ethyl acetate react under basic conditions to produce a beta-keto ester, ethyl 3-oxobutanoate, which is also known by its common name, acetoacetic ester.
    • Also known as acetoacetic ester condensation
  • ​The reaction proceeds by addition of an enolate anion to the carbonyl group of an ester, followed by displacement of ethoxide ion.
88
Q

Explain the reduction of ester reaction

A
  • Esters may be reduced to primary alcohols with LAH, but not with NaBH4.
  • This allows for selective reduction in molecules with multiple functional groups
  • Note that different alcohols are produced from the ester alkoxy functional group and the carbonyl-containing carbon chain
89
Q

Explain the conversion of acyl halides to amides, synthesis of amides

A
  • Acyl halides can be readily converted into amides by nucleophilic substitution with amines
  • An amine such as ammonia attacks the carbonyl group, displacing chloride
  • The side product is ammonium Chloride, formed from excess ammonia and HCL.
  • Primary and secondary amines cnan also be used as the nucleophile to create substituted amides; tertiary amines are not able to lose a hydrogen and thus cannot participate in this reaction
90
Q

Explain the conversion of anhydrides into amides

A

Ammonia + anhydride -> amide + carboxylic acid (goes to ammonium carboxylate)

  • Anhydrides are cleaved by ammonia, producing an amide and a carboxylic acid
  • The carboxylic acid then further reacts with ammonia to form ammonium carboxylate
91
Q

Explain the conversion of ester into amides

A

ester + amimonia -> amide + alcohol

  • Nitrogen bases such as ammonia act as nucleophiles and will attack the electrophilic carbonyl carbon atom, displacing the ester functional group to yeild an amide and an alcohol side-product
92
Q

Explain the hydrolysis reaction of amides

A

water + amide –(acidic condition)–> carboxylic acid + ammonia

  • Amides can be hydrolyzed under acidic conditions, via nucleophilic substitution, to produce carboxylic acids.
  • Under basic conditions amides react to form carboxylates
93
Q

Explain the Hofmann rearrangement reaction for an amide

A
  • The Hofmann rearrangement converts amides to primary amines with the loss of the carbonyl carbon as a molecule of CO2
  • The mechanism involves the formation of a nitrene, the nitrogen analog of a carbene
  • The nitrene is attached to the carbonyl group and rearranges to form an isocyanate, which under aqueous reaction conditions is hydrolyzed to the amine
94
Q

Explain the reduction reaction of the amide

A

Amide –(LAH)–> amine

  • Amides can be reduced with LAH to the corresponding amine. Notice that this differes from the product of the Hofmann rearrangement in that no carbon atom is lost
  • Note that, unlike with a carboxylic acid reduction with LAH, the oxygen atom is completely removed
95
Q

Review the summary table for the carboxylic acid derivatives, name and describe each

A

Picture #1

96
Q

Review the summary table for the carboxylic acid derivatives, name and describe each

A

Table #2

97
Q

Explain the summary table for amines

A

Formula, IUPAC, COmmon Name

Class of compound; characteristics

98
Q

Name the commine amines

A
99
Q

Explain the direct alkylation of amines

A
  • Alkyl halides react with ammonia to produce alkylammonium halide salts.
  • Ammonia functions as a nucleophile and displaces the halide atom
  • When the salt is treated with base, the alkylamine product is formed
100
Q

Explain Gabriel synthesis of amines

A
  • The preferred method for synthesizing amines is the Gabriel synthesis
  • The pathway converts a primary alkyl halide to a primary amine without uncontrolled additional reactions seen in the direct alkylation of amines
  • The first step is the creation of phthalimide, a nitrogen source based on ammonia, but with more controlled reactivity
101
Q

Explain amine reduction

A
  • Amines can be obtained from other nitrogen-containing functionalities through reduction reactions using typical reducing agents
  • Four different types:
    • From nitro compounds
    • From nitriles
    • Form imines
    • From amides
102
Q

Explain amide reduction from nitro compounds

A
  • Nitro compounds are easily reduced to primary amines
  • The most common reducing agent is iron or zinc and dilute hydrochloric acid, although many other reagents can be used.
  • This reaction is especially useful for aromatic compounds, because aromatic rigs are readily nitrated and thus provide an efficient route for amine synthesis
103
Q

Explain amine reduction from nitriles

A
  • Nitriles can be reduced with hydrogen and a catalyst, or with lithium aluminum hydride (LAH) to produce primary amines
104
Q

Explain the reduction of amines from imines reaction

A
  • Amines can be synteized by reductive amination: a process in which an aldehyde or ketone is reacted with ammonia, a primary amine, or a secondary amine to form a primary, secondary, or tertiary amine, respecitvely.
  • When the amine reacts with the aldehyde or the ketone, an imine intermediate is produced.
  • similar to a crbonyl, the imine can then undergo hydride reduction. when the imine is reduced with hydrogen in the presence of a catalyst, an amine is produced
105
Q

Explain the reduction from an amide

A

Amides can be reduced with LAH to form amines

106
Q

Explain exhaustive methylation of amine reaction

A
  • Exhaustive methylation is known as Hofmann elimination
  • In this process, an amine is converted to a quaternary ammonium iodide salt by reacting with excess methyl iodide
  • Treatment with silver oxide and water converts this to the ammonium hydroxide, which, when heated, undergoes elimination to form an alkene and an amine.
  • The predominant alkene formed is the least substituted, in contrast with normal elimination reactions, where the predominant alkene product is the most substituted
107
Q

What favors SN1 over SN2?

A

Weak nucleophile

108
Q

What is a secondary amine?

A

see attached

109
Q
A