Organic Chemistry 4.1 - ExpDetStruc - Empirical Fomula and Mass Spectrometry Flashcards
Elemental microanalysis is used to calculate the ___ formula of a compound, by determining the masses of which atoms in an organic compound?
empirical.
CHONS
The masses of Carbon, Hydrogen, Oxygen, Nitrogen and Sulfur present in an ___ compound can be determined through ___ ___.
organic, elemental microanalysis
What does an empirical formula show?
the simplest ratio of the elements in a molecule
Elemental microanalysis can be determined from which two things?
- masses of products of combustion.
- percentage by mass of products
Combustion product masses:
‘1.75 mg of an organic compound is combusted completely, producing 3.51 mg of CO2 and 1.43 mg of H2O.’
Calculate the empirical formula of the compound.
Step 1: find the mass of elements, in the products, that are guaranteed to be in the mystery compound (start with carbon and hydrogen). EG for carbon, multiply the mass of carbon dioxide (3.51mg) by 12/44 (carbon’s mass in carbon dioxide).
Step 2: Once you’ve done this for carbon and hydrogen, add the masses together. If it equals the mass of the mystery compound combusted, go to step 3. If not, subtract it from the mass of mystery compound, and take this as the mass of a third element - if CO2 and H2O were produced, its obv oxygen. - but it could be any of ‘CHONS’ so be ready for that
Step 3: Calculate moles of each element (n=m/GFM)
Step 4: Calculate mole ratio by dividing all by lowest mole value - if you don’t get (very close to) whole numbers, you may have made a mistake - or maybe try X2 or X3 all values
Combustion product masses:
‘1.75 mg of an organic compound is combusted completely, producing 3.51 mg of CO2 and 1.43 mg of H2O.’
Outline the steps you should take to calculate the the empirical formula of the compound.
- find mass of elements
- calculate moles of elements (n=m/GFM)
- calculate mole ratio (divide all by lowest mole value)
Combustion product masses:
‘1.75 mg of an organic compound is combusted completely, producing 3.51 mg of CO2 and 1.43 mg of H2O.’
Calculate the molecular formula of the compound, given that is has a GFM of 88.
Add up the GFMs of the elements in the empirical formula, and divide the molecular formula GFM by that number. that tells you how many of the empirical formula fits into the molecular
Percentage by Product Mass:
‘Calculate the empirical formula for a compound with 75% carbon and 25% hydrogen by mass.’
How do you work it out?
imagine you have 100g of the substance (you’re working with a ratio so it doesn’t matter at all).
divide each percentage by its GFM - so carbon would be 75/12, and that tells you moles (n=m/GFM).
divide each mole value by the lowest mole value, to find the simplest ratio
Mass spectrometry can be used to accurately determine the ___ and ___ ___ of a compound.
GFM, structural fomula
In mass spectrometry, a small sample of an ___ compound is ___ by ___ energy ___.
organic, bombarded, high, electrons
What happens in mass spectrometry?
a small sample of an organic compound is bombarded with high energy electrons
What does this this high energy electron bombardment do?
it removes electrons from the compound, creating positively charged molecular ions (called parent ions)
What do these parent ions then do?
break apart into smaller, positively charged ‘fragments’
This technique allows a mass spectrum to be obtained, showing a plot of the ___ ___ of the ions detected (on the y axis) , against the ___-___-___ ratio, on the x axis.
relative abundance, mass-to-charge ratio (m/z)
Describe the 4 steps to achieving a mass spectrum.
- organic compound bombarded with high energy electrons.
- electrons removed, creating a parent ion
- parent ion breaks apart, producing positive fragments
- graph plotted, with relative abundance on y axis and mass to charge ratio (m/z) on x axis