Organic Chemistry Flashcards
- Which of the following statements about carbon is NOT correct?
A. Carbon forms strong covalent bonds to itself, allowing chains and rings to be made.
B. Carbon expands its valence shell to accommodate more than eight electrons and thus forms double and triple bonds.
C. Carbon and hydrogen have similar electronegativity and form strong bonds to each other, thus avoiding the high reactivity shown by metal hydrides.
D. Carbon forms strong covalent bonds to elements like nitrogen and oxygen because it does not have lone pairs of valence electrons to destabilize the bonds.
B. Carbon expands its valence shell to accommodate more than eight electrons and thus forms double and triple bonds.
Which statement about bonding is TRUE?
A. A π bond is as twice as strong as a σ bond
B. A double bond consists of two π bonds
C. A σ bond has cylindrical symmetry about the bonding axis.
D. A π bond results from the sideways overlap of hybridized orbitals.
C. A σ bond has cylindrical symmetry about the bonding axis.
How many σ and π bonds are in acetylene?
A. 2σ, 2π
B. 3σ , 2π
C. 2σ, 3π
D. 3σ, 3π
B. 3σ , 2π
What is the bond angle and molecular geometry around C in CH2=CH2?
A. 120°, tetrahedral
B. 109.5°, tetrahedral
C. 120°, planar
D. 109.5°, planar
C. 120°, planar
What is the hybridization of O in CH3OH?
A. sp3
B. sp2
C. sp
D. sp3d
A. sp3
Oxygen in methanol has two lone pairs and forms two sigma bonds (one with hydrogen and one with carbon), making it have a tetrahedral electron geometry, which corresponds to sp³ hybridization.
Which of the following orbitals provide the most efficient overlap?
A. s-s
B. sp3 - sp3
C. sp-sp
D. p-p
C. sp-sp
How many constitutional isomers are possible for the molecular formula C5H12?
A. 1
B. 2
C. 3
D. 4
C. 3
How many distinct branched alkanes are there with the formula C6H14?
A. 1
B. 2
C. 3
D. 4
D. 4
Which of the following is TRUE for an optically active compound?
A. The molecular configuration is chiral.
B. The molecular configuration is achiral.
C. The compound is a racemic mixture of enantiomers.
D. The molecular configuration must have two or more stereogenic centers.
A. The molecular configuration is chiral.
Compounds which have different arrangements of atoms in space while having the same atoms bonded to each other are
A. constitutional isomers
B. functional group isomers
C. coordination isomers
D. Stereoisomers
D. Stereoisomers
Which of the following statements describes enantiomers?
A. They are achiral stereoisomers.
B. They are stereoisomers having a mirror plane of symmetry.
C. They are stereoisomers having non-identical mirror image configurations.
D. They are stereoisomers that do not have non-identical mirror image configurations.
C. They are stereoisomers having non-identical mirror image configurations.
Which substance can exist in enantiomeric forms?
A. 3-methylpentane
B. 2-methylpentane
C. 3-methyl-1-butanol
D. 2-methyl-1-butanol
D. 2-methyl-1-butanol
A racemic mixture consists of equal quantities of
A. cis-trans isomers
B. diastereomers
C. enantiomers
D. structural isomers
C. enantiomers
Which of the following is NOT an addition reaction?
A. Hydration
B. Dehydration
C. Halogenation
D. Hydrohalogenation
B. Dehydration
In this type of reaction, one sigma bond breaks and another forms at the same carbon atom.
A. Addition
B. Elimination
C. Substitution
D. Rearrangement
C. Substitution
In a substitution reaction, one sigma bond breaks and another sigma bond forms at the same carbon atom. This involves replacing one atom or group in the molecule with another, typically resulting in the same carbon atom being bonded to different groups.
During symmetrical bond breaking, ____ are formed.
A. Radicals
B. Electrophiles
C. Nucleophiles
D. None of the above
A. Radicals
All of the following are electrophiles EXCEPT
A. Br
B. BF3
C. AICI3
D. NH3
D. NH3
Br (Bromine): This can act as an electrophile, especially in reactions where it forms a positive ion (Br⁺).
BF₃ (Boron trifluoride): This is a strong electrophile due to the electron deficiency of boron, which has only six electrons in its valence shell.
AlCl₃ (Aluminum chloride): This is also a strong electrophile, particularly in Lewis acid-base reactions, as it can accept electron pairs.
NH₃ (Ammonia): Ammonia is a nucleophile because it has a lone pair of electrons on the nitrogen atom, allowing it to donate electrons rather than accept them.
Which of the following statements is FALSE?
A. It is not necessary for a nucleophile to have an unshared electron pair.
B. A species can react as an electrophile if it contains an atom (other than hydrogen) with an incomplete valence octet.
C. A species can react as an electrophile, even if it has one or more unshared electron pairs.
D. Any species bearing a lone pair can normally react as a nucleophile.
A. It is not necessary for a nucleophile to have an unshared electron pair.
Liquified petroleum gas is mainly composed of
A. Methane and Ethane
B. Ethane and Propane
C. Propane and Butane
D. Butane and Hexane
C. Propane and Butane
The hydrocarbon having the lowest boiling point is
A. CH4
B. C2H4
C. C4H10
D. C6H6
A. CH4
Compared to ionic compounds of similar molar mass, hydrocarbons typically have
I. Higher water solubility II. Higher melting points
A. I only
B. II only
C. both I and II
D. neither I nor II
D. neither I nor II
Which class of compounds consist exclusively of saturated hydrocarbons?
A. Alkenes
B. Aromatics
C. Alkynes
D. Alkanes
D. Alkanes
Alkanes undergo halogenation via
A. free radical substitution
B. electrophilic substitution
C. electrophilic addition
D. nucleophilic addition
A. free radical substitution
Alkenes and alkynes, because they contain π bonds, undergo this type of reaction.
A. Electrophilic addition
B. Nucleophilic addition
C. Electrophilic substitution
D. Nucleophilic substitution
A. Electrophilic addition
Alkenes and alkynes, due to their π bonds, undergo electrophilic addition reactions. The π electrons in these compounds are electron-rich and can be attacked by electrophiles, leading to the addition of atoms or groups across the double or triple bond. This type of reaction breaks the π bond and forms new σ bonds.