Organic chem - alcohols Flashcards
Explain why pentan-2-ol has a higher boiling point than pent-1-ene
-pentan-2-ol has hydrogen bonding whereas pent-1-ene only has van der waals
-Hydrogen bonding is stronger than Van der waals
-this means that it requires more energy to overcome
explain why propanone has a lower boiling point than propan-2-ol
-propanone has permanent dipole and van der waal intermoleculer forces of attraction whereas propan-2-ol has all 3 including hydrogen bonding so requires a lot of energy….
state the two reagents required to oxidise ethanol
sulfuric acid and acidified potassium dichromate (VI)
state the formula of the reacting anion and cation
Cr2O72-
H+
propan-1-ol can be oxidised. Which compound cannot be produced by the oxidation of this alcohol
CH3COCCH3
which compound produces (CH3)2CHCOCH3 when oxidised
3-methylbutan-2-ol
Ethanedioic acid is formed by the oxidation of ethane-1,2-diol (HOCH2CH2OH) .
State a suitable reagent and condition
reagent = acidified potassium dichromate (IV)
condition = reflux
which is the correct equation for the oxidation of 1-pehnylethanol
C6H5CH(OH)CH3 + [O] –> C6H5COCH3 + H2O
Suggest what would happen if the thermometer was too high
-boiling point recorded will be inaccurate - if the temp is high it does not read the temp of gaseous vapour
explain why the water should enter the condenser at the bottom and not the top
-ensures condensor is fully filled w water so organic product is fully condensed
explain 3 problems in the apparatus above
-no anti-bumping granules to create smaller bubbles
-open system w no thermometer to prevent gases escaping + allow connection of alcohol
-movement of water should be reversed to ensure complete condensation
alcohols
-alcohols are a homologous series of organic compounds with the general formula CnH2n+1OH and names ending in –ol
-The functional group of alcohols is the hydroxyl group (OH)
intermolecular forces present in alcohols
Intermolecular forces present in alcohols
-permanent dipole-permanent dipole (C-O)
-van der waals (present in all molecules)
-hydrogen bonding (O-H)
boiling point of alcohols
-alcohols have higher overall boiling point due to their hydrogen bonding which is the strongest intermolecular force so therefore requires more energy to overcome
aldehydes, ketones and carboxylic acids
Aldehyde = CHO = name ends in al
Ketone = COC = name ends in one
Carboxylic acid = COOH = name ends in oic acid
solubility
-ketones are soluble in water because they can form hydrogen bonds with molecules of water
-However, ketones are unable to form hydrogen bonds between eachother because they don’t have a delta positive hydrogen
combustion of alcohols
-alcohols burn in a plentiful supply of air with a clean (No soot) pale blue flame
-Methanol and Ethanol are both common fuels
e.g complete combustion of propanol –> C3H8O + 9/2O2 –> 3CO2 + 4H2O
primary, tertiary, secondary
-Alcohols can be described as primary, secondary or tertiary
Primary = only 1 R (alkyl group) attached
Secondary = 2 R groups attached
Tertiary = three R groups attached
e.g Secondary if 2 alkyl groups attached to the central carbon atom
potassium dichromate
Alcohols can be classified as primary, secondary or tertiary and can react with potassium dichromate (VI) (K2Cr2O7) in different ways dependent on the type of alcohol
-All three types of alcohol can be reacted with oxidising agents to produce different products
products of primary, secondary and tertiary alcohols reacting with acidified potassium dichromate (oxidised)
Primary alcohols –> aldehyde –> carboxylic acid
Secondary alcohols –> ketone
Tertiary alcohols –> cannot be oxidised so no reaction
oxidising equations
RCH2OH + [O] –> RCHO + H2O (alcohol –> aldehyde + water)
RCHO + [O] –> RCOOH (aldehyde –> carboxylic acid)
= RCH2OH + 2[O] –> RCOOH + H2O
distinguishing between types of alcohol
-Acidified potassium dichromate is orange in its usual conditions but will undergo a colour change when it is reduced
-orange –> green (Cr2O7^2- –> Cr3+)
-Cr2O72- + 14H+ + 6e- –> 2Cr3+ + 7H2O
-during the oxidation of a primary and secondary alcohol K2Cr2O7 will change from orange to green
-there is no colour change for a tertiary alcohol as it cannot be oxidised
oxidation of a primary alcohol
-distillation is used when making aldehydes to allow the aldehyde to be collected preventing further oxidation
-when being distilled to an aldehyde excess alcohol is added to prevent further oxidation
disitllation apparatus
-When distilling an alcohol the equipment must be set up carefully
Thermometer cannot be too high (must be at intersection by condenser)
Bung must be sealed around thermometer to prevent gas escaping
Water must go into the bottom and out the top of the cooling jacket
Product cannot be sealed as this could cause an explosion
anti bumping granules
-antibumping granules or small pieces of porcelain are added to prevent violent uncontrolled boiling
-Adding sulfuric acid slowly to the reacting mixture will also help prevent uncontrolled boiling bc reaction is exothermic
identify reagent P (distillation exam question)
H2SO4 (sulfuric acid)
state the chemical change that causes the solution in the flask to appear green at the end of the reaction
dichromate is reduced from Cr2O7^2- to Cr3+
give one reason why using a water bath is better than direct heating with a bunsen burner
alcohol is flammable or allows temperature to be controlled
state the purpose of the condenser
condenses volatile reactants so they are not lost / has complete oxidation
what is the purpose of adding anhydrous solid calcium chloride
-acts as a drying agent to remove excess water
Complete when turns clear from cloudy