organic 6 - workshop type lecture

Question 1

NaCNBH4 role

Answer 1

reducing agent

u write it as BH4 CN attached aswell

the B-H bond attacks C!!!!

Question 2

what should we look for when we want to break a bond

Answer 2

we look for an OH near the bond we need to break

we use a base to remove the H and form a O- on the OH we just deprotonated

then wr form a ketone and break the bond we wanted to,, this will form a double bond and also an O- if there was a carbonyl near the bond u just made by breaking the other one.

u then use the enolate u just formed to attack a H,, this ill take away the double bond and give u the reaction u want.

Question 3

how else can we form a bond apart from enolates

Answer 3

protonate a carbonyl,,, then use another OH lone pair to attack the protonated carbonyl carbon which forms a bonddd.