Nucleophilic Substitution Flashcards

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1
Q

Electron poor and tend to have a slight positive or a positive charge (or have open orbitals). Tend to accept electrons to form covalent bonds

A

Electrophile

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2
Q

True or False: Pi bonds can be nucleophiles

A

True

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3
Q

How do the definitions of a lewis acid or base come into play with nucs/electrs?

A

Lewis acids accept electrons (like an electrophile) Lewis bases donate electrons (like nucleophiles)

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4
Q

Which of the following would be the strongest nucelophile: Hydroxide ion Water Hydronium ion

A

The hydroxide ion because it has a negative charge so it has electrons to donate

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5
Q

An unknown ion has the electron configuration 1s2 and you have observed that it has 3 protons. Do you predict this element to be electrophilic or nucleophilic?

A

It should be electrophilic because if it has 3 protons that means it is Lithium. Lithium should have a 2S2 configuration. If it has a 1S2 that means it is positively charges and will act as an electrophile.

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6
Q

True or False: OH is a good leaving group

A

False, OH2 is a good leaving group so we need to protonate OH in order to turn it into a good LG

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7
Q

Are halogens good or bad LG’s?

A

Good LG’s

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8
Q

What is the rate limiting step of SN1?

A

Formation of a carbocation. This is why the rate is only dependent on the first reactant turning into a carbocat.

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9
Q

What is the most likely substrate you will encounter in SN2 reactions?

A

Alkyl halide

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10
Q

Is this SN1 or SN2?

A

SN2

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11
Q

Which would be the best LG?

Cl-

OH-

CH3

A

Cl-

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12
Q

True or false: An SN1 reaction proceeds in at least two steps, while an SN2 reaction proceeds in just one step.

A

This statement is true. An SN1 reaction proceeds through the formation of a carbocation first, then a nucleophilic attack. It is for this reason categorized as stepwise reaction mechanism. SN2 reactions, by contrast, happen in a single step that is driven by a nucleophile attacking the electrophilic site of the substrate, and these reactions are therefore categorized as concerted reactions.

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13
Q

Sodium bromide and tert-butanol are reacted in an SN1 reaction to form an alkyl halide. This reaction can be sped up by which of the following steps?

A

The carbocation intermediate must be formed, and this is the rate-limiting step of SN1 reactions.So increasing the concentration of tert-butanol would do it.

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14
Q

An SN2 reaction must be of at least which reaction order kinetics?

A

Second order reactions depend on the concentration of two species to the first power. This is the minimal reaction order for any SN2 reaction, as the reaction rate must depend on at least the concentration of the nucleophile and the concentration of the substrate.

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15
Q

Which of the following compounds would most readily serve as the substrate for an SN1 reaction?

  • Primary alcohol in a basic envrionemnt
  • Primary alcohol in an acidic environment
  • tertiary alcohol in an acidic environement
  • tertiary alcohol in a basic environment
A

Tertiary alcohol in an acidic environement. Of the options presented, a tertiary alcohol would most readily form the carbocation intermediate that is required for an SN1 reaction to take place.

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16
Q

What is the major predictive factor of whether something will be SN1 or SN2?

A

Substitution predicts the stability of the carbocation intermediate for SN1 reactions. Also, polar protic solvents (highly electronegative and H-bond forming) favor SN1

17
Q

True or False: tertiary carbocations are less stable than secondary

A

False, it is more.

18
Q

True or False: Primary alkyl halides do not undergo SN1 to a meaningful extent

A

True, they dont form stable carbocation intermediates

19
Q

Why do polar protic solvents promote SN1?

A
  1. The slight negative charge (like the oxygen on water) will stabilize the carbocation
  2. the slight positive charge (like the hydrogens on water) will interact with alkyls that are separated to keep them from going back to its orginal molecule
20
Q

True or False: SN2 reactions are more likely to occur at tertiary carbons fo rthe stability of the carbocation

A

False, they almost never occur at tertiary carbons due to steric hindrance

21
Q

What kind of solvent promotes SN2?

A

Polar aprotic like acetone and DMSO. (Polar protic solvent coudl weaken nucleophile which we dont want for SN2)

22
Q

True or false: Ethanol, ethanoic acid, and propanol are all solvents which are conducive to SN1 reactions.

A

This statement is true. All the named structures are polar protic solvents. Polar protic solvents are most conducive to SN1 reactions (note that strong acids in the absence of good nucleophiles may lead to elimination reactions, although these are NOT directly tested on the MCAT).

23
Q

What is DMSO?

A

POLAR APROTIC

dimethylsulfoxide (DMSO). Note that the two terminal methyls are not likely to dissociate protons readily, making this a polar aprotic solvent conducive to SN2 reactions.

24
Q

Would cyanided make a good nucleophile?

A

Cyanide anion is a very strong nucleophile, and strong nucleophiles drive SN2 reactions.

25
Q

What product type would this form:

A

This rxn would form an imine

An amine as a nucleophile, an acidic environment, and a ketone for a substrate are all conducive to the formation of imines.

26
Q

When will you most likely see the formation of a tetrahedral intermediate?

A

A tetrahedral intermediate is formed whenever a nucleophilic attack on a double bonded carbon occurs (commonly a carbonyl carbon). Formation of a new bond pushes the electrons from the pi bond onto the leaving group, and a carbon with four sigma bonds remains. Intermediates, while unstable, exist longer than transition states and can sometimes be isolated.

Other situations in which a trigonal planar molecular geometry undergoes nucleophilic attack are possible, but attacks on a carbonyl carbon are by far the most common scenario on the MCAT for the formation of tetrahedral intermediates.

27
Q

What is the most likely substitution mechanism to procede in this reaction?

A

The given reagents are most likely to undergo an SN1 reaction, as propanol may act as both the nucleophile and as a polar protic solvent. SN1 reactions proceed through carbocation intermediates, which conform to a trigonal planar geometry. Addition of the nucleophile subsequently may lead to the formation of both enantiomers.

Product would have the new functional group replacing the iodine, not the fluorine

28
Q

The reaction between ethyl bromide and sodium cyanide in acetone is most likely to be….

A

A strong nucleophile, a polar aprotic solvent and a primary alkyl halide with a good leaving group for a substrate all suggest an SN2 mechanism.

29
Q

Phosphorylation of certain residues on amino acids can induce rapid conformational change in proteins. The process involves the formation of a phosphoester bond, in a process somewhat similar to Fischer esterification in that the alcohol functional group acts as a nucleophile. Knowing this, which of the alpha amino acids do you expect to commonly find phosphorylated?

A

Serine, threonine, tyrosine (your -OH containing groups)

30
Q

True or False: The stability of carbanions is opposite that of carbocations.

A

True