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NMR background Flashcards

1
Q

NMR spectroscopy records…

A

…the absorption of energy between quantised energy levels

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2
Q

How does nuclear spin arise?

A

From unpaired protons or neutrons in the nucleus

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3
Q

I

A

Spin quantum number

i.e. nuclear spin

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4
Q

What is the spin quantum number (I) for protons and neutrons?

A

I = 1/2

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5
Q

Odd number of protons and odd number of neutrons

A

Spin (I) = integer 1, 2, 3 etc

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6
Q

Even number of protons and odd number of neutrons

A

Spin (I) = 1/2 integer e.g. 13C

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7
Q

Odd number of protons and even number of neutrons

A

Spin (I) = 1/2 integer e.g. 19F

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8
Q

Why do paramagnetic compounds cause problems with NMRs?

A

Because the magnetic moment of an unpaired electron is nearly 1000x larger than that of nuclei
Additional magnetic field leads to large shifts
Effective relaxation mechanism leads to broad NMR signals

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9
Q

I = 0

A

NMR spectroscopy not possible

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10
Q

I = 1/2

A

These nuclei usually give good, easily interpretable results

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11
Q

I > 1/2

A

These nuclei often give broad signals - so generally problematic

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12
Q

When does a nucleus have both a magnetic and a quadrupole moment?

A

When I > 1/2

This is due to the non-spherical nature of the nucleus

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13
Q

Effect of quadrupole nuclei on NMR spectra

A

Broad lines due to rapid relaxation of nuclei

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14
Q

The energy levels involved in NMR spectroscopy arise from the interactions of nuclear spins with:

A
  1. The spectrometer magnetic field, B0
  2. The magnetic fields created by the electrons in the system (this is what leads to chemical shifts)
  3. The magnetic fields created by other NMR-active nuclei in the system
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15
Q

Gyromagnetic ratio

A

Gamma

Governs the strength of the NMR signal

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16
Q

Negative gyromagnetic ratio

A

Usually results in a negative NOE enhancement

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17
Q

Quadrupole moment

A

Q

The smaller the quadrupole moment, the better

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18
Q

What does a spinning nucleus possess?

A

Nuclear spin angular momentum (P)

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19
Q

Nuclear spin angular momentum

A

P
Can be quantised such that P = hbar x root[I(I+1)]
Where hbar = h/2pi and I = spin quantum number

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20
Q

Spinning nucleus

A

A nucleus is a charged body
Therefore a spinning nucleus generates an associated magnetic moment (nuclear magnetic moment, mu) which is a vector quantity

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21
Q

Vector quantity

A

A geometric object with magnitude and direction

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22
Q

Nuclear magnetic moment

A

Mu = gammaP

Where gamma = gyromagnetic ratio (a constant for each nuclide)
P = nuclear spin angular momentum

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23
Q

What does the sensitivity of detection of a nuclide depend on?

A

Gyromagnetic ratio

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24
Q

Large gyromagnetic ratio

A

Nuclei are easy to observe (sensitive)

e.g. 19F

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25
Small gyromagnetic ratio
Nuclei are difficult to observe (insensitive) | e.g. 15N
26
Combining nuclear spin angular momentum and nuclear magnetic moment equations gives...
mu = gamma(hbar x root[I(I+1)])
27
Do different isotopes of the same element have the same values of gamma?
No | Different isotopes of the same element have different values of gamma
28
Why do nuclides with I=0 have no NMR signal?
I=0 means no nuclear spin angular momentum (P) and therefore no nuclear magnetic moment (mu) Examples of these nuclei include 12C, 16O, 32S
29
Magnetic quantum number
ml = the component of the nuclear spin (I) along the z-axis Can take values I, I-1, ..., -I (i.e. there are 2I+1 possible values of ml associated with the nuclear spin I) e.g. I = 3/2 has 4 possible ml values
30
ml states in the absence of a magnetic field...
...are all energetically degenerate Because there is nothing to interact with the nuclear magnetic moment and the energy of the system is not affected by the spatial orientation of the moment
31
Placing a nucleus in a magnetic field
If a nucleus with angular momentum P and magnetic moment mu is placed in a magnetic field of strength B0 orientated along the z-axis, the nuclear angular momentum orientates such that: Pz = ml(hbar) where ml = magnetic quantum number
32
Different orientations of the nuclear magnetic moment will have...
...different magnetic moments and therefore different energies depending on their orientations w.r.t. to the direction of the applied field B0
33
Why are only certain orientations of the magnetic moment (mu) allowed?
Due to the quantisation of I Each orientation corresponds to a different ml value There are 2I+1 allowed ml values (and an equal number of allowed Pz values) Therefore there is the same number of discrete energy levels
34
Zeeman splitting
The splitting of atomic energy levels in the presence of a magnetic field
35
Energy of a magnetic dipole in a magnetic field of strength/flux density B0
E = -muzB0 Where muz is the component of mu along the z-axis (the direction of the field) E = -gamma(ml)(hbar)(B0)
36
The energy of the nucleus is raised or lowered by an amount proportional to:
1. The gyromagnetic ratio (gamma) 2. The z-component of the nuclear spin angular momentum (Pz = ml(hbar)) 3. Magnetic field strength (B0)
37
DeltaE
Energy difference between ml levels/states | DeltaE = -y(hbar)(B0)
38
What is the selection rule for transitions between nuclear spin states in NMR spectroscopy?
Deltaml = +/-1 | i.e. allowed transitions occur between adjacent energy levels
39
How many possible transitions are there for a spin I nucleus?
2I Each transition has the exact same energy Therefore only one resonant frequency for the nucleus is expected, regardless of the value of I for the nuclide
40
How can the energy of a transition be expressed?
In terms of a frequency, v
41
Frequency of EM radiation that must be applied to the nucleus in order to detect a transition in NMR spectroscopy
v = yB/2pi DeltaE = E1 - E2 = hv = y(hbar)B
42
Larmor frequency
= vL = resonant frequency = the frequency of the precession (rotation) of the nucleus around the z-axis of the magnetic field = depends on the spectrometer's field strength
43
Angle of cone of precession
55degrees44'
44
How many cones of precession are there for I=1/2 nuclei?
2, representing ml=+1/2 and ml=-1/2
45
Why do all spins in the nucleus precess at the same frequency?
Because vL is independent of ml
46
How do chemical shift and coupling arise?
From interactions with the magnetic fields generated from the spin of other nuclides and electrons These interactions alter the nuclides resonant frequency (often so more than a single resonance is observed)
47
Why do the resonances for a sample recorded in different NMR spectrometers with different magnetic field strengths always exhibit the same chemical shifts?
Because chemical shift (ppm) = [DeltavL (Hz) / spectrometer freq. (Hz) x 10^6] OR chemical shift (ppm) = DeltavL (Hz) / spectrometer freq. (MHz)
48
Magnetic field (B0) of a typical NMR instrument
9.4 Tesla
49
Resonance frequency for a nuclear isotope X
vX = (yX/yH) x vH (using only the magnitude of y, not its sign) Use this equation for calculating resonant frequencies of other nuclei compared to 1H
50
How are transitions between different energy levels induced experimentally?
By irradiating the sample with a superimposed field B1 of the correct quantum energy i.e. we do not see signals from 1H nuclei in a 31P NMR spectrum - the spectrometer is tuned to the nuclide of choice
51
What happens to the nuclear spins when a sample is irradiated at the Larmor frequency?
They are both: Excited to the next highest energy level (absorption) Stimulated to relax back to the next lowest energy level (emission)
52
What does the intensity of the observed NMR signal depend on?
The difference between the numbers of absorption and emission processes occurring (i.e. the net movement)
53
What does the net movement between spin-states depend on?
Because the probabilities of absorption and emission are equal, net movement between spin-states solely depends on the population difference between the upper and lower states This population difference is given by Boltzmann statistics
54
Population difference between upper and lower states
Extremely small (approx. 1 in 30,000 population difference in favour of the lower state)
55
What does a population excess in the lower level mean?
Absorption is the dominant process This means the observed signal is proportional to Na-Nb, as well as to the total number of net spins in the sample (and thus the nuclide concentration in the sample)
56
What happens if the populations in the upper and lower state are exactly equal?
No signal is observed (= saturation) Because there is an equal number of absorptions and emissions This is used in decoupling experiments
57
Na
Lower state
58
Nb
Upper state
59
Why do nuclides with low gyromagnetic ratios give weaker signals than those with high gyromagnetic ratios?
Because the energy level separation is proportional to the gyromagnetic ratio of the nuclide
60
The sensitivity/receptivity of a nucleus, for a fixed value of B0, is proportional to:
y^3[I(I+1)]
61
If the receptivity of 1H is given as 1, the relative receptivity of nucleus X is:
(yX / yH)^3 ([Ix(Ix+1) / [Ih(Ih+1)]) (abundance of X / abundance of H)
62
In what ways can the sensitivity of an NMR experiment be increased?
Increasing B0 (i.e. using a stronger magnet) Lowering the sample temperature (See equations in green box) More concentrated samples are also advantageous
63
Pulsed NMR
Involves applying a sequence of radiofrequency pulses to the sample so that all spectral frequencies are irradiated at once (i.e. all spins excited at once) These pulses are either pi-pulses (180) or pi/2-pulses (90) The pulses lead to a FID signal, that is then converted to a 'real' spectrum by Fourier Transform (converting time domain to frequency domain)
64
FID
Free Induction Decay
65
Advantages of pulsed NMR (c.f. CW-NMR)
Very time-efficient | Allows 'rapid multiple passes', which allows a good signal to noise ratio to be established
66
Signal to noise ratio in NMR
The signal increases by a factor of N for N scans The noise increases by a factor of rootN for N scans Therefore the S/N ratio increases/improves by N/rootN (=rootN) for N scans Therefore, to double the S/N ratio you must do 4x as many scans
67
Why can the S/N ratio not be infinitely increased?
Because S/N is only increased by rootN For a really weak signal, the time required to obtain an acceptable S/N would be impractically long (so would need to increase conc of sample)

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