Nitriles, Amines and Amides Flashcards
What are amines
- Amines are organic compounds derived from ammonia, NH3, in which one or more hydrogen atoms in ammonia have been replaced by a carbon chain or ring
What is an aliphatic amine
- In an aliphatic amine the nitrogen atom is attached to at least one straight or branched carbon chain (alkyl group).
- Methylamine is the simplest aliphatic amine CH3NH2
What is an aromatic amine
- In an aromatic amine the nitrogen atom is attached to an aromatic ring
- Phenylamine is the simplest aromatic amine C6H5NH2
What is the difference between primary, secondary and tertiary amines and give examples
- Primary- 1 alkyl/aryl group attached to the nitrogen
e. g. CH3CH2CH2NH2, C6H5NH2 - Secondary- 2 alkyl/aryl groups attached to the nitrogen
e. g. (C2H5)2NH, C6H5NH(CH3) - Tertiary- 3 alkyl/aryl groups attached to the nitrogen
e. g. (CH3)3N, C6H5N(CH3)2
How do you name amines
- Primary amine with NH2 on the end of the chain- Add the suffix amine to the name of the alkyl chain e.g ethylamine
- Primary amine with NH2 on any other carbon except C-1 - Use prefix amino and a number in front to indicate its position on the carbon chain e.g 2-aminobutane
- Secondary/tertiary amines that contain the same alkyl group- prefix di or tri are used to indicate number of alkyl groups attached e.g (CH3)2NH is dimethylamine
- When two or more different groups are attached to a nitrogen atom- the compound is named as a N-substituted derivative of a larger group. e.g CH3NHCH2CH2CH3 is N-methylpropylamine
- Practice naming p6 of study pack
Name the following compounds:
- NH2CH2CH2CH2CH2NH2
- CH3CH2CH(NH2)CH2CH2CH3
- 1,4-diaminobutane
2. Hexyl-3-amine
How do amines behave in their chemical reactions and give an example with ethlyamine
- Behave as bases
- As the lone pair of electrons on the nitrogen atom can accept a proton
- When an amine accepts a proton, a dative covalent bond is formed between the lone pair of electrons on the nitrogen atom and the proton
- C2H5HN2 + H+ → [C2H5NH3]+
ethylamine + proton→ ethylammonium ion
What is formed when amines react with acids and give 2 examples:
- Propylamine + HCl
- Ethylamine + H2SO4
- They neutralise acids to make salts as they are bases
- CH3CH2CH2NH2 + HCl → CH3CH2CH2NH3+Cl-
propylamine + HCl → propylammonium chloride - 2CH3CH2NH2 + H2SO4 → (CH3CH2NH3+)2SO4 2-
ethylamine + H2SO4 → ethylammonium sulfate
Describe and explain the difference of boiling point of 1-aminobutane compared to pentane and butan-1-ol
- 1-aminobutane has hydrogen bonds between molecules which are stronger than London forces in pentane
- However, the hydrogen bonds are weaker than those in butan-1-ol
Describe the formation of primary amines and show an example with 1-chloropropane
- Ammonia has a lone pair of electrons o the nitrogen atom which allows ammonia to act as a nucleophile in a substitution reaction with a haloalkane. Forming an ammonium salt
CH3CH2CH2Cl + NH3 → CH3CH2CH2NH3+Cl-
1-chloropropane + NH3 → propylammonium chloride (salt) - Aqueous alkali is then added to generate the amine from the salt.
CH3CH2CH2NH3+Cl- + NaOH → CH3CH2CH2NH2 + NaCl + H2O
propylammonium chloride + NaOH → propylamine
What are the conditions needed for the formation of primary amines
- Ethanol is used as the solvent- this prevents any substitution of the haloalkane by water to produce alcohols. And haloalkanes aren’t soluble in water.
- Excess ammonia is used- this reduces further substitution of the amine group to form secondary and tertiary amines
Describe the formation of secondary and tertiary amines and five an example with propylamine and 1-chloropropane
- The reaction to make primary amines is unsuitable for making a pure primary amine.
- The product still contains a lone pair of electrons on the nitrogen atom that can react further with a haloalkane to form a secondary amine- the product is an ammonium salt.
CH3CH2CH2Cl + CH3CH2CH2NH2 → (CH3CH2CH2)2NH2+Cl-
1-chloropropane + propylamine → dipropylammonium chloride - The secondary amine is obtained from the salt by reacting with NaOH
(CH3CH2CH2)2NH2+Cl- + NaOH → (CH3CH2CH2)2NH + NaCl + H2O
dipropylammonium chloride → dipropylamine - Tertiary amines can also be formed by further reaction of the secondary amine e.g form tripropylamine
Describe the preparation of aromatic amines and give an example using phenylamine
- Phenylamine is made by the reduction of nitrobenzene
- Nitrobenzene is heated under reflux with tin and HCl to form the ammonium salt phenylammonium chloride
- This is then reacted with excess NaOH to produce the aromatic amine
- The tin and HCl act as reducing agent.
- Nitrobenzene + 6[H] → phenylamine + 2H2O
- Sn/conc Hcl and excess NaOH (aq) are written above and below the arrow
Which functional groups are present in all amino acids
- Carboxylic acid
2. Amine
Describe and draw the basic structure of an α-amino acid
- Amine group is attached to the α-carbon atom- the second carbon next to the carborxylic acid group
- They differ by side chain R
- General formula- RCH(NH2)COOH