Neurons and Glia 1 Flashcards
Give the ‘official’ definition of ‘reversal potential’. (1)
The potential difference across a membrane when there is no net movement of ions.
Give another name for reversal potential. (1)
Equilibrium potential
Which ions (out of K, Na, Cl, and Ca) are predominantly extracellular? (1)
Na
Cl
Ca
Which ions (out of K, Na, Cl, and Ca) are predominantly intracellular? (1)
K
Describe what is meant by the term ‘electrochemical gradient’. (1)
A combination of the concentration (diffusion) gradient of an ion and the electrical gradient acting across the membrane.
What is the function of the Nernst equation (what does it calculate)? (1)
The reversal potential of an ion.
Give the ‘pure’ form of the Nernst equation. (1)
Ex = RT/zF ln (xo)/(xi)
Give the simplified form of the Nernst equation for a mammal at 37 degrees. (1)
Ex = 61.5 log (xo)/(xi)
How do you convert from ln to log10? (1)
Multiply by 2.303
What does R stand for in the Nernst equation? (1)
Gas constant
What does z stand for in the Nernst equation? (1)
Ion valence
What does F stand for in the Nernst equation? (1)
Faraday constant
What does T stand for in the Nernst equation? (1)
Temperature (Kelvins)
According to the Nernst equation, what would Ex of an ion be if the intracellular and extracellular concentrations were equal? (1)
0mV
According to the Nernst equation (for a positively charged ion), if the extracellular concentration is higher than the intracellular concentration, will Ex be positive or negative? (1)
Positive
According to the Nernst equation (for a positively charged ion), if the extracellular concentration is lower than the intracellular concentration, will Ex be positive or negative? (1)
Negative
What is log10 (1)? (1)
0
Why are astrocytes important when looking at the Nernst equation? (2)
Astrocytes are permeable to K only
so Em will be equal to Ek.
When converting the Nernst equation for Ek to an equation for a straight line, we can disregard [K]i. Why? (2)
Because it takes very few ions to move to carry charge across the membrane.
Therefore, a change in voltage will only result in a negligible change in intracellular ion concentration.
How does increasing the extracellular potassium concentration affect the value of Ek and why? (4)
As [K]o increases, Ek increases.
Because the concentration gradient across the membrane is decreased,
and a smaller electrical gradient is required to oppose the concentration gradient,
and stop the net movement of ions across the membrane.
What would be the clinical consequence of a rise in extracellular potassium? (2)
Membrane becomes depolarised because Ek increases,
and the neurone then fires too easily.
Describe how an astrocyte is able to detect neuronal activity away from the synapse. (3)
During the AP there is efflux of potassium into the extracellular space.
This affects Vm of the astrocyte (makes it less negative)
The astrocyte becomes depolarised.
Give a brief description of how potassium activity in astrocytes can quantify neuronal activity. (3)
APs release potassium into extracellular space which changes Vm of astrocytes.
Using the change in Vm, we can use the Nernst equation
to work out the change in [K]o which occurs with an action potential.
Describe a method to work out [K]i of astrocytes using electrodes. (4)
Vm of astrocyte is equal to Ek.
When [K]i = [K]o, Ek and Vm are zero.
Keep bathing astrocytes in known concentrations of [K]o until Vm=0.
When Vm=0, [K]i will be the same as [K]o.
Why can’t the Nernst equation be used to calculate Em of neurones? (1)
Neurones are permeable to more than one ion.
Describe how the Nernst equation predicts the direction and speed with which a particular ion will move across a membrane. (2)
Ion moves across the membrane in the direction that will cause Em to move towards Ex.
The greater the difference between Em and Ex, the quicker/more ions will move.
True or false? (1)
An ion will always move down its concentration gradient, even if it means Em will move away from Ex.
False - an ion will always move so that Vm moves towards Ex, even if that means moving against its concentration gradient.
Calculate log10 (0.01). (1)
-2
Calculate log10 (0.1). (1)
-1
Calculate log10 (10). (1)
1
Calculate log10 (100). (1)
2
How does increasing [K]o affect the peak of the action potential? (1)
It doesn’t - the peak is due to sodium only
Why does the afterhyperpolarisation get smaller as [k]o increases? (2)
As [k]o increases there is less of a concentration gradient so Ek gets closer to zero.
Because Vm will approach Ek during repolarisation, it will not go as negative if Ek is not as negative.
Describe what is meant by local currents, in relation to the axon. (1)
Excitation in a region of axon will send small currents down the axon and out through the membrane.
Give three effects on the action potential of decreasing [Na]o. (3)
- The conduction velocity decreases
- Rate of upstroke decreases
- Action potential amplitude decreases
Describe the passive phase of the action potential rise. (3)
- Local currents depolarise small sections of membrane
- Up to the threshold value only
- Vm rises slowly
Describe the active phase of the action potential rise. (3)
- Threshold is reached and Na channels open
- The membrane has a rapid-onset, transient, increased conductance to Na
- Vm rises rapidly
How does a membrane’s permeability to different ions affect its Vm? (1)
At any instant, the membrane potential will approach the equilibrium potential of the ion to which it is most permeable at that instant.
Describe the magnitude and direction of the electrochemical gradient acting on Na at rest. (2)
Large gradient
driving Na into cell.
Describe the magnitude and direction of the electrochemical gradient acting on K at rest. (2)
Small gradient
driving K out of cell.
At rest, why isn’t Em halfway between ENa and Ek?
Where does it rest? (2)
Because the membrane is much more permeable to K than Na.
Em lies closer to Ek.
If the electrochemical gradient acting on Na is larger than the one acting on K at rest, why doesn’t more Na move into the cell? (1)
Na channels are not open
True or false? (1)
The voltage-gated opening of sodium channels during the rising phase of the action potential is an example of negative feedback.
False - it is an example of positive feedback
What accounts for the increased conductance to K during the repolarisation phase of the action potential? (1)
Delayed opening of voltage-gated K channels
True or false? (1)
When depolarisation occurs, sodium channel inactivation gates are triggered to close.
True - however activation gates open more rapidly to allow transient Na influx, and inactivation gate closing is delayed.
Describe the role of the Na channel inactivation gate in the neuronal refractory period. (3)
After depolarisation there is delayed closing of the inactivation gate.
The inactivation gate remains closed until the cell becomes repolarised.
Only then can another AP be stimulated to occur.
Describe the states of the activation and inactivation gates of the sodium channel during the rising phase of the action potential. (2)
Activation gates open
Inactivation gates open
Describe the states of the activation and inactivation gates of the sodium channel during the resting phase of the action potential. (2)
Activation gate closed
Inactivation gate open
Which equation would be used to work out Em of a cell which is permeable to more than one ion? (1)
Goldman Hodgkin Katz
What is the Goldman Hodgkin Katz equation? (1)
Em = RT/zF ln (PNa[Na]o + Pk[k]o)/(PNa[Na]i + Pk[k]i
What is the effect of increasing PNa on Vm?
Consider how this changes if [k]o were to be increased. (2)
Increasing PNa increases Vm.
As [K]o increases, this effect diminishes
because as [k]o increases it begins to dominate the GHK equation.
At low [k]o, which ion dominates the GHK equation? (1)
Sodium
How are PNa and Pk expressed in the GHK equation? (2)
Pk = 1
PNa expressed relative to Pk.
True or false? (1)
The numerator of the GHK equation can be treated as a constant.
False - the denominator (PNa[Na]i + Pk[k]i) can be treated as a constant.
Describe the effect (and the magnitude of the effect) of [k]o on the resting phase of the action potential. (2)
Low [k]o makes Vm slightly more negative.
Small effect because membrane is also slightly permeable to Na.
Describe the effect (and the magnitude of the effect) of [k]o on the peak of the action potential. (2)
No effect
The membrane is almost exclusively permeable to Na.
Describe the effect (and the magnitude of the effect) of [k]o on the afterhyperpolarisation phase of the action potential. (2)
Lower [k]o produces larger (more negative) hyperpolarisation.
Large effect because membrane is almost exclusively permeable to K.
At high concentrations of Na, what effect size will decreasing [Na]o have on ENa? (1)
Very little decrease