mutiphase Flashcards
Quanti gradi di libertà ha un sistema?
I need the balance for energy, mechanics and chemical for a system with m phases and r species. I also write the Gibbs eq. and get:
eq = M+(M-1)(r+2)
unk: M(r+2)
so since eq <= unk:
M<=r+2
cosa sono x, xv, eps e come sono legati?
x is the mass quality (gamma_g/gamma)
xv is the volume quality (Q_g/Q)
eps is the void fraction (omega_g/omega)
(1-x)/x = rho_l/rho_g * (i-xv)/xv = s * rho_l/rho_g * (1-eps)/eps
what are rho_b, rho_actual, rho_m
rho_b = gamma/Q
rho_actual = M/V = rho_geps + rho_l(1-eps)
rho_m = rho_gx^2/eps + rho_l(1-x)^2/(1-eps)
slip-ratio model
s = cost* (rho_g/rho_l)^a (mu_l/mu_g)^b ((1-x)/x)^c
drift-flux model
The slippage is locally calculated and then integrated:
u_g-u_l = j_g/eps - j_l/(1-eps) …
… J_g = C_0 * eps * J + J_drift
Patterns?
churn (L_c = D) :
inertia = buoyancy
u_c = sqrt((gdelta_rhoL_c)/rho_l)
bubbly (L_c«D) :
buoyancy = surface tension = inertia
L_c = sqrt(sigma/(gdelta_rho))
u_c = sqrt4((gdelta_rho*sigma)/(rho_l^2)
two phase mass balance
gamma(z) - gamma(z+dz) = 0
d(gamma)/dz = 0
d(gamma_l)/dz = d(gamma_g)/dz = 0 if no boiling or condensation
two phase momentum balance
(gamma_gu_g+gamma_lu_l)_z - (gamma_gu_g+gamma_lu_l)_z+dz = NFM
NFM = G^2d(x^2/epsv_g + (1-x)^2/(1-eps)v_l)/dzomega*dz
-dp/dz = G^2dv_m/dz + rho_actgsin(theta) + tau_wS/omega
…we need something for tau_w
pressure drop for homogeneous flow
f = 2tau_w/(G^2v)
Re = G*D/mu
Blausius correlation: f = A/Re^n
n = 0.2 for turbulent, 1 for laminar
-(dp/dz)_f = 2fG^2*v/D
homogeneous flow model
Re_tp = GD/mu_b
f_tp = A/Re_tp^n = 2tau_w/(G^2*v_b)
owens: mu_b = mu_l
cicchitti: mu_b = xmu_g + (1-x)mu_l
mcAdams: 1/mu_b = x/mu_g + (1-x)/mu_l
and
v_b = xv_g + (1-x)*v_l
We use mcAdams so:
Re_tp = GD(x/mu_g + (1-x)/mu_l)=
=GD/mu_l * (1 + xmu_lg/mu_g)
so:
f_tp = A/(Re_lo^n * (1 + x*mu_lg/mu_g)^n)
so:
-(dp/dz)_f,tp = 2 * f_lo * G^2 v_l/D * (1+xv_gl/v_l)/(1+x*mu_lg/mu_g)^n
liquid only vs liquid alone
-liquid ONLY means that the liquid flows with a flowrate equal to the total flow rate
-liquid ALONE means that the liquid flows alone with his superficial velocity
Descrbe the separated flow model
G°_g = gamma_g/omega = x * G (gas alone)
-(dp/dz)_g = 2f_gG°_g^2 * v_g/D
same for liquid so that:
Phi_g = -(dp/dz) / -(dp/dz)_g = fn (X)
X = sqrt( -(dp/dz)_l / -(dp/dz)_g )
Chisolm says:
Phi_g^2 = 1 + cost*X + X^2
so X_tt = f_l/f_g * (G°_l/G°_g)^2 * rho_g/rho_l =((1-x)/x)^(1-n/2) * sqrt(rho_l/rho_g) * (mu_l/mu_g)^n/2
why is 3 mm the limit between macro and micro pipes?
Because of the capillary length:
L_c = sqrt(sigma/(g*delta_rho)) = 3 mm
conf = L_c / D;
Bond = 1/conf^2
What are stable states?
in stable states the iosothermal compressibility:
k_T = -1/v(dv/dp)_T>0 so
(dp/dv)_T <0: these are the stable states
Thery are actually metastable (stable under small perturbations)
Bubble equilibrium curve
we start from thermodynamic equilibrium:
T_g = T_l
(p_g-p_l) * r^2pi = sigma2rpi
= >p_g = p_l + 2sigma / r
(dp/dT)_vpc = h_lg / (T_satv_lg)
3 hp: - small dp, dT
- v_lg = v_g
- far from T_crit
= > (p_g-p_l)/(T_g - T_sat) = h_lg/(T_satv_g)
2sigma/r = h_lg * (T_g-T_sat) / (T_sat*v_g)