More quizzes Flashcards
1
Q
- Gene duplication can give rise to homologous genes that are part of gene families. For example, there are six actin genes in the genome of most mammalian species. In humans, the ACTB gene, which encodes a cytoskeletal actin, is expressed ubiquitously, while ACTC1 is expressed mainly in cardiac cells. Although bacteria lack the eukaryotic cytoskeletal organization, the bacterial MreB gene bears recognizable sequence similarity to mammalian actin genes and codes for a protein that is similar to actin in structure and function. Which of the following statements is true about these genes?
A. ACTB is homologous to ACTC1 but not to MreB.
B. ACTB is orthologous to ACTC1 but not to MreB.
C. ACTB is paralogous to ACTC1 but not to MreB.
D. MreB is orthologous to ACTB but not to ACTC1.
E. ACTB is paralogous to both ACTC1 and MreB.
A
c
2
Q
- Histone subunits are modified to regulate transcription. There are also different variants of these histones subunits. What explanation most accurately explains the reason for variants?
A. Changes such as methylation and acetylation effect the distance between nucleosomes.
B. Methylation of histones over a large region creates heterochromatin forming structures such as the
centromere.
C. CENP-A substitutes for H3 which is important in centromere function and kinetochore assembly.
D. H2A substitutes for H2B to regulate processes such as transcription.
E. Non-histone proteins help stabilize the nucleosome and can be used as a substitution of a subunit.
A
c
3
Q
- Imagine a segment of DNA (within a gene) encoding a certain amount of information in its nucleotide sequence. When this segment is fully transcribed into mRNA and then translated into protein, in general, …
A. the protein sequence would carry more information compared to the DNA and mRNA sequences, because its alphabet has 20 letters.
B. the protein sequence would carry less information compared to the DNA and mRNA sequences, because several codons can correspond to one amino acid.
C. the amount of information in the mRNA sequence is lower, because the mRNA has been transcribed using only one of the DNA strands as the template.
D. the amount of information in the mRNA sequence is higher, because several mRNA molecules can be transcribed from one DNA molecule.
A
b
4
Q
- An elongating ribosome is bound to appropriate tRNAs in both the A and the P sites and is ready for peptidyl transfer. What happens next?
A. The carboxyl end of the polypeptide chain is released from the P-site tRNA and joined to the free amino group of the amino acid linked to the A-site tRNA.
B. The amino end of the polypeptide chain is released from the P-site tRNA and joined to the free carboxyl group of the amino acid linked to the A-site tRNA.
C. The carboxyl end of the amino acid is released from the A-site tRNA and joined to the free amino group of the polypeptide chain linked to the P-site tRNA.
D. The amino end of the amino acid is released from the A-site tRNA and joined to the free carboxyl group of the polypeptide chain linked to the P-site tRNA.
A
a
5
Q
- Put the following statements about RNA processing in the proper order.
1) Internal A nucleotide attacks the 5’ end of the intron to form a lariat
2) U1 snRNP recognizes the 5’ splice sequence
3) After about 25 nucleotides are synthesized a 5’- guanine cap is added
4) RNApolymerasedisassociates
5) AAUAAA sequence is recognized by poly-A polymerase
6) BBP recognizes the internal branch point site
7) Poly-A binding proteins add the poly-A tail to the 3’ end
A. 3-2-6-1-4-5-7 B. 3-6-2-1-4-5-7 C. 3-2-6-1-5-4-7 D. 5-7-2-6-1-3-4 E. 5-7-6-2-1-3-4
A
c
6
Q
- How does a eukaryotic cell deal with the superhelical tension in its genomic DNA resulting from the activity of RNA polymerases?
A. DNA gyrase introduces negative supercoils, keeping the DNA under constant tension.
B. The RNA polymerases are allowed to rotate freely around their templates during transcription, leading
to the relaxation of the tension.
C. DNA topoisomerases rapidly remove the superhelical tension caused by transcription.
D. The nucleosomes adjust the tension by binding to positively supercoiled regions behind a moving RNA
polymerase.
E. All of the above.
A
c
7
Q
- Comparing mRNA molecules from human and Escherichia coli cells, which of the following is typically NOT true?
A. A human mRNA has a special 5’ cap, while a bacterial mRNA does not.
B. A human mRNA has a poly-A tail, while a bacterial mRNA does not.
C. A human mRNA undergoes alternative splicing, while a bacterial mRNA does not.
D. A human mRNA contains noncoding sequences, while a bacterial mRNA does not.
E. A typical human mRNA encodes one protein, while many bacterial mRNAs encode several different
proteins.
A
d
8
Q
- In contrast to transporters, the channel proteins in cellular membranes …
A. interact strongly with the solute(s) that they transport.
B. undergo a conformational change every time they transport a solute.
C. can only mediate passive transport.
D. form pores that are always open.
A
c
9
Q
3. Which method is used to control the expression of a specific gene at the level of translation? A. histone actylation B. 3' UTR binding proteins C. alternative sigma factors D. DNA methylation E. eIF2 phosphorylation
A
b
10
Q
- Which of the following is NOT correct regarding cholesterol?
A. It is an amphiphilic molecule.
B. It is a sterol.
C. It makes the membrane less permeable to small hydrophilic molecules.
D. It is found in membranes of virtually all living cells.
E. It is concentrated in lipid rafts.
A
d
11
Q
6. Studying the expression of a transcription regulatory protein in two cell types, you have performed experiments showing that the mRNA encoding the protein is present at higher levels in the cytosol one of the cell types. Which of the following steps in expression of the gene encoding this protein is NOT likely to be differentially controlled in these cell types? A. Translation B. mRNAdegradation C. mRNAtransport D. Transcription
A
a
12
Q
- Demethylation of GC-island in the promoter decrease gene expression.
A. True
B. False
A
b
13
Q
- What determines the time and place that a certain gene is transcribed in the cell?
A. The type of cis-regulatory sequences associated with it
B. The relative position of cis-regulatory sequences associated with it
C. The arrangement of various cis-regulatory sequences associated with it
D. The specific combination of transcription regulators present in the nucleus
E. All of the above
A
e
14
Q
9. Which of the following DNA-binding motifs uses β sheets to recognize DNA bases? A. The helix-turn-helix motif B. Theleucinezipper C. The zinc finger motif D. The helix-loop-helix motif E. None of the above
A
e
15
Q
- Transcription regulation has similarities and differences in bacteria and in eukaryotes. Which of the following is correct in this regard?
A. DNA looping for gene regulation is the rule in bacteria but the exception in eukaryotes.
B. Most bacterial genes are regulated individually, whereas most eukaryotic genes are regulated in
clusters.
C. Transcription regulators in both bacteria and eukaryotes usually bind directly to RNA
polymerase.
D. The rate of transcription for a eukaryotic gene can vary in a much wider range than for a bacterial
gene
E. The default state of both bacterial and eukaryotic genomes is transcriptionally active.
A
d