More Lagrangian Stuff & Intro to Hamiltonian Flashcards

1
Q

Why use Lagrangian Methods?

A
  • Concepts have applications outside mechanics

- Can easily change coordinate system to the easiest one to use

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2
Q

Describe the problem with a mass on a cycloidal path.

A

Path defined by rolling a circle, and tracking the motion of a point on the circle.

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3
Q

How can we plot the position of the point mass on a graph?

A

x-y axis with θ being the max and minimum at +/- pi

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4
Q

What are the x and y coordinates equal to for this problem?

A
x = R*(θ+sinθ)
y = R*(1-cosθ)
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5
Q

What is a good choice of coordinates for this cycloidal path problem?

A

Distance u from the minimum position (x=0, y=0) at θ=0

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6
Q

What is the kinetic and potential energy equal to the the cycloidal path problem?

A

T = 1/2 * mu’^2, V = mgy = mgR(1-cosθ) = mgR2sin^2(θ/2)

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7
Q

For the potential energy V, how can we convert V(θ) to V(u)?

A

u is the length on the path, so we need to find u = integral from θ = 0 to θ’ du

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8
Q

What is the length of line element du equal to?

A

Use pythagoras: du^2 = dx^2 + dy^2 = ((dx/dθ)^2 + (dy/dθ)^2) (dθ)^2

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9
Q

How can we simplify the equation for du?

A

Substitute in the equations for x and y in the differentials, then rearrange.

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10
Q

What is the final equation for du?

A

du = 2R*cos(θ/2) dθ, so u = integral from θ=0 to θ’ of that.

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11
Q

How can we use the equation for u to change V(θ) to V(u)?

A

Rearrange for sin^2(θ/2), and substitute this into the equation for V(θ)

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12
Q

What do we find is the Lagrangian for the cycloidal path problem?

A

L = 1/2 * m*u’^2 - mgu^2/8R = L(u,u’)

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13
Q

What do we do with the Lagrangian after finding it for the cycloidal path problem?

A

Solve the E-L equation to find the equation of motion for it.

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14
Q

What is the equation for the Hamiltonian?

A

H = q’*dL/dq’ - L, for generalised coordinate q.

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15
Q

How do we find if the Hamiltonian changes with time?

A

Find dH/dt, assuming L(q,q’,t)

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16
Q

What is the first step in computing dH/dt?

A

-Use chain rule, so dH/dt = q’‘dL/dq’ + q’d/dt(dL/dq’) - (dL/dq * dq/dt + dL/dq’ * dq’/dt + dL/dt)

17
Q

What do we finally find for dH/dt?

A

dH/dt = q’*(d/dt(dL/dq’) - dL/dq) - dL/dt

This is E-L = 0, so dH/dt = -dL/dt

18
Q

Is the Hamiltonian conserved?

A

Yes

19
Q

What is the Hamtiltonian and how can we show this?

A

Is the total energy: show this by subbing in the Lagrangian and finding it is T+V rather than T-V.