Molecular Biology Flashcards

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1
Q

Outline the thermal, cohesive and solvent properties of water.

5 marks

A
  • water has a high specific heat capacity;
    (a large amount of heat causes a small increase in temperature);
  • water has a high latent heat of vaporization;
    (a large amount of heat energy is needed to vaporize/evaporate water);
  • hydrogen bonds between water molecules make them cohesive/stick together;
  • this gives water a high surface tension / explains how - water rises up xylem;
  • water molecules are polar;
  • this makes water a good solvent;
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2
Q

Describe the significance of water to living organisms.

6 marks

A
  • surface tension - allows some organisms (e.g. insects) to move on water’s surface
  • polarity / capillarity / adhesion - helps plants transport water
  • transparency - allows plants to photosynthesize in water / allows animals to see
  • (excellent) solvent - capable of dissolving substances for transport in organisms
  • (excellent) thermal properties (high heat of vaporization) - excellent coolant
  • ice floats - lakes / oceans do not freeze, allowing life under the ice
  • buoyancy - supports organisms
  • structure - turgor in plant cells / hydrostatic pressure
  • habitat - place for aquatic organisms to live
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3
Q

Describe the use of carbohydrates and lipids for energy storage in animals.

5 marks

A

carbohydrates: 3 max
- stored as glycogen (in liver)
- short-term energy storage
- more easily digested than lipids so energy can be released more quickly
- more soluble in water for easier transport

lipids: 3 max
- stored as fat in animals
- long-term energy storage
- more energy per gram than carbohydrates
- lipids are insoluble in water so less osmotic effect

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4
Q

List three functions of lipids.

3 marks

A
  • energy storage / source of energy / respiration substrate
  • (heat) insulation
  • protection (of internal organs)
  • water proofing / cuticle
  • buoyancy
  • (structural) component of** cell membranes**
  • electrical insulation by myelin sheath
  • (steroid) hormones
  • glycolipids acting as receptors
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5
Q

Describe the significance of polar and non-polar amino acids.

5 marks

A

polar amino acids: 3 max
- hydrophilic
- can make hydrogen bonds
- found in hydrophilic channels/parts of proteins projecting from membranes
- found on surface of water-soluble protein

non-polar amino acids: 3 max
- hydrophobic
- forms van der Waals/hydrophobic interactions with other hydrophobic amino acids
- found in protein in interior of membranes
- found in interior of water soluble proteins

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6
Q

Outline the role of condensation and hydrolysis in the relationship between amino acids and dipeptides.

4 marks

A
  • diagram of peptide bond drawn
  • condensation / dehydration synthesis: water produced (when two amino acids joined)
  • hydrolysis: water needed to break bond
  • dipeptide –> amino acids - hydrolysis occurs
  • amino acids –> dipeptide - condensation occurs
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7
Q

Describe the structure of proteins.

9 marks

A
  • (primary structure is a) chain of amino acids/sequence of amino acids
    (each position is occupied by one of) 20 different amino acids
  • linked by peptide bonds
  • secondary structure formed by interaction between amino and carboxyl/-NH and -C=O groups
    (weak) hydrogen bonds are formed
  • (α-) helix formed / polypeptide coils up
  • or (ß-) pleated sheet formed
  • tertiary structure is the folding up of the polypeptide
    stabilized by disulfide bridges / hydrogen / ionic / hydrophobic bond
  • quaternary structure is where several polypeptide subunits join
  • conjugated proteins are proteins which combine with other non-protein molecules
    for example metals / nucleic acids / carbohydrates / lipids
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8
Q

List four functions of proteins, giving an example of each.

4 marks

A

Structural eg. colagen, keratin
Hormonal eg. insulin, glucagon
Immunological eg. immunologlobins
Transport eg. heamoglobin
Sensory eg. rhdopsin
Movement eg. actin, myosin
Enzymes eg. amylase

Receptors eg. glycoprotein receptor
Electron carriers - cytochromes
Pigments - opsin
Active transport - sodium potassium pumps/calcium pumps
Facilitated diffusion - sodium channels/aquaporins

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9
Q

Distinguish between fibrous and globular proteins with reference to one example of each protein type.

6 marks

A
  • fibrous proteins are strands/sheets whereas globular proteins are rounded;
  • fibrous proteins (usually) insoluble whereas globular proteins (usually) soluble;
  • globular more sensitive to changes in pH/temperature/salt than fibrous;
  • fibrous proteins have structural roles / other specific role of fibrous protein;
  • globular proteins used for catalysis/transport/other specific role of globular protein;
    another role of globular protein;
  • named fibrous proteins e.g. keratin/fibrin/collagen/actin/myosin/silk protein;
  • named globular protein e.g. insulin/immunoglobulin/hemoglobin/named enzyme;
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10
Q

Lactase is widely used in food processing. Explain three reasons for converting lactose to glucose and galactose during food processing.

3 marks

A
  • it allows people who are lactose intolerant/have difficulty digesting lactose to consume milk (products);
  • galactose and glucose taste sweeter than lactose reducing need for additional sweetener (in flavoured milk products);
  • galactose and glucose are more soluble than lactose / gives smoother texture / reduces crystalization in ice cream;
  • (bacteria) ferment glucose and galactose more rapidly (than lactose) **shortening production time **(of yoghurt/cottage cheese);
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11
Q

Simple laboratory experiments show that when the enzyme lactase is mixed with lactose, the initial rate of reaction is highest at 48 °C. In food processing, lactase is used at a much lower temperature, often at 5 °C. Suggest reasons for using lactase at relatively low temperatures.

2 marks

A
  • less denaturation / enzymes last longer at lower temperatures;
  • lower energy costs / less energy to achieve 5 °C compared to 48 °C;
  • reduces bacterial growth / reduces (milk) spoilage;
  • to form products more slowly / to control the rate of reaction;
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12
Q

Outline how enzymes catalyse reactions.

7 marks

A
  • they increase rate of (chemical) reaction;
  • remains unused/unchanged at the end of the reaction;
  • lower activation energy;
  • activation energy is energy needed to overcome energy barrier that prevents reaction;
  • annotated graph showing reaction with and without enzyme;
  • substrate joins with enzyme at active site;
  • to form enzyme-substrate complex;
  • active site/enzyme (usually) specific for a particular substrate;
  • enzyme binding with substrate brings reactants closer together to facilitate chemical
  • reactions (such as electron transfer);
  • induced fit model / change in enzyme conformation (when enzyme-substrate/ES complex forms);
  • making the substrate more reactive;
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13
Q

Explain the effect of pH on enzyme activity.

3 marks

A
  • enzymes have an optimal pH
  • lower activity above and below optimum pH / graph showing this
  • too acidic / base pH can denature enzyme
  • change shape of active site / tertiary structure altered
    substrate cannot bind to active site / enzyme-substrate complex cannot form
  • hydrogen / ionic bonds in the enzyme / active site are broken / altered
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14
Q

Compare the induced fit model of enzyme activity with the lock and key model.

4 marks

A
  • in both models substrate binds to active site
  • substrate fits active site exactly in lock and key, whereas fit is not exact in induced fit
    substrate / active site changes shape in induced fit, whereas active site does not change shape in lock and key
  • in both models an enzyme - substrate complex is formed
  • in lock and key: binding reduces activation energy, whereas in the induced fit: change to substrate reduces activation energy
  • lock and key model explains narrow specificity, whereas induced fit allows broader specificity
  • induced fit explains competitive inhibition, whereas lock and key does not
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15
Q

Draw graphs to show the effect of enzymes on the activation energy of chemical reactions.

5 marks

A
  • vertical axis with energy label and horizontal axis with time label
  • labels showing reactant / substrate and product
  • labeled line showing correct shape and curve without enzyme
  • labeled line showing correct shape and curve with enzyme
  • labels for activation energy with and without enzymes
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16
Q

Explain, using one named example, the effect of a competitive inhibitor on enzyme activity.

6 marks

A
  • competitive inhibitor has similar shape/structure to the substrate
  • therefore it fits to the active site
  • no reaction is catalyzed so the inhibitor remains bound
  • substrate cannot bind as long as the inhibitor remains bound
  • only one active site per enzyme molecule
  • substrate and inhibitor compete for the active site
  • therefore high substrate concentrations can overcome the inhibition
  • as substrate is used up, ratio of inhibitor to substrate rises
  • named example of inhibitor plus inhibited enzyme / process / substrate
  • EG. COMPETATIVE
    1. NEONICOTINOIDS for ACETYLCHOLINE
    2. KRTAMINE for GLUTAMATE
    3. CARBON MONOXIDE for HEAMOGLOBIN+O2
  • EG. NON COMPETATIVE
    1. CYANIDE for CYTOCHROME OXIDASE (block of respiration)
17
Q

Explain how proteins act as enzymes, including control by feedback inhibition in allosteric enzymes.

9 marks

A
  • enzymes are globular proteins
  • there is an active site
  • substrate(s) binds to active site
  • shape of substrate (and active site) changed / induced fit
  • bonds in substrate weakened
  • activation energy reduced
  • sketch of energy levels in a reaction to show reduced activation energy
  • in feedback inhibition a (end) product binds to the enzyme
  • end-product is a substance produced in last / later stage of a pathway
  • modulator / inhibitor / effector / product binds at the allosteric site / site away from the active site
  • binding causes the enzyme / active site to change shape
  • substrate no longer fits the active site
    the higher the concentration of end-product the lower the enzyme activity
  • enzyme catalyzes the first / early reaction in pathway so whole pathway is inhibited
  • prevents build-up of intermediates
  • allosteric inhibition is non-competitive
18
Q

Discuss the solubility of proteins in water.

4 marks

A

many proteins are soluble in water:
- solubility depends on what amino acids /R groups are present
- smaller proteins are more soluble than big ones
- proteins with many polar / hydrophilic amino acids / R groups are more soluble / soluble
- proteins with polar / hydrophilic amino acids / R groups on the outside are soluble
- example of a polar amino acid / group
- globular proteins are more soluble than fibrous proteins

however, the solubility of proteins can be limited:
- solubility of proteins may also be affected by conditions (pH, temperature, salinity)
- denaturation makes proteins insoluble
- proteins do not form true solutions in water but colloidal solutions

19
Q

Describe the structure of triglycerides.

6 marks

A
  • composed of C, H and O (must be stated)
  • relatively more C and H/less O than carbohydrates
    composed of fatty acids and glycerol
  • glycerol is CH2.OH.CH.OH.CH2OH/ diagram showing it separately or as part of a triglyceride
  • fatty acids are carboxyl groups with hydrocarbon chain attached/ diagram showing it separately or as part of a triglyceride
  • ester bonds/diagram showing C-O-C=O
  • three fatty acids/hydrocarbon chains linked to each glycerol (must be stated)
  • 12-20 carbon atoms per hydrocarbon tail/diagram showing this number
  • saturated if all the C-C bonds are single/unsaturated if one or more double bonds
  • whole molecule is nonpolar/hydrophobic