module 5 Flashcards

1
Q

dynamic equilibrium

A

rates of forwards and reverse reaction are equal but non-zero
- concentrations are constant

eg. saturated solution of sodium chloride

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2
Q

what pracs can you use for reversibility

A

reversibility of the dehydration of cobalt (II) chloride
- hexahydrate pink
- anhydroussky blue
reversibility of combustion metals –> shows the lack of reversibility
- combustion of magnesium and steel wool
- no changes occur when placed in ice bath

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3
Q

system

A

boundary of where the reaction occurs and composed of both substances and energy
- open
- closed

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4
Q

closed system

A
  • constant number of particles in a system (no matter transfer)
  • energy can be exchanged with the surroundings
    eg. sauce pan and lid
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5
Q

open system

A
  • system can interact with the surroundings allowing for the exchange of matter and energy
    eg. boiling water without a lid
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6
Q

static equilibrium

A

the rates of forward and reverse reaction are equal and zero
- irreversible reaction at completion eg. dissolution of salt in unsaturated solution
- irreversible reaction before initiation
eg. combustion of fuel without th initial spark
- reversible reaction with insurmountable activation energy
eg. diamond and graphite

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7
Q

modelling dynamic equilibrium

A

counters or cards

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8
Q

enthalpy

A

amount. of stored heat energy within a substance
H reaction = h products - h reactants
- reactants > products (exo) (more energy for bond forming) forward
- reactants < products (endo) ( more energy for bond breaking) reverse

  • kJ mol-1
    -J mol-1

combustion: negative enthalpy change
photosynthesis: positive enthalpy change

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9
Q

entropy

A

measure of state of disorder in a chemical system
- J mol-1K
kJ mol-1K

delta s = sum of s products - sum of s reactants
S<0 reverse
S>0 forward
combustion: positive entropy change
photosynthesis: negative entropy change

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10
Q

difference between enthalpy and entropy

A

absolute value and change

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11
Q

law of thermodynamics

A
  1. Zeroth Law of Thermodynamics
    - if two systems are in thermal equilibrium with a third system, then they are in thermal equilibrium with each other
  2. The First Law of Thermodynamics
    - energy movement into or out of a system is in accordance with the law of conservation of energy
  3. The Second Law of thermodynamics
    - entropy of an isolated system not at equilibrium will increase over time, approaching maximum value at equilibrium
  4. The Third Law of Thermodynamics
    - the entropy of a system approaches a minimum as the temperature approaches zero
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12
Q

what is the enthalpy and entropy change in reverse reactions

A

H>0

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13
Q

collision theory

A
  • based on the principle that all matter is made up of tiny particles which are in constant motion and reactant particles have successful or unsuccessful collisions
  • collision theory explains that chemical reactions take place when molecules with sufficient energy collide at a correct orientation (successful collision)
  • high conc (reactants) – collide at high frequency –> rate of reactants formed high –> conc of reactants decreases –> forward reaction reduces over time
  • increased conc of products as they are being formed –> collision of reverse increases
  • reaches dynamic equilibrium
  • conc of both is rarely equal
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14
Q

how to increase rate of reaction through collision theory

A
  • frequency of collisions increase
  • individual collisions must have a higher chance of being successful
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15
Q

rate of reverse reaction is proportional to

A

products

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16
Q

rate of forward reaction is proportional to

A

reactants

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17
Q

Le Chateliers Principle

A

if a system is at dynamic equilibrium is disturbed, then the system will shift so to minimise the change until a new equilibrium is reached
- change in: volume/pressure, concentration, temperature

  • the change will never be completely nullified
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18
Q

shift to the right

A

forward reaction begins to exceed rate of reverse reaction

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19
Q

shift to the left

A

reverse reaction begins to excess rate of forward reaction

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20
Q

concentration LCP

A
  • increase reactants –> forward reaction –> right by LCP
  • increase products –> forward reaction –> left by LCP
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21
Q

what has no effect if added or removed within a system on the equilibrium

A

liquids and solids (solvents accepted)

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22
Q

what happens if water is added to a system

A

concentration decreases –> favours forward reaction

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23
Q

endo or exo
reactants + heat –> products

A

endo
delta H > 0

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24
Q

endo or exo
reactantas –> products + heat

A

exo
delta H < 0

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25
temperature LCP
increases temp --> favours endo side (usually left reverse) decreases temp--> favours exo side (usually right forward)
26
pressure/volume LCP
partial pressure of reactants pumped 3:2 - shifts to the right by LCP to lower the number of moles of substance per unit volume volume decreases --> pressure increases --> concentration increases - 3:2 - shifts to the rights by LCP to decrease the number of moles present - inert gas has no effect on equilibrium --> make time taken to reach longer
27
partial pressure of a gas
hypothetical pressure if it were only the gas occupying the volume of the mixture, under the same conditions
28
total pressure of an ideal gas mixture
equal to the sum of the partial pressures of each component gas
29
inert gases
no effect on equilibrium
30
catalyst
substance which increases the rate of reaction by providing an alternate pathway with a lower activation energy
31
is a catalyst consumer or produced in a reaction
no
32
catalyst effect on equilibrium
- hastens attainment of equilibrium - ratio of reactants and products is identical for catalysed and uncatlysed reactions
33
nitrogen dioxide
brown
34
dinitrogen tetroxide
colourless
35
equation for the interaction between nitrogen dioxide and dinitrogen tetroxide and colours and exo or endo
2NO2 --> N2O4 NO2 --> brown N2O4 --> colourless - exo
36
concentration via collision theory
- in a system at equilibrium, when the concentration of reactants is increased, there is an increased number of collisions between reactant particles --> rate of forward reaction increases as per collision theory - As new product particles form due to the increased rate of reaction the reverse reaction also increases as the concentration of products increase - over time a new equilibrium is re-established where the forward and reverse rates of reaction are equal - overall the equilibrium shifted to the right by LCP - reverse reaction is also higher than at old equilibrium - means forward rate is higher - therefore not all of new added reactant is removed
37
temperature via collision theory
- endothermic has higher activation energy for forward rather than reverse and exothermic has a lower activation energy for the forward reaction - increasing temp increases rate of any reaction as the proportion of particles with enough energy to overcome the activation energy increases and collision frequency increases - increasing temp has a greater effect on reaction rate when activation energy is high --> greater relative proportion of molecules will have enough energy to overcome activation energy - thus increasing temp for endo leads to an increased forward and reverse rate - however, since forward has higher activation energy, rate of forward is increase to greater than rate of reverse ---> more product molecules - therefore endo is favoured in the increase in temp
38
exothermic (activation energy)
lower for forward
39
endothermic (activation energy)
lower for reverse
40
pressure via collision theory 4:2 molar ratio
4:2 - if we decrease total volume --> increase total pressure - reactant and product molecules are brought together --> increasing collision frequency --> increasing rate of reaction of both forward and reverse - however, more moles of reactant gas --> more frequent collisions in reactant particles - rate of forward exceed rate of reverse until enough product molecule is formed to make both rates equal - more products were formed --> because it shifted right to the side with fewer moles of gas by LCP
41
addition of inert gas via collision theory
- wont change partial pressure of reactant and product gases - collision between inert gas and molecules taking place in chemical reaction is unsuccessful - addition of unsuccessful collisions will obstruct potentially sucessful -reduce both forward and reverse rates of reaction - hence equilibrium will take a longer time to reach
42
equilibrium constant
quantitative relationship between concentration of reactants and products at equilibrium - dictates the position of equilibrium - Keq is large = equilibrium position is side of products ie. right - Keq has a middling value = (0.1 - 10) = equilibrium exists as a medium measure - Keq is small = equilibrium position is side of reactants ie. left - K - Keq K = (products)^coefficients/(reactants)^coefficients - must be gases or aqueous
43
Q
concentrations of reactants and products for reaction is not yet at equilibrium Q = (same equation as K) - Q < K = system will proceed to the right to increase concentration of products (more reactants) - Q = K = system is at dynamic equilibrium - Q > K = system will proceed to the left to increase concentration of reactants (more products)
44
if pressure, volume or concentration is changed
equilibrium will sift but old Keq can still be satisfied
45
what is the only factor that can change the K value
temperature exo - increase in temp --> favours endo --> shift left by LCP--> more reactants --> smaller Keq - decrease temp --> favours exo --> shifts right by LCP --> more products --> larger Keq endo - increase temp --> favours exo --> shifts right by LCP --> more products --> larger Keq - decrease temp --> favours exo --> shifts left by LCP --> more reactants --> smaller Keq
46
3 ways to do ICE tables
- standard - quadratic - small change assumption
47
small change assumption
relative large number is added or subtracted to a relatively small number of x FIXXX
48
way to manipulate Keq
- reciprocal - square - add multiple equations together
49
catalyst via collision theory
- catalyst provides and alternate pathway for a reaction through lowering the activation energy - allows for energetically weaker collisions which were deemed unsuccessful to be considered successful - rate of forward and reverse simultaneously increase therefore relative concentration of products and reacts will not change at equilibrium - therefore changes to activation energy will never effect the value of K eq however it hastens the time taken to reach it
50
lower activation energy of forward reaction
- keq will be larger --> right by LCP
51
iron (III) nitrate
pale-orange or yellow Fe(NO3)3
51
lower activation energy of reverse
- keq will be smaller --> left by LCP
52
potassium thiocyanate
colourless KSCN
52
iron (III) thiocyanate
blood red
53
determining Keq prac
iron (III) thiocynate --> FeSCN
54
ways to calculate keq
- ICE tables - colorimetry
55
colorimetry
method of analysis which relates the absorbance of light of a specific wavelength by a colour solution to a quantitative measurement of the concentration of the solute - standard solutions with a known solute at certain concentrations analysed with a colorimeter to determine absorbance - relies on beer lambert
56
calibration curve axis
for colorimetry x-axis: concentration y-axis: absorbence
57
method of colorimetry
1.colorimeter passes light through a sample and measures the intensity of light of a specific wavelength received by the detector on the other side 2. gives a reading of the absorbency of the standard solution (unit less) between 0 - 1 3. performed number of times and calibration curve is formed - sample solutions with the same solute can be analysed through finding the absorbance and the concentration an be read of the curve
58
what does colorimetry rely on
beer lambert law: - absorbance is directly proportional to the concentration of a substance - when absorbance is plotted against concentration --> expect linear relationship
59
change in gibbs free energy
- refers to the maximum amount of work that can be performed by a thermodynamic system during a chemical process delta G = delta H -T delta S - usually J delta G < 0 = spontaneous - reaction will go to completion without an external energy input (usually a flame at the start) (exergonic) delta G > 0 = non-spontaneous - continuous energy input is required to force the reaction to occur (endergonic) delta G = 0 - neither spontaneous or non-spontaneous
60
gibbs free and Keq
large negative delta G --> Keq is large --> positioned to the right - forward spontaneous
61
rule of solubility
polar solutes dissolve in polar solvents non-polar solutes dissolve in non-polar solvents
62
when will a solute dissolve
if the formation of intermolecular forces between the solute and the solvent are more favourable than the existing intermolecular forces between solute molecules and solvent molecules
63
dissolution
solute -solute bonds: broken (requires energy --> endothermic): - ionic lattice held together by ionic bonds --> forces of electrostatic attraction between positively and negatively charged ions solvent-solvent bonds: broken (requires energy --> endothermic): - liquid state (water molecules are held together by intermolecular forces eg. hydrogen bonding, dipole - dipole interactions, dispersion forces) solute-solvent interactions: formed (between ions and water molecules --> energy is released --> exothermic) - solvation/hydration(case of water) --> solvent molecules form hydration spheres around individual ions - the ion - dipole forces are formed between the ions and the water molecules are. formed --> stronger than hydrogen bonding in water molecules
64
hydration
in aqueous solutions - NaCL dissolves in water, slightly positive hydrogen in the polar H2O orients towards the Cl- anions while the slightly negative oxygens orient themselves towards the Na+ cations
65
salts that dissolve exothermically
CaCl2 NaCO3 NaOH
66
salts that dissolve endothermically
KCl NaHCO3 (bi - carb) NH4O3
67
entropy during dissolution
increases - ionic lattice has low entropy --> ions are in a fixed position - the hydrated ions are free to move --> higher entropy
68
how does dissolution effect the ionic lattice
once an ion from one corner or edge is broken off --> more edges and corners are formed --> increasing number of sites for dissolution
69
how to determine if dissolution of substance is static equilibrium or dynamic equilibrium
saturated (dynamic) or unsaturated solution (static)
70
what equilibrium is unsaturated solution
static - heavily favoured forward reaction
71
what equilibrium is saturated solution
dynamic - both rates of forward and reverse gradually become equal - dissociation is occurring at the same rate as precipitation - when solute added to saturated solution --> total mass of dissolved solute wont increase - dynamic eq is still formed because ions are in constant motion
72
unsaturated
salt will completely dissolve
73
saturated
- maximum amount of salt has been dissolved to reach dynamic equilibrium sufficient salt is added to dissolve - precipitate can form - eq constant = ksp
74
supersaturated
formed when a solution is heated or cooled to allow for more solute to be dissolved than at standard conditions
75
what is the concentration of a saturated solution
solubility
76
what equilibrium is unsaturated solution
dynamic - precipitate out any excess dissolved solute when standard conditions are re-esablished
77
if the concentration of a saturated solution is:
soluble: >10g/L partially soluble: 1 - 10g/L insoluble: <1g/L
78
relate gibbs free to dissolution
spontaneous (delta G < 0) = soluble salt
79
islander fruit
cycad --> toxin: cycasin (C8H16N2O7) - carcinogenic to detoxify - crushed increases surface are two methods of removing toxins: - roasting (increases rate of reaction) --> leaching - leaching for long periods of time - water is drained --> resultant extracted --> pounded into fine powder again --. leached again - repeated leaching and pounding ensures little cycasin left as possible
80
explain removing cycasin from cycad using solubility equilibrium
- cycasin (s) --> <--- cycasin (aq) - when seed is leached --> solid cycasin dissolves into the water in its aqueous form --> reaches dynamic eq - water is drained --> dissolved toxin is removed (some solid cycasin may be left) - process repeated with more clean water - some of the toxin will produce more cycasin (aq) due to dynamic equilibrium - the toxin will be leached out again by draining - boiling water aids this --> increase temp --> increase rate of reaction - more Cycasin (aq) toxin produced and drained away
81
solubility of cycasin
56.6 L G L -1
82
cobalt (II) chloride aqueous prac
endothermic - mixture heated --> favours endo --> shifts right by LCP --> blue CoCl42- - mixture cooled --> favours exo --> shifts left --> more pink Co(H2O062+
83
Ksp/ dissociation constant
tendency of a substance to dissociate ?? - larger --> more likely to dissociate to respective ions - lower --> less likely to dissociate
84
precipitation
precipitation reaction involves two solutions mixing together resulting in the formation of an insoluble solid --> precipitate
85
precipitate
insoluble solid eg. silver chloride, lead (II) iodide, barium sulfate
86
solubility rules
NAGSAG N: nitrate A: ammonium G: group 1 S: sulfate except CaStroBar compounds A: acetate G: group 7
87
what happens when a slightly ionic substance dissolves in water in sufficient quantities
some dissolves while some remains as a solid
88
solubility measurements
- g/100ml - mol L -1
89
ionic product
Qsp: when concentrations are not necessarily at equilibrium Qsp < Ksp = unsaturated - more ionic solid will dissolve if added (right) Qsp = Ksp - at equilibrium and saturated Qsp > Ksp = solution may be supersaturated and ionic solid will precipitate (left)
90
common ion effect
- possible to dissolve salts into solutions that already contain one or more of the same dissolved ions - decreases solubility of salts when dissolved in comparison to dissolution in pure water (DUE TO LCP increased conc of an ion causes the reverse reaction eg precipitation) - if insoluble or sparingly soluble is added to the solution the concentration of the common ion does not change very much --> small change assumption
91
is there a limiting reagent in dynamic equilibrium
no
92
steps for finding K sp
- identify salt precipitated (least soluble) - write equilibrium reaction for dissolution - ice table
93
prac for precipitations
droppers and observe colours
94
lead (II) iodide precipitate
yellow
95
iron (II) hydroxide precipitate
green that tuns reddish brown as Fe2+ oxidises to Fe+
96
silver chloride precipitate
white
97
copper (II) hydroxide precipitate
blue-green
98
barium sulfate precipitate
white
99
reaction rate
dependent on frequency and success of collisions