Module 4 Interference Flashcards
Principal of superposition
when two waves of similar type meet at a point, the sum of their displacements is equal to the displacement of the resultant wave
What is a pulse?
A fragment of a wave
Define path difference
difference in the distance from one source to the detector compared to another source to the detector
Formula for path difference
S1P – S2P in meters (SP being length)
What is phase difference?
the angle by which a wave lags or leads another
What is the phase difference of waves in phase?
0 or 2π radians
(0 or 360 degrees)
What is the phase difference of two waves in anti-phase
π or 3π radians
(180 or 540 degrees)
Definition of coherent waves
when two waves of the same type are emitted with a constant phase difference, same frequency, wavelength, plane polarised in the same plane and similar amplitude (same magnitude)
Definition of interference
Superposition of two progressive waves from coherent sources to produce a resultant wave with displacement equal to the vector sum of individual displacement of the two waves
How is intensity increased if amplitude is doubled
intensity is increased by multiple of 4
What is constructive interference?
when two waves meet in phase their amplitude/displacement adds up
Path difference is a whole number of wavelengths
What is destructive interference?
When two waves meet exactly out of phase (in antiphase) the displacements cancel out and produce a wave of zero displacement and amplitude
Path difference is a whole number of wavelengths plus half wavelength
Explain how you would measure the wavelength of a monochromatic laser using two source interference?
- place the laser in front of a double slit board facing a screen
- measure the distance between the centre of the slits using a traveling microscope by using a vernier scale - this is a
- measure the distance between multiple fringes on the screen (say 8) then divide by the number of gaps (7) - this is x
- measure the distance between the double slit and screen - this is D
use the formula λ = ax/D
How to observe the interference of sound waves?
- Attach a speaker to a signal generator
- place speaker behind a double slit board with slits approx 10cm wide
- Measure distance between centre of slits on the board - this is a
- Move a microphone parallel to the slit board at a given distance and measure where the maxima and minima are (loud and quiet) - this is x/2
This is interference
YOUNGS DOUBLE SLIT EXPERIMENT WITH WHITE LIGHT
Central fringe is white (path difference is the zero for all wavelengths in white light)
Each constructive interference position is a spectrum from blue to red (blue is closest to the straight through position so at a smaller angle than red)
When investigating the interference of visible light, what is a suitable value for a (slit separation)?
<1mm
Why when carrying out Young’s double slit experiment, does the value for a (the slit) need to be approx = to the wavelength. of light being used?
so light diffracts so that interference can be observed
When carrying out Young’s double slit experiment, why must multiple fringes be measured to find the value of x?
to reduce percentage error due to random error (unc on x)
you are measuring a larger distance for several fringes so error/measurement x 100 is lower ie percentage uncertainty lower
Describe how you would observe two source interference using a microwave generator
- Attach two transmitter cones to a microwave generator
- Move a receiver probe parallel to the transmitter cones at a set distance
- Receiver will measure alternating patterns of strong and weak signals
How are fringes labelled?
as orders - zero order, first order, second order, etc. labelled from the straight through position
(order number is n in diffraction formula)
What is a word to describe when waves are at 0º to each other?
in phase
What do you use to measure the distance a in an the young’s double slit experiment?
a travelling microscope with a vernier scale
What can be said about the relationship between wavelength and distance between maxima and minima?
shorter wavelength the shorter the path difference between maxima and minima
for maxima, path difference = whole wavelengths
for minima, path difference=half wavelength + whole wavelength