Module 4: Alkanes (Chapter 12) Flashcards

1
Q

Define sigma bonds

A

Overlap of orbitals on the line directly between the bonding atoms. This is end on overlap. Free rotation is possible

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Bond angle in alkanes

A

109.5 = 4 bonded pairs around each carbon atom meaning electrons repel as far as part as possible. Leads to a tetrahedral arrangement.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Reason for high bp with increasing chain length

A

More points of surface contact due to increased surface area. Means stronger London forces so more energy needed to overcome the intermolecular forces.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Reasons for low bp with more branching

A

Fewer points of surface contact so weaker London forces, so less energy needed to overcome intermolecular forces.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

Why are alkanes so unreactive?

A

High bond enthalpy due to sigma bonds, non-polar between C-C and negligible electronegativity between C-H means they are considered non-polar

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Why does CO kill?

A

Combines irreversibly with Hb in red blood cells to form carboxyhaemoglobin preventing oxygen being transported around the body. Odourless and colourless so unknown.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

3 stages of radical substitution

A

Initiation
Propagation
Termination

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Reactant needed for initiation

A

UV radiation

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

How does termination differ from other steps?

A

Involves 2 radicals colliding to form a stable species, whereby no more free radicals are produced

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Limitations of radical substitution

A

Further substitution = until all H atoms removed. Results in a mixture.
Substitution at different points along the carbon chain = results in isomers

How well did you know this?
1
Not at all
2
3
4
5
Perfectly