Module 3.5

Question 1

Conservation of momentum

Answer 1

The total momentum of a system before an event must be equal to the total momentum of the system after the event, assuming no external forces act

Question 2

Elastic collisions

Answer 2

A collision in which the total kinetic energy of the system before the collision is equal to the total kinetic energy of the system after the collision

Question 3

Impulse

Answer 3

The change of momentum of an object when a force acts on it. It is equal to the product of the force acting on the object and the length of time over which it acts

Question 4

Inelastic collsions

Answer 4

A collision in which the total kinetic energy of the system before the collision is not equal to the kinetic energy of the system after the collision

Question 5

Linear momentum

Answer 5

The product of an object’s mass and linear velocity

Question 6

Newtons first law

Answer 6

An object will remain in its current state of motion, unless acted on by an resultant force. An object requires a resultant force to be able to accelerate

Question 7

Newtons second law

Answer 7

The resultant force on an object is equal to the rate of change of momentum

Question 8

Newtons third law

Answer 8

If body A exerts a force on body B, then body B exerts a force back on body A of equal in magnitude and opposite in direction of the same type

Question 9

What are the 4 fundamental forces

Answer 9

Gravitational, electromagnetic, strong nuclear force and weak nuclear force

Question 10

Is Linear momentum a vector or scalar quantity

Answer 10

Vector quantity

Question 11

what does the area under a force-time graph mean

Answer 11

Impulse and change in momentum

Question 12

What is always conserved in collisions

Answer 12

momentum

Question 13

What is the formula for a one dimensional collision

Answer 13

m1u1 + m2u2 = m1v1 + m2v2

Remember velocity is a vector quantity and add the negative signs

Question 14

In a 2D collision m1 hits the particle m2 with the velocity v0 in the x-axis and 0 velocity in the y-axis. m1 is sent with velocity v1 at an angle Z1 from the normal and m2 is send with velocity v2 with an angle Z2.

What is the formula for the momentum for this system in the x-direction and y-direction

Answer 14

Initial momentum = final momentum

x-direction: m1v0 = m1v1cos(Z1) + m2v2cos(Z2)

y-direction: 0 = m1v1sin(Z1) + m2v2sin(Z2)