Module 3 Flashcards

1
Q

Describe the effect of kVp on the quality of the x-ray beam

A

When kVp is increased, the speed of the electrons is increased making them hit the tungsten target with greater force and energy creating a more penetrating x-ray with shorter wavelengths = higher quality x-ray

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2
Q

Describe the effect kVp on the x-ray image (density and contrast)

A

Increasing kVp results in an increased overall density (darkness) on the image

Low kVp = high contrast (black/white)
High kVp = low contrast (gray)

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3
Q

Describe the effects of mA on the quantity of the x-ray beam

A

As mA is increased more electrons are produced increasing the number of x-rays produced

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4
Q

Describe the effect of mA on the x-ray image (density)

A

Increasing mA increases the overall density of the x-ray giving you a darker image; lowering the mA reduces the overall density of the image

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5
Q

Describe the relation of exposure time with kVp and mA

A

If you increase kVP, mA increases, and you will decrease the exposure time

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6
Q

Describe how distance affects the intensity of the x-ray beam

A

As an x-ray travels from the tungsten target the intensity of the beam lessens

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7
Q

List the distances that need to be considered when taking an x-ray

A

Target-surface distance
Target-object distance
Target-film/receptor distance

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8
Q

Define target-surface distance

A

The distance from the source of radiation to the pt’s skin

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9
Q

Define target-object distance

A

The distance from the source of radiation to the tooth

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10
Q

Define target-receptor distance

A

The distance from the source of radiation to the receptor/film

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11
Q

Define the inverse square law

A

The intensity of radiation is inversely proportional to the square of the distance from the source of the radiation

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12
Q

Describe how the inverse square law informs whether an 8 inch PID or 16 inch PID has more intense x-ray beams

A

When you change an 8 inch PID to a 16 inch PID, the source of film distance is now doubled so the beam is now 1/4 the intensity

Original intensity/new intensity = new distance^2/original distance ^2

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13
Q

Describe what is meant by half-value layer

A

The thickness of the tube filter (aluminum filters), which is placed in the path of the beam inside the x-ray tube head, removes low-energy, less penetrating longer wavelength x-rays

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14
Q

How is the half-value layer related to the intensity of the x-ray beam?

A

Decreases the intensity of the x-ray beam by half

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