Module 27: Coordinate Geometry Flashcards
Location of the 4 quadrants on the coordinate plane
In counter-clockwise order, starting in the top left, I, II, III, IV
Calculating slope
Rise/run
OR
y2 - y1 / x2 - x1
Slope of a hoirzontal line is _____; slope of a vertical line is ________
Zero; undefined
Slope-Intercept Equation
y = mx + b
Coordinate plane: Shortcut to find X & Y intercepts
Set X and Y equal to 0 in the original equation of y = mx+b.
y = -2x + 5 0 = -2x + 5 0 = -x + 5/2
x = 2.5 y = -2x + 5 y = -2(0) + 5 y = 5
Calculating the x-intercept
1) Re-work the slope-intercept equation to isolate X.
y = mx +b
y - b = mx
x = (y - b) / m
2) Replace Y with 0
x = -b / m (b = Y intercept, m = slope)
The equation for a vertical line is x = ____
the X intercept. Just one number.
Same idea for a horizontal line: Y = 4 (if the y-intercept is 4)
How to determine if a point is on a line, when the slope-intercept equation of the line is given
1) Insert the x & y values of the point into the slope-intercept equation that was given.
2) Simplify
3) If the statement is true, the point is on the line. If it’s false, the point is not on the line
In order to define a line’s equation, you must know one point on the line as well as (2 options:)
- the slope of the line (or a slope of a line that is parallel/perpendicular)
- a second point on the line, to then use rise/run to find the slope
How to calculate distance between two points
Pythagorean theorem!
- Graph the line, draw legs of a right triangle below it.
- Vertical leg = rise, horizontal leg = run
- (rise)^2 + (run)^2 = c^2
The product of the slope of two perpendicular lines
-1 (always, because they are negative reciprocals)
For example: 2 and - 1/2
Coordinates of an x-axis reflection
(x,y) -> (x,-y)
The Y value gets flipped
Coordinates of a y-axis reflection
(x,y) -> (-x,y)
The X value gets flipped
Coordinates of a reflection over the origin
(x,y) -> (-x,-y)
Both points get flipped
Reflecting a line, steps
1) Pick any 2 points on the line (start with the Y intercept and 1-2 spots away from it - easiest)
2) Reflect the 2 points over the line axis. Re-calc the slope for these points if need be
* Note: Reflections are not necessarily perpendicular