Midterm 1 Flashcards
CH 13 Solutions CH 16 Kinematics
As charge density _______, the heat of hydration will become more ______
As charge density increases, the heat of hydration will become more negative
Heat of Hydration Equation
Concentrated aqueous HCl contains 38% w/w HCl. Calculate the mass of water present in 250. g of this solution.
1-.38=.72 *100% = 72% H20
250g H20 * 72% =155g
The hydration of an ion is always (exothermic/endothermic) because ion-dipole forces are very strong
Exothermic (-)
What is the equation for heat of hydration of water?
Which of the following pairs of ions is arranged so that the ion with the larger heat of hydration is listed first?
A)Ca2+, Sc3+
B)Na+, Li+
C)Br-, K+
D)Mg2+, Sr2+
D)Mg2+, Sr2+
Select the type of interaction that best describes the attraction between Mg2+ ions and water molecules.
ion-dipole
Consider the expression below, showing the terms which contribute to the heat of solution, ΔHsoln:
ΔHsoln = ΔHsolute + ΔHsolvent + ΔHmix
Which of the following sets correctly shows the signs (positive or negative) of the three terms on the right hand side of the equation?
ΔHsolute > 0 (endothermic)
ΔHsolvent >0 (endothermic)
ΔHmix <0 (exothermic)
Which of the following ions will be expected to have the most negative heat of hydration, ΔHhydr?
Ca2+
The Henry’s Law constant (k) for carbon monoxide in water at 25°C is 9.71 × 10−4 mol/(L·atm). How many grams of CO will dissolve in 1.00 L of water if the partial pressure of CO is 2.75 atm?
9.71 × 10−4 mol/(L·atm) * 1.00 L * 2.75 atm = 2.67x10^-3 mol
2.67*10^-3 mol * 28g/mol = 7.48x10^-2 g CO
Soda drinks bubble when the bottle is opened because
The partial pressure of CO2 is above the solution is reduced
A saturated solution of carbon dioxide in water contains 3.00 g of CO2 when the CO2 partial pressure is 8.0 atm. What mass of CO2 will escape if the partial pressure is lowered to 3.2 atm?
(3.00g * 1 mol/44 g)/8.00 atm = Kh
Kh=.0085
mol CO2 (DISSOLVED)= .0085 * 3.2 atm= 1.2g CO2 dissolved
3.00 g CO2-1.2g CO2 (dissolved) = 1.8 g CO2 escapes
Calculate the molarity of a solution prepared by diluting 1.85 L of 6.5 M KOH to 11.0 L
(1.85 L)*(6.5 M) /11 L = 1.1 M
What is the molality of a solution prepared by dissolving 86.9 g of diethyl ether, C4H10O, in 425 g of benzene, C6H6?
2.76 m
The solubility of the oxidizing agent potassium permanganate is 7.1 g per 100.0 g of water at 25°C. What is the mole fraction of potassium permanganate in this solution?
0.0080
0.0449 mol KMnO4
100 g H20/18g H2O/1 mol H2O = 5.55 mol
Total mol soln = 5.55+0.0449=5.6 mol soln
mol fraction KMnO4 = 0.0449/5.6 = 0.0080
Children under the age of 6 with more than 0.10 ppm of lead in their blood can suffer a reduction in I.Q. or have behavior problems. What is the molality of a solution which contains 0.10 ppm of lead?
4.8x10^-7m
.1 Pb/207.2 g Pb/1mol Pb =4.826 x 10^-4
4.826x10^-4 /1x10^6 = 4.826x10^-10
4.826x10^-10 * 1x10^3 = 4.826x10^-7 m
Colligative properties depend on
The number of particles dissolved
From the following list of aqueous solutions and water, select the one with the highest boiling point.
0.75 m CuCl2
Dissociates into 0.75 mosm Cu2+, 1.5 mosm Cl-
i=3
From the following list of aqueous solutions and water, select the one with the lowest freezing point.
0.75m (NH4)3PO4
i=4 (3 NH4+ and 1 PO4 3-)
Calculate the freezing point of a solution made by dissolving 3.50 g of potassium chloride (ℳ = 74.55 g/mol) in 100.0 g of water. Assume ideal behavior for the solution; Kf = 1.86°C/m.
-1.75 C
3.50g KCl/74.55 g/mol = 0.0469 mol KCl
m=0.469 mol KCl/.1 kg water = 0.469
i=2 (dissociates into K+ and Cl-)
Kf=1.86 C/m
Delta Tf= iKf m
Delta Tf= (2)(1.86)(0.469)