Metal and Ligand Coordination Preference Pt2 Flashcards
There are few examples of supramolecular complexes formed from d⁰ to d⁴ metal ions compared to many examples from d⁵ to d¹⁰ ions
What are the reasons for this?
- The Irving Williams series: metal-ligand coordination strength is weaker in the early d-block due to the larger size of metal ions and so complexes are less stable
- Early in the d-block, the d-orbitals are higher in energy and so match less well with the energy of the ligand orbitals for covalent bonds (note some early d metal ions have no d-electrons, e.g. Sc³⁺, Y³⁺)
- Some metals form oxo ions e.g. VO₂⁺ for Vandium(V) and VO²⁺ for vanadium (IV) and this makes it more difficult to form larger coordination complexes
What factors affect whether a metal complex is high spin or low spin
d⁵ metals can be high spin or low spin meaning?
Can have pair or unpaired electrons
Mn(II) and Fe(II) are the most common example of d⁵ complexes
What are these metals like?
- These ions are both relatively hard therefore like hard ligands, like anionic oxygen ligands
Why is a high spin configuration partictuarly favoured with d⁵
As it has the maximum amount of exchange energy energy due to having five paired electrons
Hence losts of complexes are
Fe(III) form a ….. complex with strong field ligands?
low spin
d⁶ can be high spin or low spin meaning…
can have 3 or 1 paired electrons
why is low spin more common in d⁶
Which d⁶ elements are always low spin?
Because the low-spin orientation has the maximum amount of crystal field stabilisation energy possible
4d and 5d elements
Fe(II) can be high spin or low spin depending on…
…whether the ligand is a weak or strong field ligand
What types of ligands do d⁶ metals bind to?
These metal ions are softer and prefer nitrogen donors (such as pyridines) and phosphines - tend to be neutral donors
Why are d⁷ a little more complex?
- Ions with a d⁷ configuration can for 4, 5 and 6-coordination complexes in a range of geometries and so are difficult to predict. Octahedral is a good first guess
- Also all paramagnetic as has an odd number of electrons
- [Co(OH₂)₆²⁺ + 4Cl⁻ → [CoCl₄]²⁻ + 6H₂O
- e.g. Co(II) changes geometry during this reaction
d⁸ metals on the other hand are very predictable because…
- With the exception of Ni(II), these are almost exclusively square planar
- This is because in the square planar geometry all the low energy orbitals are filled and the high energy dx²-y² is vacent
- e.g. Ni(II), Pd(II), Pt(II), Rh(II), Ir(I)
Why is Ni(II) the exception in d⁸ complex?
- Ni(II) is a 3d metal and therefore had a low Δo
- It can for 4-coordinate high spin tetrahedral complexes with weak field ligands
- and 4-coordinate square planar complexes with strong field ligands
- BUT also forms 6-coordinate octehedral complexes and some 5-coordinate complexes too
Cu(Ii) is a d⁹ metal which forms octahedral complexes that have…
- a Jahn-Teller Distortion (usually an axial elongation
- This lowers the overall energy of the electrons (2 in the dz² fall in energy and only 1 in the dx²-y² rises in energy)
What are the properties of a d¹⁰ metal?
- There is now a filled d shell, the d-electron count no longer affects the geometrical preferences
- It makes these species diagmagnetic
- e.g. Cu(I), Ag(I), Au(I), Zn(II)
Cu(I) prefers…
… tetrahedral coordination