Memorization Flashcards
20
1
21
2
22
4
23
8
24
16
25
32
26
64
210
1024
100
1
101
10
102
100
103
1,000
104
10,000
105
100,000
106
1,000,000
10-1
0.1
10-2
0.01
10-3
0.001
√2
1.4
√3
1.7
√5
2.2
22
4
32
9
42
16
52
25
For any set of consecutive integers with an odd number of terms, the sum of the integers is always a multiple of the number of terms. For example, the sum of 1, 2, and 3 (three consecutives – an odd number) is 6, which is a multiple of 3. For any set of consecutive integers with an even number of terms, the sum of the integers is never a multiple of the number of terms. For example, the sum of 1, 2, 3, and 4 (four consecutives – an even number) is 10, which is not a multiple of 4.
The result is consistently odd, but does this hold for all perfect squares? Yes. When factored into pairs, one pair in a perfect square is always a number times itself. The existence of this “identical pair” will always make the number of factors odd for any perfect square. Any number that is not a perfect square will automatically have an evennumber of factors. Statement I must be true.
The sum of a set = (the mean of the set) × (the number of terms in the set)
