Memorization

Question 1

2⁰

Answer 1

1

Question 2

2¹

Answer 2

2

Question 3

2²

Answer 3

4

Question 4

2³

Answer 4

8

Question 5

2⁴

Answer 5

16

Question 6

2⁵

Answer 6

32

Question 7

2⁶

Answer 7

64

Question 8

2¹⁰

Answer 8

1024

Question 9

10⁰

Answer 9

1

Question 10

10¹

Answer 10

10

Question 11

10²

Answer 11

100

Question 12

10³

Answer 12

1,000

Question 13

10⁴

Answer 13

10,000

Question 14

10⁵

Answer 14

100,000

Question 15

10⁶

Answer 15

1,000,000

Question 16

10^-1

Answer 16

0.1

Question 17

10^-2

Answer 17

0.01

Question 18

10^-3

Answer 18

0.001

Question 19

√2

Answer 19

1.4

Question 20

√3

Answer 20

1.7

Question 21

√5

Answer 21

2.2

Question 22

2²

Answer 22

4

Question 23

3²

Answer 23

9

Question 24

4²

Answer 24

16

Question 25

5²

Answer 25

25

Question 27

For any set of consecutive integers with an odd number of terms, the sum of the integers is always a multiple of the number of terms. For example, the sum of 1, 2, and 3 (three consecutives – an odd number) is 6, which is a multiple of 3. For any set of consecutive integers with an even number of terms, the sum of the integers is never a multiple of the number of terms. For example, the sum of 1, 2, 3, and 4 (four consecutives – an even number) is 10, which is not a multiple of 4.

Question 28

The result is consistently odd, but does this hold for all perfect squares? Yes. When factored into pairs, one pair in a perfect square is always a number times itself. The existence of this “identical pair” will always make the number of factors odd for any perfect square. Any number that is not a perfect square will automatically have an evennumber of factors. Statement I must be true.

Question 29

The sum of a set = (the mean of the set) × (the number of terms in the set)