Membrane Proteins - Andrew Hitchcock Flashcards

1
Q

Why is photosynthesis a crucial area of study?

A
  • O2 is essential for life on earth, oxygenation of atmosphere by cyanobacteria allowed for evolution of aerobic organisms and complex multicellular life.
  • It helps maintain the CO2/O2 balance of the biosphere.
    -Need for more food and energy with less CO2 emissions.
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2
Q

What are the 4 main steps of photosynthesis?

A
  • Light harvesting and energy transfer by antenna complexes within the antenna network
  • Primary electron transfer at photosynthetic reaction centre, upon uptake of harvested excitation energy this drives the charge separation of a pair of redox active chlorophyll molecules causing an electron transfer that results in the reduction of a quinone to a quinol.
  • The reduced quinones produced by the reaction centre migrate to Rieske/cytochrome B complex (BC1 or B6f) The reoxidising of the quinols is coupled with the generation of a PMF.
  • The PMF is used to drive ATP synthesis by ATP synthase.
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3
Q

What do the light dependent reactions of photosynthesis involve?

A

The light reactions of photosynthesis use light and H2O to phosphorylate ADP and reduce NADP+ to produce NADPH and ATP

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4
Q

Where do the light dependent reactions take place?

A

The thylakoid membranes

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5
Q

What are the light independent reactions?

A

Reactions of the Calvin cycle to produce a range of carbohydrates (fixing atmospheric CO2 to produce sugar molecules)

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6
Q

Where do the light independent reactions take place?

A

The stroma

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7
Q

Why are cyanobacteria thought to be evolutionary precursors to chloroplasts?

A

They perform photosynthesis in a very similar way, and-so are thought to have been incorporated into eukaryotes by endocytosis.

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8
Q

How are light harvesting membrane systems specialised for light harvesting? (thylakoid)

A

Thylakoid membranes stake into Grana, these are connected by stromal lamellae (unstacked thylakoid membranes) -> these stacks maximise the surface area of the light harvesting membrane to maximise space for components of the ETC.

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9
Q

Process of the linear electron transport chain following excitation of photosystem 2?

A

takes in light and H2O -> produced PQH2 (plastoquinol) are reoxidised by Cytochrome b6f, in turn Plastocyanin is reduced in the thylakoid lumen -> Pc donates an electron to PSI -> PSI uses this electron and harvest light to reduce ferredoxin -> which then via Fd-NADP+ reductase reduces NADP+ into NADPH which is fed into the Calvin cycle.

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10
Q

What is the key side product of the light reaction of photosynthesis?

A

Oxygen, from the splitting of water by oxidation.

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11
Q

How many bacterial phyla contain chloro-phototrophic members?

A

8

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12
Q

What phylum are purple bacterium in?

A

Proteobacteria

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13
Q

Advantages of using purple bacteria?

A
  • Easy to grow in large volumes
    -Most metabolically versatile organisms on the planet
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14
Q

How do purple bacteria adapt to low oxygen conditions?

A

Under oxygen tension and the presence of light, they switch to photosynthetic metabolism, producing densely pigmented membranes (chromatophore) not dissimilar to thylakoids.

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15
Q

What are the two main intracytoplasmic membrane architectures in purple bacteria?

A

Lamellar (concentric stacks) and Vesicular (spherical membranes formed from the invagination of the cytoplasmic membrane).

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16
Q

What allows for the metabolic versatility of purple bacteria in aerobic conditions?

A

their extensive internal membrane system (known as intracytoplasmic membranes)

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17
Q

What is the function of intracytoplasmic membranes (ICMs)?

A

To increase the membrane area housing photosynthetic apparatus to enhance the amount of solar energy that can be absorbed.

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18
Q

Features of Oxygenic photosystems:

A

Two light driven reactions
Two types of reaction centre
Produces O2
Linear electron transfer
Cytochrome b6f
reduces plastocyanin
Generates PMF to drive ATP synthase
Directly reduces NADP+

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19
Q

Features of Anoxygenic Photosystems:

A

One light driven reaction
One type of reaction centre
Does not produce O2
Cyclic electron transfer
Cytochrome bc1
reduces cytochrome c2
Generates PMF to drive ATP synthase
Doesn’t directly reduce NADPH+

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20
Q

What feature of chlorophylls anchor them to complexes within the membrane?

A

long hydrophobic isoprenoid tail

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21
Q

What feature of chlorophylls is light sensitive?

A

They’re tetrapyrroles with a fifth ‘E’ ring. Upon light absorption, an electron within the conjugated pi electron system (formed by alternating double and single bonds) the tetrapyrrole is excited to a higher energy state.

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22
Q

What types of diagrams are used to show electron energy states?

A

Jablonski diagrams.

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23
Q

What is Forster Resonance Energy Transfer (FRET)

A

Non-radiative transfer of energy from an excited donor to an acceptor

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24
Q

What are the two main requirements for FRET?

A
  • There must be spectral overlap between the fluorescence emission of the donor and the absorbance of the acceptor.
  • Small distance, the energy transfer efficiency is inversely proportional to the 6th power of the distance (must be within 5nm)
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25
Q

Why do purple bacteria absorb different wavelengths of light of other oxygenic autotrophs?

A

Their bacteriochlorophyll has adapted via changes in structure and scaffold proteins to absorb light not absorbed by the cyanobacteria closer to the water’s surface.

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26
Q

Purpose of accessory light-harvesting pigments:

A

To increase the spectra of light which can be absorbed to excite the reaction centre.

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27
Q

What are carotenoids?

A

An example of an accessory light-harvesting pigment. They have a delocalised pi electron system, only capable of S0 to S2 excitation, very quickly transferring the excitation energy (due to their short excitation lifetime of 200ps)

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28
Q

What is meant by carotenoids being able to perform non-photochemical quenching (NPQ)?

A

Carotenoids perform a photoprotective function. Chlorophylls can form triplet excited states, these are long lived and can make reactive oxygen species and damage proteins -> carotenoids can accept the energy of the triplet, returning the chlorophyll’s electron to it’s ground state.

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29
Q

Why do phototrophs require an antenna system?

A
  • The pigment density of the reaction centre is low, prioritising electron transfer over light harvesting. Antenna complexes allow for a much higher pigment density than the reaction centres alone, increasing the amount of light and wavelengths that can be absorbed.
  • Without an antenna the RC would only act at ~1% of its theoretical efficiency
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30
Q

What are the properties of good antenna systems:

A
  • Wide spectral Cross-section of absorbance
  • High pigment concentration
  • Wide Spatial Cross section
  • Modular
  • Directionality
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31
Q

How do antenna systems achieve a wide spectral cross-section?

A

They use a variety of pigments (or modified forms of the same pigment) to absorb a variety of wavelengths of light

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32
Q

How do modifications to pigments alter the wavelengths they absorb?

A

Modifications to the polypeptide environments surrounding pigments affect their pi-electron system, affecting their excited state properties and therefore their absorption maxima.

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33
Q

What is meant by antenna systems being modular?

A

Antenna systems have the ability to be modulated, increasing in number per RC in low light, a decreasing in number when there’s high light intensity, where excess energy can cause damage.

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34
Q

What are the two broad classes of antenna complex?

A

Primary antenna complexes and Peripheral antenna complexes

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35
Q

Primary antenna complexes:

A

complexes directly associated with RC in a fixed arrangement and stoichiometry. Split into fused antenna and core antenna.

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36
Q

What is meant by antenna systems forming an ‘energy trap’ ?

A

The arrangement of pigments makes it unfavourable for energy to transfer from the reaction centre to the accessory pigments, thereby trapping the excitation energy.

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37
Q

Fused antenna complexes

A

Primary antenna complexes wherein RC pigments and the antenna are bound to the same polypeptide and cannot be biochemically separated

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38
Q

Core antenna complexes:

A

Primary antenna complexes wherein the RC and antenna pigments are on different polypeptides (coded by different genes) which then interact and associate with each other. These can be biochemically separated.

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39
Q

What antenna complex is an example of a core antenna?

A

LH1 in purple bacteria, wherein different constituent polypeptides associate to form a larger complex.

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40
Q

What is the role of peripheral antennas in light-harvesting systems?

A

To interact with RCs and primary antenna to increase the light-harvesting capacity of the system (in addition to the primary antenna)

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41
Q

What is the key difference between primary and peripheral antennas?

A
  • They slightly differ by function
  • Key difference is peripheral antennas don’t have a fixed physical arrangement with other antenna or the RC, having the ability to be mobile within the membrane and interact with different RC-antenna complexes.
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42
Q

What are the two types of peripheral antennas?

A

Membrane intrinsic (Non soluble e.g. LH2) and membrane extrinsic (water soluble e.g. phycobilisomes in cyanobacteria)

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43
Q

What model organism is used to study the light harvesting systems of purple bacteria?

A

Rba. sphaeroides

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44
Q

What are chromatophores?

A

Internal membrane vesicles produced by purple bacteria under anaerobic conditions, that increase the amount of membrane available for accommodating anoxygenic photosynthetic machinery. Each estimated to hold 2000 bacteriochlorophyll pigments.

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45
Q

What anoxygenic photosynthetic machinery are found in chromatophore membranes?

A

RC-LH1 core antenna complexes, LH2 peripheral antenna, Cytochrome bc1, ATP synthase

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46
Q

What are the structural effects of the addition of LH1 to RCs to form RC-LH1 complexes?

A

Increases the number of bacteriochlorophylls (BChl) from 4 to 32, and increases the area from 132nm2 to 490nm2, the pigment density increasing from 1 BChl per 33nm2 to 1 BChl per 15nm2.

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47
Q

What is the effect of LH1 association with RC in terms of functioning?

A

The physical area for light absorption is increased and pigment density is doubled, and-so the system becomes much more effective at absorbing energy from light.

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48
Q

How can the effects of antenna complexes be visualised?

A

By deconvoluting the absorption spectrum of a model organism, to visualise the contributions of different complexes to absorbance. They can be found to increase both the amount of light and breadth of the wavelengths absorbed.

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49
Q

Describe the structure of LH2 in purple bacteria

A

Basic unit: heterodimer of a and b polypeptides = ab pair
- Each ab pair binds: Bchla, Bchla dimer, and carotenoid
- 9 of these assemble to form LH2

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50
Q

How does each ab pair and associated pigments act as one single pigment?

A

The interactions between the Bchla and Bchla dimer allow energy transfer between them

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51
Q

What is the absorbance spectrum of LH2 (each pigment)

A

Bchla -> B850 ring (lowest energy)
Bchla dimer -> B800 ring
Carotenoid -> 400-550nM

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52
Q

Can energy be transferred between all of them?

A

B800 and B850 are close enough (1.8nm) for almost 100% efficient FRET
B850 are close enough to each other for delocalisation (0.9nm)
B800 are too far apart for this (2.1nm)

Carotenoid can transfer to both (0.5nm)

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53
Q

How is energy transferred?

A

Carotenoid -> B800 -> B850 (energetically downhill)

Carotenoid excited to S2, rapid internal conversion to S1
Transfers to B800 S1 in 1.6ps
Transfers to B850 S1 in 0.7ps
Rapidly delocalises around B850 in 0.1ps

54
Q

Describe LH2 and RC-LH1 arrangement in chromatophores

A

LH2 surround RC-LH1 complexes, allowing energy to be trapped at the RC
Allows even very peripheral LH2 to transfer energy to RC (~60ps)

55
Q

Why does Rba.Sphaeroides need to tune LH2?

A

Without tuning, Bchla absorbs at 771nm (needs to be at 800 or 850) so coordinate binding site

Mainly though: H-bonds to Ring E and C3-acetyl, acting as Mg ligand

56
Q

How is it tuned to B800 ring

A

B800 tuning:
- H-bonds with C3-acetyl group and b-Arg30
- Carboxyl O of N-terminal carboxy Met acts as a ligand for central Mg
- H2O H-bonds to ester O on Ring E
His22 and Asn3 form H-bond network

57
Q

How is it tuned to B850 ring

A
  • His31 and His40 forming ligands for Mg
  • Ser27 H-bonded to keto on Ring E
  • Tyr45 forms H-binds to C3-acetyl carbonyl of Bchl and with the adjacent Bchl (2x)

2 C3 acetyl H-bonds = more red shifted

58
Q

What does H-bonding to C3 acetyl groups cause?

A

More H-bonds to C3 acetyl means more red-shifted (increased nm absorbance)

59
Q

What is different about the arrangement of m.purpuratum

A

Has 7 subunits instead of 9. This increases the distance and angle between pigments
Reduces excitonic coupling and lowers H-bonding = less red-shifted at 828nm

60
Q

Describe the LHII PLANT peripheral antenna structure and energy transfer

A

Single polypeptide
Each polypeptide binds: 8 ChlA, 6 ChlB and 4 Carotenoids

Form trimers and monomers. Positioned: trimer -> monomer -> PSII core antenna -> PSII RC

61
Q

Describe energy transfer from antenna to RC in anoxygenic PSS

A
  • LH2 absorbs light energy, and internal transfer occurs
  • LH2 transfers this energy to other LH2 in 2.7ps
  • LH2 transfers to LH1 in 4.5ps which then transfers to RC in 50ps = slightly uphill so slower
62
Q

How does it make sure energy doesn’t transfer back

A

LH1 to LH2 transfer is slower making it energetically more uphill

63
Q

Describe the LH1-RC complex from Rba.sphaeroides

A

Tuned at 875nm
Each ab pair binds a Bchla dimer and are faced perpendicular to each other to allow excitonic coupling and delocalisation
14 ab pairs assemble

LH1 complex binds 2 carotenoids
Incomplete ring around RC
Held open by PufX

64
Q

what is excitonic coupling

A

If pigments are within 1nm of each other, they can acts as 1 pigment and energy delocalises around their ring in 0.1ps

65
Q

Describe the RC-LH1 dimer complex

A

S-shaped 28 subunit surrounding 2 RCs
PufX essential for dimerisation, particularly its Arg45 and Arg53 residues (mutations stop dimers)
PufX forms salt bridge at dimer interface

66
Q

What is the advantage of dimerisation

A

Curvature of 152 degrees imposed by PufX pushes on membranes, facilitating chromatophore formation
Also allows more efficient trapping - if one is busy the other can accept the energy

67
Q

How are Bacteriochlorophyll of Rba.sphaeroides coordinated for excitonic coupling

A

His from each subunit coordinating central Mg ions
H-bonds from Tryp to C3 acetyl carbonyls

These red shift absorbance (to 875) and orient them for efficient energy transfer and directionality as 875 is lower than LH1 850

68
Q

Difference between Type 1 and Type 2 RCs

A

Type 1 –> reduce Fd
Type 2 –> Reduce Quinones

69
Q

What effect does BchlB and the gamma subunit have on B.viridus

A

BchlB used over BchlA = absorb lower wavelengths (red shifts)

Extra 16 gamma subunits shift this more, from useless 972nm (wavelength of water vapour) to 1018nm
Suggests gamma was recruited by bacteria to absorb useful wavelengths

70
Q

How does an Open or Closed RC-LH1 complex affect quinone/quinol diffusion

A

Closed = diffuse through small pores in LH1 antenna. Possible as only 1 carotenoid per ab pair

Open = Some species have 2 carotenoids per pair that blocks usual pores, so structure needs to be open to allow diffusion

Shown -> PufX mutants can only grow once 2nd carotenoid removed

71
Q

Describe the structure of the Rba.sphaeroides Reaction Centre

A

3 subunits = L, M and H

L and M form heterodimer with pseudo symmetry. These bind all the cofactors. Structurally similar (like D1 and D2 of PSII RC)

H subunit has a soluble cytoplasmic domain that insulates the quinone binding sites to stop them performing unwanted redox

72
Q

Describe the ETC cofactors

A

BchlA dimer is P870 special pair

A branch (L):
BchlL–> BpheL –> Qa

B branch (B):
BchlM –> BPheM –> Qb
Carotenoid for photoprotection

Fe at the top for stabilisation

Asymmetrical so e- transfer up L branch only

73
Q

Describe the electron transfer chain

A
  1. P870 excited and becomes very reducing
  2. Moves e- to BChlL ad BPheL in small downhill energy drops (favoured)
  3. e- to Qa in big energy drop then to Qb in more favourable one
  4. This separates e- from P870 sink on another side of the membrane
  5. during this, reduced Cyt2 donates an e- to RC to reset it
  6. This repeats until Q fully reduced to QH2
74
Q

How is recombination prevented

A

FRET efficiency decays to 1/6th distance so cannot transfer straight back
Electron transfer efficiency decays with the square of the distance

Forward reactions are faster than recombination due to Marcus Inverted Theory = many small steps faster than one fewer big steps

75
Q

Why is distance between RC and LH1 seen as a compromise

A

Distance created to make transfer: Fast enough for general efficiency but purposefully slower so RC doesn’t get over excited and form toxic triplets

76
Q

How and why is triplet formation prevented

A

If e- stalls at BPhe then it recombines with excited P870* and forms triplet state. Relaxation of this forms singlet O that damages RC in 30 mins

  1. Big uphill energy gap from Qa to BPhe means more likely to safely recombine with P870+ instead
  2. Carotenoids help photoprotection through NPQ (non-photochemical quenching) -> quench BChl triplets that form
77
Q

What is the role of PSII

A

Using light energy to couple oxidation of 2 H2O to reduction of 2 PQ

78
Q

What is the Oxygen Evolving Complex. Where is it and how does it work

A

Catalyses oxidation of water
Sits outside membrane on lumenal surface of PSII
D1 side
Sits next to TyrZ to funnel e- back into special pair

79
Q

How does P680 and H2O/O2 potential change?

A

P680 becomes very oxidising (+1200mV to -630mV)
H2O becomes oxidised (+820mV to ??)

80
Q

Describe PSII structure from Cyanobacteria T.vulcanus

A

Symmetrical dimer
Much more complex than PSI

  • D1 and D2 subunits form heterodimeric RC core
  • CP43 and CP47 are core antenna (bind RC and introduce carotenoids and chlorophyll in)
  • PsbO ( and PsbU and PsbV) is extrinsic in membrane, and stabilises OEC and Mn cluster
81
Q

Describe the PSII ETC structure in cyanobacteria T.vulcanus

A

Same pseudo symmetry to purple bacteria
A branch: D1 side
B branch: D2 side

ChlA dimer special pair (P680)
A –> ChlD1 –> PheD1 –> PQA
B –> ChlD2 –> PheD2 –> PQB

Non-heme Fe at the top
Carotenoids and peripheral Chlorphylls on each branch to help get energy in

TyrZ and Mn cluster om D1 side to reconcile charge separation

82
Q

Describe the electron transfer steps

A

((Only branch A active, like purple bacteria))
1. P680 excited, e- moves to PQA then PQB = substrate binding site
2. Forms semiquinone (only 1 e- bound)
3. Electron hole at P680 filled by TyrZ donating e-
4. TyrZ re-reduced by Mn cluster (many oxidation states)
5. Reset to repeat again

The PQH2 moves to Cytb6f

83
Q

Describe PSII energetcics

A

Redox cofactors are very close together (less than 1.4nm) with small downhill steps –> recombination much much slower than forward

84
Q

Why is PSII energy squeezed?

A

Needs to reduce PQ and oxidise water together so it cannot afford the big energy gap between Phe and QA

85
Q

Why can PSII not prevent triplet formation

A

No big energy drop means no safety mechanism
some electrons transfers back meaning PSIII RC needs to be replaced every 30 mins

Carotenoids perform NPQ to photoprotection

86
Q

What’s the midpoint difference of Redox potential between PSII and RC in purple bacteria? what’s the importance

A

P680 (PSII) special pair starts with more (+) oxidising redox than PB P870 as it needs to oxidise H2O (PB cannot as P870 is less (+) than H2O)

But P870* reaches a more (-) reducing redox than P680. This makes its potential difference between UQ 0.8V instead of 0.5V for P680 and PQ

This bigger difference makes it harder for back reaction to occur

87
Q

Give general Z scheme of PSII -> Ctyb6f –> PSI

A

PSII generates reducing P680* to take e- from water
This donates 2e- to PQ to reduce it.
PQH2 moves to Cytb6f to be regenerated into PQ
PQ oxidation coupled to PC reduction

PSI oxidises PC to generate very reducing P700* to reduce Fd
FNR couples Fd oxidation to NADP+ reduction -> NADPH

88
Q

Describe PC structure and redox reactions

A

Small, soluble
Has a Cu atom that can be +1 or +2 to change oxidation state

Reduced by Cytb6f, oxidised by PSI

89
Q

Describe Fd structure and redox reactions

A

2Fe2S cluster coordinated by 4 Cys residues
Fd reduced by PSI then oxidised by FNR

90
Q

How does FNR link Fd oxidation with NADPH generation

A

Serves as a converter –> Fd only transfers 1e- at a time, but reducing NADP+ needs 2e-

Uses Flavin cofactor that can be in different reduced states (like quinones forming semi quinones)

91
Q

Describe the structure of PSI monomer in Cyanobacteria

A
  • PsA and PsaB –> core RC subunits form asymmetrical heterodimer. Core antenna fused to core RC
  • PsaC –> binds remaining e- acceptors. mediates electrostatic interactions with Fd
  • PsaF –> subunit extends into lumen and mediates PC interactions
  • PsaL –> important for oligomerisation

Spatial segregation = allows energy transfer in but not electron transfer out

92
Q

Why and how do some cyanobacteria species form oligomers?

A

Monomers, trimers, tetramers, oligomers …
Difference in bulkiness of PsaL sidechains allow different oligomers to form

Form to fit more membrane in and help with excitation sharing most likely

93
Q

What PSI form do plants/Eukaryotes usually take.

A

monomeric PSI. Usually forms supercomplex with LHC1

94
Q

Why can they not form oligomers

A

Cannot oligomerise due to extra subunit: PsaH that prevents it.
Tend to like to coat PSI in more antenna than anoxygenic does, meaning monomeric structure better for them

95
Q

Describe the PSI-Fd complex that forms

A

Interactions mediated by electrostatic interactions:
PSa,c,d,e, and f subunits of PSI have (+) patches corresponding to Fd’s (-) patches

96
Q

Describe the PSI-PC complex that forms

A

Interaction relies on hydrophobic interactions with PsA and PsB on PSI

97
Q

Why do these complexes need to form?

A

To allow quick docking and dissociation to allow PC and Fd to move between complexes

98
Q

Describe the PSI electron transfer system

A

Have B and A branch (other way round)
P700 special pair –> chlorophyll –> chlorophyll –> Plastoquinone –> Fx –> Fa –> Fb (FeS clusters)

Electrons donated from Pc docking (fills e- hole)
Reduced Fd

99
Q

What is different about this pathway?

A

e- transfer can proceed up either branch because electron doesn’t need to be held somewhere = no 2e- gate needed (Fd only takes 1e-)
Both pathways intersect at Fx

100
Q

How are the A and B branches tuned to give slightly different redox potentials. Why?

A

PQ potentials are tuned slightly different. A branch tuned to minimise triplet formation

B branch given slightly less driving force = step from Chlb –> PQb is quicker than A (smaller difference) but the next step to Fx is slower (bigger difference)

This means if e- stuck at Fx, it will travel down the A branch more readily as it is energetically downhill = quicker. A-branch is less likely to form triplet as recombination now is quicker than the back reaction.

101
Q

Why is cyclic electron transfer needed in oxygenic PSS

A

Linear chain only makes 1.28:1 ATP:NADPH ratio but needs to make this 1.5:1 for Calvin cycle

Need to make ATP without making NADPH

102
Q

Describe the 2 mechanisms of cyclic e- transfer

A
  1. PGR5 docks e- from Fd/FNR on to Cytb6f to generated PQH2 and make PC
  2. Photosynthetic complex 1 (added into membrane when needed). Uses e- from Fd/FNR to generate PQH2 and make PC
103
Q

Give an example of a homo-dimeric Type 1 RC

A

Heliobacteria, green sulphur

104
Q

Describe their structure

A

P800 special pair
Uses Bacteriochlorophyll G
Single Fx FeS cluster
No Quinone/Plastoquinone (e- goes straight from Chl to FeS)

105
Q

How are these thought of evolutionarily?

A

Thought that duplication of ancestral homo-dimeric genes, then divergence of these genes from one another lead to formation of heterodimeric RCs

106
Q

What are the key components of the mitochondrial ETC?

A

Complex I –> NADH ubiquinone oxidoreductase
Complex II –> succinate ubiquinone oxidoreductase
Complex III –> cytochrome bc1
Complex IV–> cytochrome c oxidase
Complex V –> ATP synthase

Succinate to Fumarate oxidation
Cytochrome C
Quinones/quinols

107
Q

Describe the role and structure of mitochondrial complex I

A

Feeds NADH into Krebs cycle and adds to PMF
- Large 1000kDa
- 45 subunits
- 2 major domains:

  1. hydrophilic arm extending into matrix that binds NADH and cofactors
  2. Long membrane domain anchoring complex containing 4H+ pumps
108
Q

What are MCI’s electron transfer cofactors? How and where do they act

A

1 FMN and a wire of 7xFeS clusters on the arm domain

FMN accepts 2e- from NADH and transfers them down the clusters in the arm to Ubiquinone reduction site
UQ –> UQH2

Pumps 4H+

109
Q

What is Photosynthetic complex 1?

A

PhS1 = NADPH dehydrogenase added into membrane when cyclic transfer is needed (making ATP not NADPH)

Re-oxidises 2 Fd (using 4xFeS clusters) by reducing PQ and pumps 4H+ across membrane

110
Q

How do PhS1 and MC1 compare?

A

Similar:
Both use FeS clusters to reduce a quinone
Share 11 core subunits

Different:
Have complexes specific to each other (oxygenic specific, Fd or NADH specific)
PsC1 cannot bind NADPH so binds Fd instead
PsC1 has a shorter arm domain

111
Q

Describe the role of Mitochondrial Complex III

A

Key players = Rieske, CytC and CytB
Always dimeric
Re-oxidise quinols, move H+ and create soluble e- carriers

112
Q

What are respirasomes

A

Complex III, I and IV can form this to make it easier to pass molecules between them, and helps with membrane packing

113
Q

Describe the structure of MCIII from purple bacteria

A

Symmetrical dimer
3 key subunits:
- CytB
- Rieske FeS protein (ISP)
- CytC

Each monomer has 3 core subunits and 2 independent Quinone/Quinol binding sites

114
Q

Describe the structure of Photosynthetic Complex III (Cytochrome b6f)

A

Dimeric with 4 core subunits
Each monomer has 2 PQ/Q binding sites

Main subunits:
- Cytb6
- Subunit 4
- Rieske ISP
- CytF
- Pet G,L,M,N

115
Q

Compare both Complex III’s

A

Cytb6 + subunit 4 (Photosynthetic) are homologous to Cytb (mitochondrial) with one less TM

Both have helix and extrinsic domains of subunits swapped between 2 monomers to allow Rieske to interact with CytB and CytC1

116
Q

Compare the redox factors of Cytbc1 and Cytb6f

A

Cytb6f has an addition C haem

117
Q

How does Cytb6f coordinate Rieske FeS clusters differently to Fd? Why?

A

Unusual cluster ligation = gives it a more (+) redox value
Coordinates with 2xHis and 2xCys instead of 4xCys

Changes redox from -430mV to +300mV to allow it to strip electrons from quinones

118
Q

Describe the process of the modified Q cycle of CtyBc1

A

Showing e- transfer of just one subunit:
- 2xQH2 arrive at Qo (oxidation) site
- 4e- released (and 4H+ moved to lumen)–> 2e- go down high redox cofactor chain and 2e- go up low potential redox chain

  • HPC = Qo –> FeS cluster in Rieske –> Cyt1 –> reduces 2xCytC2
  • LPC = Qo –> CytbL –> CytbH –> Qi (inside) –> reforms 1xQH2 (takes up 2H+)
119
Q

Describe the movement of H+ and how many protons moved per Q

A

Oxidising 2xQH2 moves 4H+ into the lumen
Reforming one molecule of QH2 takes out 2 H+ from cytoplasm

This means for each 2 quinols oxidised, one is remade = doubles the number of protons translocated per quinol oxidised

120
Q

Why does the Rieske subunit move?

A

When Q is at Qo site it is close enough to FeS cluster for e- transfer but the FeS is too far away to C1 (heme) for e- transfer

Rieske subunit uses a hinge region to move move the FeS cluster closer to C1 for quick e- transfer

121
Q

What are plant chloroplasts organised into in higher plants

A

Interconnected stacks of thylakoid membranes: grana lamellae
Connected by non-stacked membranes: stroma lamellae

122
Q

What is the function of arginine residues in the alpha subunits in F0 of ATP synthase?

A

Has an amine froup that can bind to protons, when in proximity to a glutamate it stabilises it, allowing for it to deprotonate the glutamate, allowing for the release of protons in the low high pH region.

123
Q

What process is coupled in the F0 region of the ATP synthase?

A

the resolving concentration gradient with the generation of torque.

124
Q

What is the difference between a and b subunits on ATP synthase?

A

They are structurally similar however only B units are catalytically active.

125
Q

What are the 3 conformations of Beta subunits on F1 head of ATP synthase?

A

Open, Tight, and Loose.

126
Q

What subunits form the F1 head of atp synthase?

A

3 alpha and 3 beta subunits.

127
Q

What is the gamma subunit of ATP synthase?

A

The central shaft that transmits toque from F0 to F1, changing the conformation of the beta subunits.

128
Q

What is the difference between a and b subunits on ATP synthase?

A

They are structurally similar however only B units are catalytically active.

129
Q

What residue of the C ring of ATP synthase bind to the H+ ions ?

A

Glutamate residues

130
Q

What are the components of ATP synthase?

A

A subunits, 8-15 c subunits, Y subunit, 3 alpha, 3 beta subunit, Beta 2 and sigma subunits