Meet the Lanthanides 2 Flashcards
What are the magnetic properties of any ions the combination of contributions from
- Spin and orbital angular momenta
What happens to orbital angular momentum in first row transition metals
- Orbital angular momentum often removed or partially quenched by interaction of the ligands with the partially occupied d orbitals
- Often (not always) correspond to spin only formula
What is the spin only formula
- Ueff= root(n(n+2))
- n=number of unpaired electrons
What is the electronic structure of lanthanide ions governed by
- Very large spin-orbit coupling characteristic of high Z
- means you can’t treat spin and momentum separately - Very small crystal-field splitting (contracted f orbitals)
- no partial quenching from ligands
What is the Russell-Saunders coupling scheme
- Because 4f orbitals have limited radial extension and are core like
- They have little role in bonding- the orbital angular momentum is not quenched
- Magnetic properties of the Ln3+ ions are very well described from the coupling of spin and orbital angular momenta
What does the Russell-Saunders coupling scheme assume
- Spins of the electron couple - total spin angular momentum (S)
- Orbital momenta also couple- total orbital angular momentum (L)
- Totall angular momentum, J, of the system is given by coupling of S and L
What is the typical Ln3+ spin orbit coupling in comparison to ligand field effects and what is the result of that
- Typically large (1000cm^-1)
- In comparison to ligand field effects (100cm^-1)
- As a result only the ground J-state is populated
- magnetism is essentially independent of environment.
- Thus we only need to know the ground state of an Ln3+ ion to predict and understand its magnetic and spectroscopic behaviour.
How are atomic or ionic energy levels defined
- By a term symbol (2S + 1)LJ
- Ground state term symbol contains all the information needed to calculate U for a Ln3+ complex
Describe the magnetism of Ln3+ ions
- arises from presence of unpaired 4f electrons
- Magnetic moments of Ln3+ complexes are little affected by the ligand environment- so similar to those calculated for the free ions
- Inherently very high magnetic moments
What is the Russell-Saunders approach to magnetism
- Spin-orbit coupling splits the atomic or ionic term into a series of J levels
- Spin-orbit coupling is so large that the excited levels are inaccessible and the magnetic moment is determined by the ground state of the ion
- The magnetic moment of a J-state is expressed by the Lande Formula
What is the Lande Formula
- Uj= g root(J(J+1)) where:
- g=3/2 + S(S+1)-L(L+1)/2J(J+1)
Why is there no observed magnetic moment for Pm
- It too radioactive
Do the calculated magnetic moment show a good agreement with experimental
- Yes
- Except Sm3+ and Eu3+
Why do Sm3+ and Eu3+ magnetic moment values not show good agreement with experimental
- Both ions have excited states close in energy to the ground term to be thermally accessible and contribute to the observed magnetic moment
- Low lying energetic states- different magnetic moments contributing to magnetic moment
What does Sm3+ and Eu3+ magnetic moments mean for dependence on other factors
- Low lying energetic states leads to temperature dependence
- The observed moments at RT decreases as the temperature is lowered
- Thermally populated as governed by the Boltzmann distribution
- Excited states are closer than KT (around 200cm^-1 which is RT)
Why is Eu expected to not have magnetic moment
- Ground state term- 7F0
- 0 in J state
- Orbital and spin angular momentum should cancel out