Measurement of Absorbed Dose Questions & Answers Ch 6 Flashcards
The roentgen is not defined above what energy?
3 MeV
The SI unit for absorbed dose is what unit and what is its definition?
Gray, Gy, 1 Gy = 1 Joule/kg = 1 J/kg
What is the conversion between joule and ergs, and what is the definition of a rad? What SI unit is
used in place of the rad?
1 J = 107 ergs, 1 J/kg = 1 x 107 ergs/1,000 gm
1 J/kg = 1 x 104 ergs/gm
(1 x 104 ergs/gm-Gy) / (100 ergs/gm-rad) = 100 rads/Gy
Why is absorbed dose used in radiation oncology rather than some other unit?
Because biological effect is a function of the absorbed dose
In terms of charge and mass how is exposure defined?
Exposure = (charged collected in air) / (mass of air)
1 Roentgen, R = 2.58 x 10-4 C/kg
Exposure can only be measured when what state of affairs exists in volume of matter dm?
Electronic Equilibrium
What is the definition of exposure in terms of dQ, Charge, and dm, Mass?
X = dQ/dm
What is the mean energy in eV required to create an ion pair in air, W/e?
33.97 eV per ion pair
Define the mean energy de/dm in a mass of air using dQ, dm and W/e where dQ is the charge
liberated, dm is the mass of air, and W/e is the average energy in eV required to produce an ion pair in
air?
De/dm J/kg = (dQ/dm C/kg) (W/e J/C)
Define Da the absorbed dose per unit mass of air using X the exposure.
Da = X x W/e
Is the absorbed dose per unit exposure a constant for air at all energies and if so, why?
Yes, because W/e is a constant. This is probably not strictly true at very low photon energies
which are of little interest in radiation oncology measurements.
. What is the absorbed dose per R for air in today’s units?
Da = J/kg = X (R) x 2.58 x 10-4 (C/kg)/R x 33.97 J/C
0.876 x 10-2 [(J/kg) /R] x R
1 rad = 0.01 J/kg
Da = 0.876 (rad/R) X(R)
Given an exposure of 3 x 10-3 C/kg, what is the dose in rads to air, dose in cGy, and
dose in Gy?
3 x 10-3 (C/kg) / 2.58 x 10-4 C/kg-R = 11.63 R exposure
Da = 11.63 R x 0.876 rad/R = 10.19 rad or cGy
Da = 10.19 cGy x 0.01 Gy/cGy = 0.102 Gy
What conditions must be present in order to calculate the absorbed dose in a medium
at a point from the energy fluence in Gy/m2 and the mass energy absorption coefficient in
m2/kg?
Charged particle or electronic equilibrium must exist
Using the average energy to create an ion pair in air in J/C and the R in C/kg, what is
the average energy per kg of air absorbed for 1R? Under what conditions is this true?
2.58 x 10-4 C/kg x 33.97 J/C = 0.00876 (J/kg) /R
In using Thimble chambers, what removes the perturbing effect of the chamber?
The calibration number derived by the calibration lab
What is the purpose of the build-up cap on the thimble chamber?
To establish electronic equilibrium in the volume of the chamber
In the megavoltage x-ray range, the roentgen to rad factor primarily varies with what
quantity?
Number of electrons per gram, primarily because of Compton effect