*Matrizenaufgaben (Muster erkennen/Symbolreihen/Figurenreihen) Flashcards

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d

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E

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10
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b

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11
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b

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12
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Schwierig.

Aber wenn man sich die erste Reihe anschaut: bei Bild 1 findet sich ein rechter Winkel, beim 2 nicht, beim 3 gibt es einen rechten Winkel, beim 4. nicht, beim 5 wieder einen.

  1. Ziele 1. Bild keinen, 2. hat einen, 3. hat keinen etc…

? darf keinen rechten Winkel enthalten… B

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13
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14
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15
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C

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16
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8

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17
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18
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a

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19
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7

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20
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21
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22
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8

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23
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b

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24
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4

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25
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26
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9

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27
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3

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28
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29
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30
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d

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31
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32
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33
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34
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g

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35
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36
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3

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37
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38
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39
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b

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40
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e

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41
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42
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43
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D

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44
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45
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4

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46
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a)

Immer Spaltenweise ansehen: 1. Spalte+2.Spalte +4. Spalte ergibt die 3. Spalte.

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47
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48
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2

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49
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8

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50
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4

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51
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52
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e

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53
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e

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54
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G

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55
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5

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56
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5

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57
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d passt nicht

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58
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d

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59
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9

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60
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B

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61
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62
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63
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d

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64
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6

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65
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c

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66
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F

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67
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1

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68
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1

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69
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a

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70
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d

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71
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72
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6

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73
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e

Rechts und links immer drei Kreise/Quadarte.

Stern in erster Zeile wandert, auch das Herz in der 2. Zeile, und in der 3. Zeile der Kreis ebenfalls.

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74
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75
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76
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A

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77
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78
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c:

  1. Spalte + 3. Spalte = 2. Spalte
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79
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4

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80
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7

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81
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e

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82
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83
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e:

Stäbchchen: zwei nachrechts zwei nach links = neutral.

andere linksorientiert…

wechselt sich ab

n = neutral

l = linksorientiert

r = rechtsorientiert

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84
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b

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85
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e

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86
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87
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88
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89
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g

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90
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b

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91
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b

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92
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93
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c

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94
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95
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E

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96
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Achtung: jedes Dreieck braucht man 3x… somit ist es nicht das Dreieck nach oben, weil das gibt es ja schon 3x (im Gesamtbild), sondern das Dreieck nach unten, denn das gibt es nur 2x

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97
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9

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98
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b

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99
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A

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100
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b

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101
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102
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c

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103
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104
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5

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105
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2

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106
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4

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107
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e

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108
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b

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109
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h

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110
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c

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111
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112
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a

Weil 1. Spalte + 2. Spalte (was fehlt)

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113
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4

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114
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e

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115
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116
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117
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a

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118
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119
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6

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120
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c

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121
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122
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b

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123
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e

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124
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5

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125
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126
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B
keine tolle Anordnung - fast alles willkürlich.

Dreiecke immer rechts unten in den Ecken

Überall ein Quardrat drinnen.

Und die Kombi aus Dreieck rechts unten und Quadrat im Bild ergibt auch schon die Lösung, weil alle anderen Bilder können es nicht sein.

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127
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3

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b

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131
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132
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f

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e

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140
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e

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a

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Antwort E

Also bei dem musst du darauf achten, ob ein rechter Winkel vorhanden ist 😊. In jeder Zeile ist bei jeder zweiten Figur ist einer vorhanden. Nur das die erste und dritte mit einem rechten Winkel beginnen und die zweite nicht. Das heißt du suchst bei der Lösung ein Bild ohne rechten Winkel.

Also in diesem Fall wäre es E

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e

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d

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b

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a

192
Q

Sudoku Prinzip, Ausschluss, Diagonale kaum, immer alle Figuren 3x zb

A
193
Q
A

a

194
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A

f

195
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A

c

196
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A
197
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A

C

198
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A

2

199
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A
200
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A
201
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A

2

202
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A

c

203
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A

8

204
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A
205
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A

6

206
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A
207
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A
208
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7

209
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A
210
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5

211
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A

d

212
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2

213
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A
214
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A
215
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A

e

216
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A

4

217
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A

5

218
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A

5

219
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A

c

220
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A
221
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A
222
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A
223
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A

c

224
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A
225
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A

8

226
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A

2

227
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A
228
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A

5

229
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A
230
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A

c

231
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A

7

232
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A

8

233
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A
234
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A

c

235
Q
A
  1. Zeile über die 2. Zeile legen = kommt 3. Zeile raus

wir müssen nur: die schwarzen Linien doppel elimieren sich. Bei den weissen Linien ist es ungekehrt: nur die die sich überlagern bleiben.

236
Q
A

e

237
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A
238
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A
239
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A
240
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A

b

241
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A

5

242
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A
243
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A

3

244
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A

b

245
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A

c

246
Q
A

6

247
Q
A
248
Q
A

a

249
Q
A

7

250
Q
A

G

Weisse und schwarze Punkte getrennt voneinander anschauen.

Spaltenweise in Summe müssten es immer 5 weisse Punkte sein.

Für die schwarzen Punkte von links nach rechts schauen: nur jene schwarzen Punkte überleben für die 3. Spalte, die auch in der 1. und 2. Spalte vorhanden sind.

251
Q
A

E

252
Q
A
253
Q
A

a

254
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A

8

255
Q
A
256
Q
A

b

257
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A
258
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A

i

259
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A

3

260
Q
A

8

261
Q
A

3

262
Q
A

8

263
Q
A

8

264
Q
A
265
Q
A

Diagonalen anschauen:

In Diagnoale Mitte immer Strich nach unten…

rechts und links davon die Diagonale hat Diagonalen Strich und ganz aussen immer Waagrecht. Somit kann nur Stich nach unten sein.

266
Q
A

d

267
Q
A
268
Q
A
269
Q
A

a passt nicht

270
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A

b

271
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A

6

272
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A

5

273
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A

f

274
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A

A

275
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A

e

276
Q
A
277
Q
A
278
Q
A

4

279
Q
A

8

280
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A

6

281
Q
A

D

282
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A

f

283
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A

c

284
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A

e

285
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A

1

286
Q
A
287
Q
A

D

288
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A

A

289
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A

c

290
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A

3

291
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A

e

292
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A

2

293
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A

6

294
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A

c

295
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A

5

296
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A

c

297
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A
298
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A

7

299
Q
A

c

300
Q
A

d

301
Q
A

7

302
Q
A

e

303
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A

g

304
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A

C

305
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A

A

306
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A

c

307
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A
308
Q
A

d

309
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A

b

310
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A

d

311
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A

f

312
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A

d

313
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A

8

314
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A
315
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A

d

316
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A

f

317
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A

7

318
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A
319
Q
A

e

320
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A

a

321
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A

7

322
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A
323
Q
A

3

324
Q
A
325
Q
A
326
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A

d

327
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A
328
Q
A

c

329
Q
A

a

330
Q
A

5

331
Q
A

Ausschliessen: Schattierung (50:50 statt 20%)

REGELN SUCHEN: Anzahl der Linien: 3, 4 oder 5 Ecken, siehe Matrix (mathematisch… dort fehlt 5 Ecken!)

332
Q
A

8

333
Q
A
334
Q
A

a

335
Q
A
336
Q
A

1

337
Q
A
338
Q
A

c

339
Q
A
340
Q
A

c

341
Q
A

a

342
Q
A
343
Q
A
344
Q
A
345
Q
A

1

346
Q
A

d

Zeilenweise nach unten von Links oben nach rechts unten:
grün, rot, blau, gelb, schwarz und dann gehts wieder von vorne lso:
grün, rot, blau - Also kanns nur GELB sein.

Gleich mit den Formen: 5-eck, dann 6-eck, dann 7eck, 8eck, 9eck, und dann rückwärts: 8eck, 7eck, 6-eck und somit kann nur 5-ECK richtig sein!

347
Q
A

5

348
Q
A

b

349
Q
A

e

350
Q
A
351
Q
A

5

352
Q
A

b

353
Q
A
354
Q
A

e

355
Q
A
356
Q
A
357
Q
A

3

358
Q
A
359
Q
A

Mehr Punkte sind Aussen, daher bleiben die Punkte aussen (A) und nicht innen (I)

360
Q
A
361
Q
A
362
Q
A

b

363
Q
A

e

364
Q
A

b

365
Q
A

D

366
Q
A

6

367
Q
A
368
Q
A

d

369
Q
A
370
Q
A

C

371
Q
A

4

372
Q
A
373
Q
A

8

374
Q
A
375
Q
A

d

376
Q
A

d

377
Q
A
378
Q
A
379
Q
A

c

380
Q
A

c

381
Q
A
382
Q
A

a

383
Q
A

B

384
Q
A

1

385
Q
A

7

386
Q
A

c

387
Q
A

c

388
Q
A

Antwort B

Bei dem habe ich mich zu Beginn an den Linien orientiert 😊 weshalb schon einmal nur B, D und E zur Auswahl standen. Danach habe ich jeweils die Striche, welche nach links und nach rechts zeigen, gezählt. Wenn du diese gezählt hast, dann wirst du bei der ersten Zeile merken, dass abwechselnd die gleiche Anzahl und eine unterschiedliche Anzahl vorkommt (3&3, 2&4, 4&4). Bei der letzten Zeile verhält es sich genauso und bei der zweiten Zeile genau umgekehrt. Also brauchst du in der dritten Spalte in der Mitte eine Lösung bei der nicht die selbe Anzahl vorhanden ist und somit kann nur Lösung B richtig sein

389
Q
A

Achtung: dritter geschwungerer Pfeil ist durch den Playbutton verdeckt. Die verstecktheit oben soll auch unten drauf hinweisen, dass es unten versteckt ist.

390
Q
A

i

391
Q
A
392
Q
A

Wieder jede Zeile oder jede Spalte. Die Linien fallen weg… Überlagerung mit substration: Sachen die doppelt sind übernehm ich, andere fallen weg.

393
Q
A

7

394
Q
A
395
Q
A

c

396
Q
A
397
Q
A

d

398
Q
A

a

399
Q
A

e

400
Q
A

e

401
Q
A

e

402
Q
A

6

403
Q
A

6

404
Q
A
405
Q
A

7

406
Q
A

5

407
Q
A

b

408
Q
A

b

409
Q
A
410
Q
A

6

411
Q
A

e

412
Q
A

e

413
Q
A

E - muss 5 Ecken haben

414
Q
A
415
Q
A

8

416
Q
A

8