LS 7B Flashcards
How do most cancers arise?
A. from a single mutations arising simultaneously in a cluster of cells
B. from a series of mutations that arise in the descendants of a single somatic cell
C. from multiple mutations arising simultaneously in a single cell
D. from mutations arising in a single cell that are then transmitted to other cells in the body
B. from a series of mutations that arise in the descendants of a single somatic cell
How do mutations arise?
A. Mutations in cancer cells arise because they need to divide faster.
B. Mutations arise in a specific sequence where a mutation in one gene directly leads to a mutation in a specific second gene.
C. Mutations arise randomly and independent of other mutations in the cell.
D. Mutations arise simultaneously, where whole sets of mutations occur in a single event.
C. Mutations arise randomly and independent of other mutations in the cell.
What effect does each successive mutation have on the colon cells in the example?
A. It causes them to leave the colon and spread to other tissues.
B. It causes them to divide more rapidly than normal cells.
C. It causes them to become non-colon cells.
D. In causes them to become larger and expand in the colon.
B. It causes them to divide more rapidly than normal cells.
When p53 becomes mutant in cells already mutant for APC and Ras, what occurs?
A. These cells survive despite DNA damage and divide extremely rapidly.
B. These cells die.
C. These cells remain benign.
D. These cells expand their chromosome number to 53.
A. These cells survive despite DNA damage and divide extremely rapidly.
According to Figure 14.2, the average number of new mutations that occur across an entire human genome in one generation is approximately _____ times higher than in nematodes.
A. 100
B. 1000
C. 10
D. 10,000
E. 2
A. 100
The number of new mutations in organisms following a round of genome replication:
A. generally decreases with larger genomes.
B. generally increases with larger genomes.
C. None of the answer options is correct.
D. is highest in bacteria.
E. is similar, independent of genome size.
B. generally increases with larger genomes.
Sites in the genome that are more susceptible to mutations than others are called:
A. risk factors.
B. genes.
C. mutation spots.
D. hotspots.
E. noncoding DNA.
D. hotspots.
_____ mutations are important to the evolutionary process; most cancers result from _____ mutations.
A. Somatic; germ-line
B. Germ-line; heritable
C. Somatic; heritable
D. Point; germ-line
E. Germ-line; somatic
E. Germ-line; somatic
Which of the following statements concerning cancer and mutations is CORRECT?
A. Cancer can only occur with a mutation in a somatic cell.
B. Usually, multiple mutations are required in different genes to cause cancer.
C. Usually, a single mutation is all that is required to cause cancer.
D. Cancer can only occur with a mutation in a germ cell.
E. None of the other answer options is correct.
B. Usually, multiple mutations are required in different genes to cause cancer.
The definition of mutation is “any heritable change in the genetic material.” The qualifier “heritable” is necessary because:
A. most changes in the genetic material are harmful to the organism.
B. changes in the genetic material occur without regard to the needs of the organism.
C. changes in the genetic material occur at random along the genome.
D. most changes in the genetic material are repaired soon after they occur.
D. most changes in the genetic material are repaired soon after they occur.
Prophase of meiosis I has some important differences from prophase of mitosis. These differences include: ___________ pair, and _________ occurs.
A. chromatids; condensation
B. chromosomes; separation
C. homologous chromosomes; crossing over ,
D. homologous chromatids; separation
C. homologous chromosomes; crossing over
During meiosis crossing over takes place between:
A. any two chromatids.
B. sister chromatids.
C. non-sister chromatids.
D. nonhomologous chromosomes.
E. nonhomologous chromatids.
C. non-sister chromatids.
In this partial image of anaphase I of meiosis, most of a chromosome is shaded dark, whereas a portion of what is in the circle is shaded light. Which of the following statements best explains the meaning of this shading?
A. The dark and light indicate homologous chromosomes.
B. The light part came from the homolog by crossing over.
C. The light part is a mixture of genes from both parental types.
D. The light and dark parts are different genes.
B. The light part came from the homolog by crossing over.
In the image below, let the light shade indicate maternally derived chromosomal material and the dark shade indicate paternally derived material. Which circle is likely to contain both paternal and maternal gene variants (alleles)?
A. circle a
B. circle b
C. circle c
D. circle d
B. circle b
In the figure below, which box encloses two copies of the same gene variants (alleles) from only one of the parents?
A. box a
B. box b
C. box c
D. box d
C. box c
In the figure below, which box encloses gene variants (alleles) of the same genes from both parents?
A. box a
B. box b
C. box c
D. box d
B. box b
In the figure below, which box contains only single gene copies from one of the parents?
A. box a
B. box b
C. box c
D. box d
A. box a
In the figure below, which box contains some gene variants (alleles) from one parent and some from the other, but not variant alleles from the same gene?
A. box a
B. box b
C. box c
D. box d
D. box d
Which of the following is NOT true about gametes?
A. They are genetically identical to other gametes formed during meiosis.
B. They fuse to form a new organism during fertilization.
C. They have half as many chromosomes as a somatic cell of the same individual.
D. They are formed by meiotic cell division.
E. They are called eggs and sperm in animals.
A. They are genetically identical to other gametes formed during meiosis.
Which of the following is NOT a characteristic of meiotic cell division?
A. Cell division results in the production of gametes.
B. Daughter cells are genetically identical.
C. Cell division requires two rounds of nuclear division.
D. Cell division results in the formation of four daughter cells.
B. Daughter cells are genetically identical.
When do sister chromatids separate in meiosis?
A. anaphase I
B. metaphase II
C. telophase I
D. anaphase II
D. anaphase II
Homologous chromosomes separate from each other in:
A. meiosis I.
B. mitosis.
C. They never separate from each other during any form of cell division.
D. meiosis II.
A. meiosis I.
In a population of organisms with 4 alleles, how many homozygous genotypes are possible? How many heterozygous genotypes are possible?
A. 3; 4
B. 4; 3
C. 4; 4
D. 4; 6
E. 4; 10
D. 4; 6
Consider a gene with four alleles A1, A2, A3, and A4. How many distinct heterozygous genotypes are possible?
A. 2
B. 3
C. 4
D. 5
E. 6
E. 6
Gene A exists in five forms in the human population. Each form, or allele, has a different number of tandem repeats. The alleles are amplified with PCR and then run on a polyacrylamide gel for analysis, yielding the following banding pattern.
Which of the lanes in the gel below could represent the alleles found in one individual?
A. All 5 lanes are possible.
B. Lanes 2, 4, and 5 are possible.
C. Lanes 2, 3, 4, and 5 are possible.
D. Lanes 1, 2, 3, and 4 are possible.
B. Lanes 2, 4, and 5 are possible.
Instructional Guidance: This question emphasizes that each numerical variant is an allele and that each individual has a maximum of 2 possible alleles. This second point seems to be a common stumbling block for students. If used during in-class instruction instead of an exam, different lanes could be included or excluded. Then, the complete gel could be used on an exam question because students have been given this example previously. The question might be made a little easier by eliminating the homozygous genotype in lane 5 or using it as a point of discussion in class.
In genetics, the dash symbol (–) is a “wild card” that stands for either the dominant allele or the recessive allele; for example, A– means the individual has either the genotype AA or Aa. Two genes that undergo independent assortment affect coat color in the house mouse. Each gene has two alleles, one of which is dominant for coat color. Genotypes of the form A– B– have a brownish color called agouti, those of the form A– bb are black, and those of the form aa B– and aa bb are albino (white). What ratio of agouti : black : white is expected from the cross Aa Bb × Aa Bb?
A. 10:3:3
B. 9:3:4
C. 12:3:1
D. 9:6:1
B. 9:3:4
In genetics, the dash symbol (–) is a “wild card” that stands for either the dominant allele or the recessive allele; for example, A– means the individual has either the genotype AA or Aa. Two genes that undergo independent assortment affect flower color in sweet peas. Each gene as two alleles, one of which is dominant for flower color. Genotypes of the form A– B– have purple flowers, whereas those of the form A– bb, aa B–, and aa bb have white flowers. What ratio of purple : white is expected from the cross Aa Bb × Aa Bb?
A. 9:7
B. 10:6
C. 12:4
D. 13:3
E. 15:1
A. 9:7
Instructional Guidance: This type of epistasis is known as “duplicate recessive epistasis.”
A pea plant is heterozygous (Aa) for seed color and heterozygous (Bb) for seed shape. According to Mendel’s principle of independent assortment: (Select all that apply.)
A. each gamete will contain either a seed-color allele or a seed-shape allele, but not both.
B. a gamete that contains dominant allele for seed color must also contain the dominant allele for seed shape.
C. a gamete that contains dominant allele for seed color must also contain the recessive allele for seed shape.
D. a gamete that contains the dominant allele for seed color is equally likely to contain the dominant or the recessive allele for seed shape.
E. possible gamete genotypes are AB or ab; each is equally likely to occur.
D. a gamete that contains the dominant allele for seed color is equally likely to contain the dominant or the recessive allele for seed shape.
E. possible gamete genotypes are AB or ab; each is equally likely to occur.
With independent assortment, the ratio of genotypes in the F2 generation of a cross between true-breeding strains (AA bb × aa BB) can be described as 1:2:1:2:4:2:1:2:1. To what genotype does the “4” in the ratio refer?
A. AA Bb
B. Aa BB
C. Aa Bb
D. None of the answer options is correct.
C. Aa Bb
Consider a gene with n alleles A1, A2, …, An. How many distinct genotypes are possible, taking into account both homozygous and heterozygous genotypes?
A. n2
B. n2/2
C. n(n –1)
D. n(n – 1)/2
E. n(n + 1)/2
E. n(n + 1)/2
Assuming that the trait represented by the filled symbols below is a rare inherited trait with complete penetrance due to a single gene with alleles A and a, what mode of inheritance does the pedigree suggest?
A. dominant
B. recessive
B. recessive
In the pedigree above, what can you say about the likely genotypes of individuals A and B?
A. both are AA
B. one is AA and the other is Aa
C. both are Aa
D. It is not possible to determine this for certain from the information provided.
C. both are Aa
You are given two populations of true-breeding tomato plants with two simple dominant/recessive traits that sort independently. Using the multiplication rule, how many different phenotypic combinations would you expect to see in the F2 generation? In what phenotypic ratio?
A. two, 3:1
B. three, 9:6:1
C. four, 9:3:3:1
C. four, 9:3:3:1
Imagine that a rancher has a herd of cattle with brown hides and short horns. All of his cattle are also relatively short in stature. If all of these traits were true-breeding, what could you say about the progeny of these cattle?
A. It is impossible to determine the traits of such progeny―they will likely demonstrate different hide colors, horn lengths, and heights.
B. The progeny of these cattle will have short horns, but a variety of hide colors and heights.
C. The progeny of these cattle will have brown, black, white, and spotted hides.
D. Because the cattle are true-breeding, the progeny of this herd will all be sterile.
E. The progeny of these cattle will be short in stature and have brown hides and short horns.
E. The progeny of these cattle will be short in stature and have brown hides and short horns.
In humans, ability to roll the tongue (R) is dominant to being unable to roll (r). Having freckles (F) is dominant to having no freckles (f). A freckled tongue-roller could have which of the following genotypes?
A. RRFF
B. RrFf
C. rrFF
D. RRFF and RrFf only
E. All of these choices are correct.
D. RRFF and RrFf only
In a diploid individual, one chromosome carries A and B genes, and the homologous chromosome carries different forms (alleles) of these same genes, a and b. If there is a single crossover between these two genes involving non-sister chromatids during metaphase I of meiosis, the resulting four gametes are:
A. AB, AB, ab, ab.
B. AB, ab, AB, ab.
C. AaBb, AaBb, AaBb, AaBb.
D. AB, Ab, aB, ab.
E. Ab, Ab, aB, aB.
D. AB, Ab, aB, ab.
Flower color in snapdragons is due to a gene with incomplete dominance: CRCR plants have red flowers, CRCW have pink flowers, and CWCW plants have white flowers. Which cross is expected to yield progeny that all have pink flowers?
A. CRCR × CRCW
B. CRCR × CWCW
C. CRCW × CRCW
D. CRCW ×CWCW
E. CWCW × CWCW
B. CRCR × CWCW
In the F2 generation of a homozygous round (AA) × homozygous wrinkled (aa) cross in peas, three seeds are chosen at random. What is the probability that two seeds are round and the other is wrinkled?
A. (1/4)^3
B. 3(1/4)(3/4)^2
C. 3(1/4)^2(3/4)
D. (3/4)^3
B. 3(1/4)(3/4)^2
Consider a gene with four alleles A1, A2, A3, and A4. If the cross A1A2 × A3A4 yields two offspring, what is the probability that both of them have the same genotype?
A. 1/8
B. 1/4
C. 1/3
D. 1/2
E. 3/4
B. 1/4
In genetics, the dash symbol (–) is a “wild card” that stands for either the dominant allele or the recessive allele; for example, W– means the individual has either the genotype WW or Ww. In summer squash, genotypes W– G– and W– gg are white, ww G– are yellow, and ww gg are green. W and G show independent assortment. What is the ratio of white : yellow : green among progeny of the cross Ww Gg × Ww Gg?
A. 12:3:1
B. 9:3:1
C. 10:3:3
D. 9:6:1
E. None of the answer options is correct.
A. 12:3:1
If you crossed two heterozygous yellow-seed pea plants (genotypes Aa), the relative frequency of:
A. the a allele in each parent’s gametes would be 1/2.
B. the A allele in each parent’s gametes would be 1/2.
C. green-seed plants (genotype aa) would be 1/4.
D. homozygous yellow-seed plants (genotype AA) would be 1/4.
E. All of these choices are correct.
E. All of these choices are correct.
Among the progeny of a heterozygous round (Aa) × homozygous wrinkled (aa) testcross, three seeds are chosen at random. What is the probability that all three seeds are round?
A. (1/2)3
B. 2(1/2)3
C. 3(1/2)3
D. 4(1/2)3
A. (1/2)^3
According to Figure 14.2, the average number of new mutations that occur across an entire human genome in one generation is approximately _____ times higher than in nematodes.
A. 2
B. 10
C. 100
D. 1000
E. 10,000
C. 100
Consider a gene with four alleles A1, A2, A3, and A4. In the cross A1A2 × A3A3, how many offspring genotypes are possible?
A. 2
B. 3
C. 4
E. 5
F. 6
A. 2
A true-breeding black rabbit is crossed with a true-breeding white rabbit to produce an F1 generation of 15 individuals. If the black color trait is dominant, which of the following represents the expected phenotype of an F1 generation cross?
A. 15 black rabbits, 0 white rabbits, 0 grey rabbits
B. 5 black rabbits, 5 white rabbits, 6 grey rabbits
C. 0 black rabbits, 0 white rabbits, 15 grey rabbits
D. 5 black rabbits, 3 white rabbits, 7 grey rabbits
E. 0 black rabbits, 15 white rabbits, 0 grey rabbits
A. 15 black rabbits, 0 white rabbits, 0 grey rabbits
During meiosis in the female, sex chromosomes segregate to produce two types of eggs: X-bearing eggs and Y-bearing eggs.
A. True
B. False
B. False
All organisms have either an X or Y chromosome, as these chromosomes are solely responsible for determining the sex of an individual. Mendel’s failure to identify X and Y chromosomes in his pea plants invalidated a portion of the data he collected.
A. False
B. True
A. False
Homologous chromosomes usually have the same arrangement of genes along their length.
A. True
B. False
A. True
Genes located along the X chromosome:
A. have a full set of complementary alleles in the Y chromosome.
B. are contributed solely by the female parent.
C. are called X-linked genes.
D. are always recessive to genes located in the Y chromosome.
C. are called X-linked genes.
Which of the following is true of a cross involving a sex-linked gene but not of a cross involving an autosomal gene?
A. The phenotype outcomes of female offspring compared to males can be different.
B. A Punnett square cannot be utilized for illustrating the possible outcomes of a cross involving a sex-linked gene.
C. Only autosomal genes observe the law of segregation.
D. Both parents have two copies of a sex-linked gene.
E. Recombination or crossing over cannot take place between sex chromosomes.
A. The phenotype outcomes of female offspring compared to males can be different.
Review the pedigree shown in Figure 17.7 and choose the most accurate statement about the inheritance of an X-linked recessive mutation.
A. The brothers of affected males are always affected.
B. The offspring of an affected male are usually affected.
C. For rare X-linked traits, most of the affected individuals are males.
D. The sons of the sisters of affected males will always be affected.
E. Daughters of affected males are always affected.
C. For rare X-linked traits, most of the affected individuals are males.
Which of the following is a possible human genotype that could result from nondisjunction of the sex chromosomes in one of the parental gametes?
A. All of these choices are correct.
B. XO
C. XYY
D. XXX
E. XXY
A. All of these choices are correct.
Sometimes homologous chromosomes fail to separate normally during meiosis I, a process called:
A. nontransferrance.
B. chromosome separation.
C. nondisjunction.
D. conjugation.
E. unijunction.
C. nondisjunction.
A heterozygous female harboring one mutant allele for hemophilia is called a(n) _____ for that trait.
A. messenger
B. homozygote
C. unaffected female
D. carrier
E. harborer
D. carrier
For most genes on the human X chromosome, what percent of XY males with a mutant allele on the X chromosome will express the mutant phenotype?
A. 0%
B. 25%
C. 50%
D. 100%
E. There is insufficient data to predict.
D. 100%
In humans, fruit flies, and many other organisms, most of the genes on the X chromosome are not found on the Y chromosome.
A. true
B. false
A. true
If an XY male carries a mutation on his X chromosome, _______________BLANK will receive the mutant X.
A. all of his sons
B. all of his daughters
C. all his sons and daughters
D. half his sons and half his daughters
B. all of his daughters
A normal female who carries a recessive X-linked allele for hemophilia will pass it on to:
A. all of her daughters.
B. half of her daughters.
C. all of her sons.
D. half of her sons.
E. half of both her sons and daughters.
E. half of both her sons and daughters.
Color blindness is a recessive X-linked trait in humans. In a family where the mother is color-blind and the father is normal, the probability of their having a color-blind son is:
A. 0.
B. 1.
C. 1/4.
D. 1/2.
E. 1/16.
B. 1.
Color blindness is a recessive X-linked trait in humans. In a family where the mother is heterozygous for color blindness and the father is color-blind, the probability of their having a color-blind daughter is:
A. 0.
B. 1.
C. 1/4.
D. 1/2.
E. 1/16.
D. 1/2.
The genotype of a fetus can be screened for SNPs associated with some diseases.
A. True
B. False
A. True
Mutations that destroy or create a cleavage site for a restriction enzyme are the source of:
A. restriction fragment length polymorphisms.
B. copy-number variants.
C. single-nucleotide polymorphisms.
D. variable number tandem repeats.
A. restriction fragment length polymorphisms.
After doing PCR on the same region between two individuals, you notice that each person’s DNA yielded pieces of different sizes. Which of the following is the MOST likely explanation?
A. A mistake was made during gel electrophoresis.
B. A mistake was made during the PCR.
C. This is an example of VNTRs.
D. This is an example of RFLPs.
E. None of the answer options is correct.
C. This is an example of VNTRs.
An individual is heterozygous for two linked genes, but whether its genotype is A B/a b or A b/a B is not known. The individual is crossed with an a b/a b individual, and among the progeny are the following:
16 A B/a b
54 A b/a b
46 a B/a b
24 a b/a b
These results imply that the genotype of the doubly heterozygous parent was A B/a b.
A. True
B. False
B. False
Instructional Guidance: The most frequent classes of gametes are the nonrecombinant (parental) types and therefore tell you that parental genotype.
X-linked genes show crisscross inheritance because males:
A. get their Y chromosome from their father.
B. get their X chromosome from their mother.
C. transmit their Y chromosome to their sons.
D. transmit their X chromosome to their daughters.
E. get their Y chromosomes from their father and transmit their Y chromosomes to their sons.
F. get their X chromosomes from their mother and transmit their X chromosomes to their daughters.
F. get their X chromosomes from their mother and transmit their X chromosomes to their daughters.
Suppose that certain genes related to the eye, ear, nose, and throat are present in two autosomes, and each of these genes has multiple alleles. The eye and ear genes have a recombination frequency of 25%, and the nose and throat genes have a recombination frequency of 35%. As a genetic counselor, you are examining these genes in a couple who are interested in having children soon. Simplified illustrations of the mother’s and father’s genotypes are below.
If the couple’s potential child inherits the eye7 allele from the mom, what is the chance of the child also inheriting the eye8 allele from the father?
A. 100%
B. 75%
C. 50%
D. 25%
E. 0%
E. 0%
Suppose that certain genes related to the eye, ear, nose, and throat are present in two autosomes, and each of these genes has multiple alleles. The eye and ear genes have a recombination frequency of 25%, and the nose and throat genes have a recombination frequency of 35%. As a genetic counselor, you are examining these genes in a couple who are interested in having children soon. Simplified illustrations of the mother’s and father’s genotypes are below.
What proportion of the couple’s offspring will be eye7 eye7/nose3 nose3?
A. 1/4
B. 1/2
C. 1/8
D. 1/16
E. 1/32
D. 1/16
Suppose that certain genes related to the eye, ear, nose, and throat are present in two autosomes, and each of these genes has multiple alleles. The eye and ear genes have a recombination frequency of 25%, and the nose and throat genes have a recombination frequency of 35%. As a genetic counselor, you are examining these genes in a couple who are interested in having children soon. Simplified illustrations of the mother’s and father’s genotypes are below.
Assuming equal frequencies of recombination in females and males, which combination would be more common in offspring?
A. nose3 throat1 in one chromosome, nose3 throat1 in the other chromosome
B. nose3 throat1 in one chromosome, nose6 throat2 in the other chromosome
C. nose6 throat2 in one chromosome, nose6 throat2 in the other chromosome
D. None. All possible combinations would be equally represented in offspring.
D. None. All possible combinations would be equally represented in offspring.
Suppose that certain genes related to the eye, ear, nose, and throat are present in two autosomes, and each of these genes has multiple alleles. The eye and ear genes have a recombination frequency of 25%, and the nose and throat genes have a recombination frequency of 35%. As a genetic counselor, you are examining these genes in a couple who are interested in having children soon. Simplified illustrations of the mother’s and father’s genotypes are below.
What proportion of the couple’s offspring will inherit eye7 ear4 from the mother?
A. 100%
B. 75%
C. 37.5%
D. 25%
E. 12.5%
C. 37.5%
The pedigree shown here pertains to a trait due to a rare, X-linked recessive mutation.
Individual 1 has an affected father, but the genotypes and phenotypes of individuals 1–4 are unknown. What is the probability that individual 1 is heterozygous? What is the probability that individual 3 is heterozygous? What is the probability that individual 4 is affected?
A. 1/2; 1/4; 1/4
B. 1/2; 1/4; 1/2
C. 1; 1/4; 1/2
D. 1; 1/2; 1/4
E. 1; 1/2; 1/2
E. 1; 1/2; 1/2
An individual who is heterozygous for two linked genes (with alleles A, a and B, b) is crossed with an a b/a b individual, and among the progeny are the following:
14 A B/a b
36 A b/a b
34 a B/a b
16 a b/a b
What is the frequency of recombination?
A. 0.30
B. 0.35
C. 0.40
D. 0.60
E. 0.70
A. 0.30
Red-green color blindness is due to a mutant gene in the X chromosome. An XX female with normal color vision and an XY male with normal color vision have a child with karyotype XXY who is color blind. The likely explanation is that the:
A. father was heterozygous for the color-blindness mutation.
B. mother was heterozygous for the color-blind mutation.
C. father had CNV of the color-blind mutation.
D. mother had CNV of the color-blind mutation.
E. None of the other answer options is correct.
B. mother was heterozygous for the color-blind mutation.
Considering an X-linked dominant trait, if an unaffected woman and an affected man decide to have children, which of the following statements is TRUE about the possibilities for their children?
A. Their sons are expected be heterozygous for the associated gene.
B. Their daughters are expected be heterozygous for the associated gene.
C. All their children, whether male or female, are expected to show the dominant trait.
D. All of their sons are expected to show the dominant trait.
E. Their daughters are not expected to show the dominant trait.
B. Their daughters are expected be heterozygous for the associated gene.
Given equal probabilities of the birth of a boy or girl, what is the probability that a group of four siblings includes all boys? All girls? All boys or all girls?
A. 1/8; 1/16; 3/8
B. 1/16; 1/8; 3/8
C. 1/16; 1/16; 1/64
D. 1/16; 1/16; 1/8
D. 1/16; 1/16; 1/8
The pedigree shown here pertains to a trait due to a rare, X-linked recessive mutation.
Individual 1 has an affected grandfather, but the genotypes and phenotypes of individuals 1–4 are unknown. What is the probability that individual 1 is heterozygous? What is the probability that individual 3 is heterozygous? What is the probability that individual 4 is affected?
A. 1; 1/4; 1/4
B. 1; 1/2; 1/2
C. 1/2; 1/4; 1/2
D. 1/2; 1/2; 1/2
E. 1/2; 1/4; 1/4
E. 1/2; 1/4; 1/4
Hemophilia is a sex-linked recessive trait in humans. If a carrier female (heterozygous for the trait) mated with a nonaffected male, what would be the expected outcome(s)?
A. None of the offspring would have hemophilia.
B. None of the daughters would have hemophilia.
C. Half the daughters would have hemophilia.
D. Half the sons would have hemophilia.
E. None of the daughters would have hemophilia, and half of the sons would have hemophilia.
E. None of the daughters would have hemophilia, and half of the sons would have hemophilia.
An individual that is heterozygous for two linked genes has the genotype A b/a B, which means that the A and b alleles are in one chromosome and the a and B alleles in the homologous chromosome. Among the products of meiosis listed below, which are the recombinant types? (Select all that apply.)
A. A B
B. A b
C. a B
D. a b
A. A B
D. a b
What is an SNP?
A. a single nucleotide polymorphism
B. a location where individual alleles differ by one base pair
C. a genetic difference that can occur between different individuals
D. All of these choices are correct.
D. All of these choices are correct.
Which of the following is not part of a microarray used to detect SNPs?
A. short DNA sequences attached to a glass slide
B. oligonucleotides that match the sequence of a known SNP site in the genome
C. mRNAs that are expressed from a specific gene
D. short DNA sequences synthesized with a specific sequence
E. oligonucleotides that differ in sequence only at the SNP itself and are positioned at different locations on a glass slide
C. mRNAs that are expressed from a specific gene
Which of the following is not part of the process of using a microarray to detect SNPs in an individual’s DNA?
A. DNA from the individual is isolated from his or her cells.
B. Sequences from the region containing the SNP are amplified.
C. Amplified DNA is labeled with a fluorescent dye.
D. Proteins from the gene are allowed to stick to the microarray.
E. DNA is hybridized to the oligonucleotides to allow exact base pairing.
D. Proteins from the gene are allowed to stick to the microarray.
How are SNP alleles in an individual detected using a microarray?
A. The DNA from the individual is sequenced using dideoxy sequencing.
B. The location on the microarray of the hybridizing DNA is visualized using a microscope.
C. DNA primers on each side of the SNP are hybridized for PCR.
B. The location on the microarray of the hybridizing DNA is visualized using a microscope.
How will SNP microarray results differ in an analysis of DNA from an individual who is homozygous for one allele compared with an individual who is heterozygous for both alleles?
A. The strength of the fluorescent glow will be stronger in the analysis of DNA from the homozygous individual.
B. The fluorescent signal will be detected for both A−T and G−C base pairs in analysis of DNA from the heterozygous individual, but for only one of these base pairs in DNA from homozygotes.
C. DNA from heterozygous individuals will not be hybridized to the microarray, but base-pair matching hybridization will occur using DNA from heterozygotes.
B. The fluorescent signal will be detected for both A−T and G−C base pairs in analysis of DNA from the heterozygous individual, but for only one of these base pairs in DNA from homozygotes.
How many SNPs can be detected using a single microarray?
A. 1
B. 2
C. 46
D. millions
D. millions
Much of the genetic variation seen in the human population is neutral.
A. False
B. True
B. True
A newly arisen point mutation always creates an SNP.
A. True
B. False
B. False
For an SNP with three alleles, how many different diploid genotypes are possible?
A. 3
B. 4
C. 6
D. 7
E. 5
C. 6
A new gene is discovered that dramatically aids in the digestion of fish. You hypothesize that populations with a history of being near the shoreline would have more copies of this gene than populations found farther inland. How would you classify this genetic difference?
A. SNP
B. RFLP
C. CNV
D. VNTR
E. None of the answer options is correct
C. CNV
Saying that a SNP is associated with a disease means that if you possess that particular SNP, you will end up with that disease.
A. True
B. False
B. False
SNPs arise from:
A. translocations.
B. inversions.
C. point mutations.
D. deletions.
E. duplications.
C. point mutations.
Consider a normal human cell in which one chromosome undergoes nondisjunction in mitosis. What chromosome numbers would be found in the daughter cells?
A. 46 and 47
B. None of the answer options is correct.
C. 45 and 46
D. 46 and 46
E. 45 and 47
E. 45 and 47
First division nondisjunction will only yield gametes with an extra chromosome, whereas second division nondisjunction will only yield gametes missing a chromosome.
A. True
B. False
B. False
The failure of a pair of chromosomes to separate during anaphase is referred to as:
A. nondisjunction.
B. translocation.
C. trisomy.
D. disjunction.
E. inversion.
A. nondisjunction.
What is one reason a woman with the genotype XXX are not phenotypically different from an XX female?
A. The extra X chromosome only becomes active in nonreproductive areas of the body.
B. None of the answer options is correct.
C. The X chromosome only carries genes dealing with being a female, so having another one doesn’t matter.
D. Only one X is active in each cell, regardless of how many X chromosomes there are in a cell.
E. We have enzymes that will recognize and degrade the extra X chromosome.
D. Only one X is active in each cell, regardless of how many X chromosomes there are in a cell.
Which of the following is true?
A. Down syndrome is the one inherited disorder that results from an extra copy of an entire chromosome.
B. Down syndrome is caused by errors in fertilization.
C. Errors in chromosome segregation can occur in either the first or second meiotic division.
D. Nondisjunction can only produce gametes with extra chromosomes, not missing chromosomes.
C. Errors in chromosome segregation can occur in either the first or second meiotic division.