Limits Flashcards
Name all limit laws
- Sum law
- Difference law
- Constant multiple law
- Product law
- Quotient law
- Power law
- Root law
- Constant law
- Direct substitution law
Sum law
lim_x-a (f(x) + g(x)) = lim_x-a f(x) + lim_x-a g(x)
Difference law
lim_x-a (f(x) - g(x)) = lim_x-a f(x) - lim_x-a g(x)
Constant multiple law
lim_x-a (cf(x)) = c lim_x-a f(x)
Quotient law
lim_x-a (f(x)/g(x)) = (lim_x-a f(x))/(lim_x-a g(x))
Product law
lim_x-a (f(x) * g(x)) = lim_x-a f(x) * lim_x-a g(x)
Power law
lim_x-a (f(x)^n) = (lim_x-a f(x))^n
Root law
lim_x-a sqrt(f(x)) = sqrt(lim_x-a f(x))
Constant law
lim_x-a c = c
Direct substitution law
If f(x) is elementary (continuous everywhere, but mainly at a), not piecewise, and f(a) is defined:
lim_x-a f(x) = f(a)
Theorems for limits at infinity
e^inf = inf
e^-inf = 0
1/inf = 0
inf^p = inf
inf^-p = {-inf, p is odd} {inf, p is even}
Indeterminate values for infinity
inf - inf
0 * inf
inf/inf
0^inf
1^inf
inf^0
0^0
Infinite arithmetic
inf + inf = inf
-inf - inf = -inf
c + inf = inf
c - inf = -inf
c(inf) = inf ; c>0
c(inf) = -inf; c<0
(inf)(inf) = inf
(-inf)(-inf) = inf
(-inf)(inf) = -inf
sqrt(inf) = inf
1/inf = 0
c/inf = 0
c^inf = inf; c>1
c^inf = 0 ; 0<c<1
c^-inf = 0; c>0
Solving limit with finite value
- If function is absolute value, convert to a piecewise limit and solve each one sided limit
- Check if direct substitution works
- Check if hole or asymptote
If hole: Solve algebraically or use l’hospital’s rule
If asymptote: Limit does not exist, but find if it’s +- inf
Finding +- inf for limit
Plug in values close to a on either side of a to find +- for each side
Solving algebraically
*Only applies if limit is a hole
*Goal is to stop bottom from equaling zero
*Factor and then simplify, then use direct substitution
*If you see a square root, use conjugate pairs to move radical to denominator, then simplify
*With complex fractions, combine and simplify
*Use limit laws to simplify if needed
*As a least resort use squeeze method if you are dealing with sin and cos
*You can’t assume # * DNE = DNE, but you can assume # +DNE = DNE
Squeeze method
If f(x) =< g(x) =< h(x) near x=c,
and lim_x-c f(x) = L = lim_x-c h(x)
then lim_x-c g(x) = L
A function that’s continuous at a must:
- Have f(a) be defined
- lim_x-a f(x) exists
- Lim_x-a f(x) = f(a)
Things needed for squeeze theorem for sin and cos
-1 =< sin x =< 1
-1 =< cos x =< 1
It does not matter what is inside the function. It could be 2x or 1/x or whatever.
Solving limits at infinity
- If function is absolute value, convert to a piecewise limit and solve each one sided limit
- Check if direct substitution works
- a. Divide everything by largest power of x then try again
b. Use dominance theory
c. Use l’hospital’s rule
d. Transform the function
Limits of e
lim_x-a e^x = e^(lim_x-a x)
Limits of logs
lim_x-a ln(x) = ln(lim_x-a x)
Function theorem limits
If f(g(x)) is continuous at x, then lim_x-a f(g(x)) = f(lim_x-a g(x))