Less9ProdQuotRulesTrigDeriv Flashcards
Prove that the derivative of the product is not the product of the derivatives with:
f(x) = x g(x) = x²
f’(x) = 1 g’(x) = 2x
The product of the derivatives is 2x
x*x² = x³ It’s derivative is 3x²
What is the Product Rule formula?
[f(x)*g’(x)] + [g(x)*(f’(x)]
Use the Product Rule to solve f(x) = x*x²
f(x) = x f’(x) = 1
g(x) = x² g’(x) = 2x;
(x*2x) + (x²*1) = 3x²
Use the Product Rule to find the derivative of:
3x²*sinx
f(x) = 3x² f’(x) = 6x;
g(x) = sinx g’(x) = cosx;
(3x²*cosx) + (sinx*6x) =
3x(xcosx + 2sinx)
What is the formula for the Quotient Rule of derivatives?
d/dx[f(x)/g(x)] =
[g(x)f’(x) - f(x)g’(x)]/g²(x)
g(x) not=0
What is the derivative of (x³+cosx)/6?
= 1/6*(x³ + cosx)
Use the constant multiple rule
d/dx = 1/6*(3x² - sinx)
You don’t need the quotient rule.
What is the derivative of tanx?
sin’(x)/cos’(x)
f(x)=sinx f’(x)=cosx
g(x)=cosx g’(x)=-sinx
(cosxcosx) - (sinx-sinx)/cos²x
cos²x + sin²x = 1 so
1/cos²x = sec²x
How do you find the cotx on a TI-84?
The cotx is 1/tanx.
tan(1 radian) ≈ 1.557
1/1.557 ≈ .6421
What is the derivative of cotx?
cotx = cosx/sinx
f(x) = cosx f’(x) = -sinx
g(x) = sinx g’(x) = cosx
g²(x) = sin²x
[-sin²x - cos²x]/sin²x
-(sin²x + cos²x)/sin²x
[sin²x + cos²x = 1]
-1/sin²x = -csc²x
d/dxcotx = -csc²x
What is the derivative of secx?
secx = 1/cosx
d/dxsecx = secxtanx
What is the derivative of cscx?
d/dxcscx = -cscxcotx
What is d/dx (3x - tanx)?
3 - sec²x
What are higher orders of derivatives?
Derivatives of derivatives
What are the first five orders of derivatives of f(x) = x4?
f’(x) = 4x³
f”(x) = 12x²
f”‘(x) = 24x
f”“(x) = 24
f””‘(x) = 0
all higher ones are 0
How do you find the numerical derivative at any point on a graph on a TI-84?
Enter equation on y= screen → Graph → 2nd/Trace → Enter the letter x → x-value
You must go through this process each time for different x-values