Lenses Flashcards

1
Q

Describe the action of a thin converging lens on a parallel beam of light.

A

A thin converging lens bends a parallel beam of light inward, causing the rays to converge at a point called the focal point.

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2
Q

Describe the action of a thin diverging lens on a parallel beam of light.

A

A thin diverging lens bends a parallel beam of light outward, causing the rays to spread apart as if they originate from a focal point behind the lens.

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3
Q

Define ‘focal length’.

A

The focal length is the distance between the center of the lens and the focal point, where parallel rays converge or appear to diverge.

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4
Q

Define ‘principal axis’.

A

The principal axis is the straight line passing through the center of the lens and the two focal points.

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5
Q

Define ‘principal focus’ (focal point).

A

The principal focus is the point on the principal axis where rays parallel to the axis converge (for a converging lens) or appear to diverge from (for a diverging lens).

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6
Q

State the difference between real and virtual images formed by lenses.

A

A real image is formed by converging rays and can be projected onto a screen, while a virtual image is formed by diverging rays and cannot be projected.

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7
Q

Draw and describe a ray diagram showing the formation of a real image by a converging lens.

A

A ray passing parallel to the principal axis refracts through the focal point. A ray passing through the center of the lens continues straight without bending. The rays meet to form a real image on the other side of the lens.

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8
Q

Draw and describe a ray diagram showing the formation of a virtual image by a converging lens.

A

A ray passing parallel to the principal axis refracts through the focal point. A ray passing through the center of the lens continues straight without bending. The rays diverge, and the virtual image is formed by extending the rays backward.

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9
Q

Define linear magnification.

A

Linear magnification is the ratio of the image length to the object length.

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10
Q

State the formula for linear magnification.

A

Linear magnification = image length / object length.

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11
Q

Describe how a single lens is used as a magnifying glass.

A

A converging lens is used to produce a magnified virtual image of an object by placing the object within the focal length of the lens.

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12
Q

Alternate-style question: How can you experimentally determine the focal length of a converging lens?

A

Focus parallel sunlight onto a piece of paper using the lens. Measure the distance between the lens and the paper when the smallest, brightest point of light appears. This distance is the focal length.

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13
Q

Draw and describe a ray diagram showing the formation of images in the normal eye.

A

Parallel rays entering the eye converge on the retina due to the focusing action of the eye’s lens, forming a sharp image.

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14
Q

Draw and describe a ray diagram showing the formation of images in a short-sighted eye.

A

In a short-sighted (myopic) eye, parallel rays converge in front of the retina, causing distant objects to appear blurry.

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15
Q

Draw and describe a ray diagram showing the formation of images in a long-sighted eye.

A

In a long-sighted (hyperopic) eye, parallel rays converge behind the retina, causing nearby objects to appear blurry.

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16
Q

Describe how a converging lens corrects long-sightedness.

A

A converging lens bends incoming rays inward, causing them to converge on the retina, correcting the issue of rays focusing behind the retina.

17
Q

Describe how a diverging lens corrects short-sightedness.

A

A diverging lens spreads incoming rays outward, shifting the focal point forward so that the rays converge on the retina.

18
Q

What is the purpose of using a magnifying glass?

A

A magnifying glass enlarges the apparent size of an object by forming a magnified virtual image of the object.

19
Q

Alternate-style question: How can you verify the magnification provided by a lens?

A

Measure the object’s length and the length of its image using a ruler, then calculate magnification using the formula: magnification = image length / object length.

20
Q

Why is the principal axis important in ray diagrams?

A

The principal axis serves as the reference line for drawing and interpreting the paths of light rays through the lens.