Lecture 8: Water Homeostasis Flashcards

1
Q

how is H2O intake altered?

A

activation or decrease in thirst

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2
Q

how does the body excrete H2O and how is excretion regulated?

A

loss from skin, respiration, GI tract, kidney**

kidney regulates it

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3
Q

how much of total body water is in the ICF versus ECF?

A

2/3 in ICF, 1/3 in ECF
1/4 of ECF in intravascular (plasma) fluid
3/4 of ECF in interstitial (extravascular) fluid

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4
Q

What is the difference between osmolality and tonicity?

A

osmolality is the total particles per unit weight of solvent. It is measurable and calculable

tonicity is the # of particles that cannot freely cross cell membrane per unit volume (effective osmolality). it is not measurable, but is calculable

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5
Q

What ions play a major role in ECF?

A

Na - major cation

Cl-, HCO3- major anions

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6
Q

What ions play a major role in ICF?

A

K+ and Mg2+ are major cations

proteins and phospgate are the major intracellular anions

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7
Q

What must occur to have renal H2O excretion?

A

Fluid must be filtered at the glomerulus
Salt must be removed from the ultrafiltrate (thick AL of loop of Henle).
The “free” H2O must transverse through tubules that are H2O tight

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8
Q

What must occur to have renal H2O reabsorption?

A

An osmotic gradient must be generated to allow H2O to be reabsorbed.
This gradient is established by generating and maintaining a hypertonic medullary
interstitium
Vasopressin must be present to allow H2O reabsorption in the collecting duct by
increasing H2O permeability of the apical membrane (insertion of aquaporin 2).

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9
Q

Describe water filtration at glomerulus

A

H2O is freely filtered. ~150 liters of H2O are filtered daily (GFR).

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10
Q

Describe water reabsorption at proximal tubule

A

Solutes and H2O are reabsorbed isotonically by the proximal tubule. ~60% to 70% of the
ultrafiltrate is reabsorbed normally. Up to 90% reabsorption of the ultrafiltrate can occur
with severe effective circulating volume depletion.

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11
Q

Describe permeabilities in the descending limb of the loop of Henle

A

H2O permeable, and Na+ impermeable

H2O leaves the urinary space through aquaporins as the tubular fluid flows through the medulla in response to the osmotic gradient.The concentration of solutes in the tubular fluid progressively increases to a maximum value at the tip of Henle’s loop. Under conditions of severe effective circulating volume depletion, up to 90% of the H2O in the filtrate that reaches the loop of Henle can get reabsorbed in this segment. Therefore, low ECBV decreases the renal capacity for the excretion of water by activating a series of steps that enhance proximal fluid reabsorption through hemodynamic effects and a direct stimulation of transport in the proximal tubule and enhanced water reabsorption in the descending limb. It can also reduce GFR in extreme cases. The net result is a limit on the amount of isotonic fluid that is delivered
downstream to the distal diluting sites

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12
Q

Describe permeabilities in the ascending limb of the loop of Henle

A

H2O impermeable, but actively transports Na+ out of the tubule and can establish a local osmotic gradient of ~200 mOsm across the epithelial layer. This antiparallel (or countercurrent) flow of fluids through neighboring pathways generates a
hypertonic interstitium as well as hypotonic tubular fluid at the end of Henle’s loop. This process is termed countercurrent multiplication. The interstitial
osmolality varies from between 285 mOsm/kg H2O in the cortex to up to ~1200 mOsm/kg H2O in the inner medulla under conditions of maximum antidiuresis.

NaCl is transported out the tubular space, such that by the end of the loop of Henle, the osmolality of the tubular fluid is quite low (or hypotonic; ~ 50 to 100 mOsm/kg H2O).
- In the first portion of the ascending limb, the thin ascending limb, NaCl passively diffuses out of the tubular lumen. The NaCl concentration in the interstitium is lower than in the tubular lumen. Urea diffuses into the tubular lumen from the interstitium,
as the urea concentration in the interstitium is greater than in the tubular fluid.
- The latter portion of the ascending limb is the thick ascending limb. NaCl is transported
out of the tubular lumen by crossing the apical membrane via a Na/K/2Cl cotransporter. The Na+, K+-ATPase then extrudes Na+ from the cell and Cl- exits the cell via basolateral Cl- selective ion channels.
- ~ 15% - 20% of the filtered H2O is reabsorbed in the loop of Henle

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13
Q

Describe water reabsorption at the distal convoluted tubule

A

Largely H2O impermeable. Vasopressin will increase H2O permeability of the late distal
convoluted tubule. As NaCl is transported out the lumen, the osmolality of the tubular fluids may decrease further.

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14
Q

Describe water reabsorption at the collecting duct

A

The collecting duct is the final site of H2O reabsorption by the kidney.
Without vasopressin, the apical membrane is H2O impermeable.
The final urine osmolality can be as low as 50 mOsm/kg H2O. Up to 18 liters of free H2O exit the loop of Henle.
In the continued absence of vasopressin, H2O excretion by the kidney can approach levels of 18 liters/day.
In the presence of vasopressin, H2O permeability of the apical membrane is increased by the movement of water channels from a cytoplasmic pool to the cell surface. In the cortical collecting duct, the tubular fluid osmolality can rise up to ~300 mOsm/kg. The cortical collecting duct is largely impermeable to urea. As the tubular fluid flows through the medullary collecting duct, both H2O and urea can be reabsorbed in the presence of vasopressin by passive diffusion. The final urinary
osmolality can reach levels as high as 1,200 mOsm/kg H20.

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15
Q

Describe urea reabsorption at the collecting duct

A

Urea diffuses out of the medullary collecting duct and contributes to the osmolality of the
medullary interstitium and during states of active water reabsorption by the kidney, can
account for up to 40-50% of the solutes in the medullary interstitium. Vasopressin
activates urea transporters in the medullary collecting duct that facilitate the transport of
urea out of the tubular lumen and into the medullary interstitium. In the absence of
vasopressin (e.g., chronic ingestion of large volumes of water, diabetes insipidus)
medullary urea concentration drops, decreasing the ability of the affected individual to
form a concentrated urine.

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16
Q

Steps in the countercurrent multiplication mechanism

A
  1. Active transport of NaCl in the thick ascending limb by Na-K-2Cl cotransporter in apical membrane and Na-K-ATPase in basolateral membrane => removal of salt from lumen leaves tubular fluid hypotonic as it enters the distal nephron.
  2. If kidney is trying to conserve water (i.e., a significant amount of ADH is present), water
    reabsorption will occur through ADH-regulated water channels in the cortical and medullary collecting duct.
  3. The relative impermeability of the cortical and medullary collecting duct to urea allows
    urea to build up in the tubules until it reaches the inner medulla, where ADH-regulated urea permeability allows urea to exit and contribute to the generation of the hypertonic environment there.
  4. Osmotic water loss throughout the descending limb of the loop of Henle allows the luminal NaCl concentration to get very high by the hairpin turn.
  5. As it enters the thin ascending limb, NaCl can passively diffuse out into the interstitium
    down its concentration gradient.
17
Q

Describe vasopressin

A

peptide hormone synthesized in the supraoptic nucleus of the hypothalamus and secreted by the posterior pituitary gland
major regulator of body tonicity

18
Q

What causes the release of ADH

A

a) Volume depletion or decreases of “effective circulating volume”
b) Drugs - barbiturates, narcotics, nicotine.
c) Stress - pain, trauma, nausea, anxiety.
d) Central nervous system disease.

19
Q

What suppresses release of ADH?

A

hypotonicity, alpha-adrenergic stimulation, ethanol,

and volume expansion.

20
Q

What is the mechanism of action of vasopressin?

A

Two receptors for vasopressin have been identified (V1 and V2). Binding of vasopressin to specific V2 receptors in the basolateral membrane of collecting tubular cells results in increased production of cAMP. This leads to movement of H2O channels (aquaporin 2) present in membrane vesicles in the cell interior to the apical membrane, and will increase the apical membrane H2O permeability.

21
Q

What stimulates thirst?

A

plasma osmolality >285 mOsm

decreases in ECFV or effective arterial volume

22
Q

Clearance of osmotically active particles or osmolal clearance equation

A

(Cosm) = (Uosm x V) / Posm
Where Uosm = urine osmolality
Posm = plasma osmolality
And V is the urine volume.

23
Q

What are the differences between dehydration and volume depletion? How do you treat each?

A
  1. Dehydration = free water deficit = hypernatremia
    Treatment: free water repletion (generally slowly)
  2. Volume depletion = extracellular fluid or effective circulating blood volume depletion
    Treatment: isotonic fluid replacement (generally more rapidly)
  3. Rule of thumb: correct volume deficits first, then correct water imbalances (slowly)
24
Q

What are the sensors for osmoregulation

A
Central Osmoreceptors:
- Organum Vasculosum of 
Lamina Terminalis (OVLT) 
is the main central 
osmosensor
Peripheral Osmoreceptors:
- Pharynx, esophagus, GI 
tract, portal vein, 
splanchnic mesentery
25
Q

what are the sensors for volume regulation?

A

Carotid sinus, atria, afferent

arterioles

26
Q

What are the effectors of osmoregulation?

A

ADH

thirst mechanism

27
Q

what are the effectors of volume regulation?

A

SNS
RAAS
Natriuretic peptides
ADH

28
Q

What is effected by osmoregulation?

A

water excretion

water intake

29
Q

What is effected by volume regulation?

A

sodium excretion