Lecture 4 - Advanced 1D Conduction (DOBSON) Flashcards

1
Q

What is the thermal resistance equation for heat flow inside a cylinder?

A

Rth = ln(r_o/r_i)/2Pik*L

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2
Q

If the surface of a cylinder is undergoing natural convection, what does the thermal resistance become?

A

Rth= 1/2Pir_oLh

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3
Q

Why is it often not the case that when two materials are brought together their contacting surface temperatures are the same?

A

Normally considered to be due to surface roughness, preventing a perfect contact.

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4
Q

How can we calculate the surface contact thermal resistance?

A

Rth = 1?h_c*A, where h_c is the contact conductance coefficient.

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5
Q

When can a lumped capacitance model be used?

A

Whenever heat conduction within an object is much faster than heat conduction across the boundary of the object. The changing uniform temp within the object or part of a system, can then be treated like a capacitate reservoir which absorbs heat until it reaches a steady thermal state in time.

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6
Q

Example of a lumped capacitance model?

A

Newton’s law of cooling: the temp of a hot (or cold) object will progress toward the temp of its environment in a simple exponential fashion.

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7
Q

Most important assumption with lumped system analysis?

A

The temp within the part is uniform

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8
Q

What does the Biot number do?

A

Allows us to asses whether it is safe to assume the temp within a part is uniform.

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9
Q

What is the limit for Biot number?

A

If Bi < 0.1 , surface convection/conduction is small enough compared to internal conduction: internal temp distributions should be uniform.

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10
Q

Equation for Biot number?

A

Bi = h(V/A)/k

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11
Q

When is the Biot number <1?

A

When the thermal resistance to heat transferred into the object is larger than the resistance to heat being diffused within the object. Must be <1 for usefully accurate approximation and heat transfer analysis.

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12
Q

If the Biot number is not small enough what can we do?

A

Break the system down into a sufficient number of sections so that Bi becomes small enough (since Bi depends on characteristic length).

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13
Q

What is heat capacity?

A

The amount of heat required to change a substance’s temp by a given amount (J/K).

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14
Q

What is specific heat capacity?

A

The heat capacity per unit mass of a material (J/kgK)

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15
Q

What does doubling the amount of substance do to the heat capacity?

A

Doubles it

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16
Q

The larger the no. of degrees of freedom available to the particles, what happens to the specific heat capacity?

A

The larger the specific heat capacity.

17
Q

Rate of heat transfer for a capacitive model?

A

q = -c.rho.V.dT/dt

18
Q

Therefore what is the thermal capacitance associated with a capacitive model?

A

Cth = c.rho.V

19
Q

If T=To at t=o then?

A

T-Tinf./To-Tinf = e^[(-hA/rho.c.V)t]