Lecture 3: Continuous Cultures and Fed Batch Cultures Flashcards

1
Q

How do you calculate yield?

A

biomassT1-BiomassT0 / SubstrateT0-SubstrateT1

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2
Q

What does Qp mean?

A

Productivity

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3
Q

How can fermentation be manipulated to increase yield?

A

Production of Biomass (primary product): Develop conditions for maximum cell yield in stationary phase, but consider factors such as the time required to realise the yield

Primary metabolites (growth-linked products): Develop conditions to extend exponential growth phase. E.g., use substrate for which the organisms has a low Ks

Secondary metabolites (non-growth-linked products): Develop conditions to reduce exponential phase and extend deceleration phase. E.g., use substrate for which organisms maintain a high Ks

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4
Q

What is a continuous culture

A
  1. constant nutrient medium supply
  2. well-mixed culture
  3. Products and cells are simultaneously withdrawn
  4. Can maintain growth and product formation
  5. At steady state, cell, product, and substrate concentrations remain constant
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5
Q

What factors affect populatoin growth in a continuous culture?

A
  1. relationship between organisms growth rate and limiting nutrient concentration
  2. amount of bacteria prod per unit mass of nutrient (yield)
  3. Concetnration of limiting nutrient feed
  4. Flow rate and vessel volume
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6
Q

What is the equation for the rate of dilution

A

D = F/V

D = rate of dilution
F = flow rate (L.h^-1)
V = volume of vessel (L)

Units: (L.h^-1/L) = h^-1

“THE RATE INWHICH WE ALTER THE CONTENSE OF THE VESSEL”`

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7
Q

What is the chemostat theory?

A

The flow of medium into chemostat is described by the dilution rate

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8
Q

What is the equation for net change in biomass?

A

Sigma x / Sigma t = ux - Dx

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9
Q

How is a steady state achieved

A

When ux = Dx
(rate of biomass formation = rate of biomass loss)

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9
Q

How is a steady state achieved

A

When ux = Dx
(rate of biomass formation = rate of biomass loss)

THEREFORE u = D (specific growth rate is the same/controlled by the dilution rate)

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10
Q

What happens at steady state?

A
  1. increased growth rate = increased dilution rate
  2. Slow the growth rate = slow the dilution rate
  3. setting the correct dilution rate is therefore important in optimising product and biomass formation
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11
Q

What is Dcrit?

A

If dilution rate is increased wash-out of cells can occur, as cells dont have enough time to ‘double’ before being washed out of overflow.

This point is referred to as the critical dilution rate (Dcrit)

STEADY STATE IS LOST

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12
Q

How do you calculate yield for continuous cultures

A

Ysp = P/(Cfs - Cs)

P = product
Cs = residual substrate from eluent
Cfs = concentration of substrate/feed

P and Cs can be determined from the eluent

Productivity can be measure by multiplying yield by the dilution rate

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13
Q

What is the Monod Paramaters

A

U = D = UmS/Ks+S

-> S = KsD/Um-D

therefore concentration of the limiting substrate increases with dilution rate

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14
Q

How can you predict Dcrit using Monod

A

Dcrit = Umax Cfs/Ks+Cfs

Increases nutrient feed concentration will increase Dcrit and U

Umax = max growth rate
Cfs = conc of feed stock
Ks

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15
Q

What are the problems with continuous batch culture?

A
  1. req constant monitoring
  2. increase chance of contamination
  3. increase chance of mutation
  4. selective pressure for biofilms
  5. hard to reconcile productivity with complete substrate conversion
16
Q

What is the fed-batch technique

A

Last 20 years its been increasingly explored for prod of recombinant proteins

Now many industrial fermentation processes are batch fed

17
Q

What are fed batches

A
  1. Fed with substrate solution so that one substrate component is growth rate limiting
  2. substrate feed is often sugar rather than complete medium
  3. feed flow is low - therefore low dilution rate
  4. substrate concentration is a high as possible (30-50%) to reduce voume increases
  5. no withdrawl of culture (so volume DOES increase)
18
Q

Why use a fed-batch?

A
  1. substrate limitation offers a tool for reaction rate control: control prod of specific product over another
  2. Substrate limitation offers metabolic control: avoid catabolite repression, repression of gene expression due to intermediary catabolites
  3. Eg, bakers east grown on glucose - low glucose favours cell mass over alcohol

Glucose prevents cAMP formation, meaning cAMP cant bind to CAP, CAP affects transcription of a large number of operons, in most cases, it functions as an activator but there are also cases where it is a repressor

19
Q

Why cant fed batch cultures reach steady state?

A

Maths is different to batch or contrinous as the volume constant changes.

D = (1/V) . (sigmaV/sigmaT)

Either: dilution rate exponentially decreases or the feed flow has to exponentially increase with time

20
Q

How is the yield produced linked to the feed concentration in fed-batches

A

Ysx(Cfs-Cso)-X0/Ysx(Cfs-Cs)-X = V/V0

Ysx = yield
X0 & X = start & end biomasses
V0 & V = start & end culture volumes

A high Cfs will give high biomass for little change in volume

21
Q

What is Cfs with regards to chemostat

A

concentration of limiting nutrient

22
Q

hat is Cs with regards to chemostat

A

residual substrate

23
Q

What is X with regards to chemostat

A

change in biomass

24
Q

What is V with regards to chemostat

A

volume of vessel

25
Q

What is F with regards to chemostat

A

Medium flow rate

26
Q

What happens as the dilution rate goes up

A

the growth rate goes up as theres more available nutrients